Project-1: Powertrain for aircraft in runways

6 a.. FORCES REQUIRED FOR PULL OR PUSH AIRCRAFT ARE:

ROLLING RESISTANC:

                       BODY RESISTS THE MOTION SUCHA AS BALL TIRE WHEN IT IS ON THE SURFACE.

                        Frr=Crr*m*g

Crr  is rolling resistance coefficient

m is mass of the body

g is acceleration  due to gravity.

AERODYNAMIC DRAG FORCE:

                                             IT IS RESISTANCE OFFERED BY AIR WHEN THE VEHICLE IS IN MOTION ON THE FRONTAL AREA.

Fad=1/2*V^2*A*Cd*DENSITY

V IS VELOCITY OF VEHICLE IN M/S

 A IS FRONTAL AREA

Cd IS COEFFICIENT OF DRAG FORCE

D IS DENSITY

CALCULATION:

TOWING VEHICLEMASS (kg)=45000KG

MASS OF AIR CRAFT(kg)= 160000KG

TOTAL WEIGHT (m)= 160000+45000=205000KG

FRONTAL AREA=18M/SEC^2

VELOCITY OF VEHICLE(V)=16KMPH.

SPEED OF THE VEHICLE IN M/S=16*5/18

                                                         =4.44m/s

COEFFICIENT OF ROLLING RESISTANCE=Crr=0.01

 FORCE OF ROLLING RESISTANCE=Frr=Crr*m*g

                                                         =0.01*205000*9.81

                                                             20110.5kg

 SIMILARLY FOR AERO DYNAMIC DRAG:

COEFFICIENT OF DRAG OF TOWING VEHICLE Cd1=0.608

 COEFFICIENT OF DRAG FOR AIR CRAFT Cd2=0.15 

TOTAL DRAG Cd=0.758

 AIR DENSITYD= 1.225KG/M^3

AERODYNAMIC DRAG FORCEFad= 0.5*Cd*D*V^2*A

                                                      =0.5*1.225*(4.444)^2*18*0.758

                                                       165.075

 TOTAL FORCE REQUIRED TO PUSH OR PULL THE VEHICLE FOR aircraft for thE TOWING VEHICLE IS 

Frr+Fad

20110.5+165.075

20275N

POWER CALCUATION:

P=Frr*V

  =20275*4.44

  =90.11KW

6.b. WE DONE SIMULINK ODELS BY USING ABOVE PARAMETERA OF ROLLING RESISTANCE FORCE , AERODYNAMIC DRAG FORCE, AND POWER FORMULA IMPLEMENTATION.

AND WE OBSERVE THE RESULTS SAME AS THE CALACULTION RESULTS.

7.ASSUMPTIONS FOR POWER TRAIN:

 AIRCRAFT MASS=160000KG

TOWING VEHICLE MASS= 45000KG

ROLLING RESISTANCE COEFFICIENT=0.01

 AIR DENSITY=1.225kg/m^3

towing vehicle drag coeffiecient=0.608

AIR CRAFT DRAG COEFFICIENT=0.15

 FRONTAL AREA=18M/SEC^2

INCLINATION ANGLE=0

 TYRE PRESSURE=196PSI/13.51bar

TOWING VEHICLE(v)=13KMPH=3.611M/SEC

TOWING TIME=2MINS

RADIUS OF THE TOWING VEHICLE WHEEL=0.4M

TOTAL FORCE ACTING ON THE VEHICLE

  TOTAL TRACTION FORCE(F)=20110.5

POWER REQUIRED(p)=90.11KW.

 TORQUE (T)= FORCE(F)*RADIUS OF THE WHEEL(R)

 T= 20110.5*0.4

    =8110.23NM

 

ENERGY REQUIRED BY THE VEHICLE FOR TOWING APPLICATION IS 

 ENERGY(E)=POWER(P)*TOWING TIME

                       =90.11*2/60

                        3.003KWH

SO THE INPUT GIVEN TO THE VEHICLE IS TAKE AS (KW)=110

 OUTPUT POWWER IS 90.11 KW

 DUTY CYCLE = OUTPUT POWER /INPUT POWER

                          = 90.11/110

                          =0.8912

 DUTY CYCLE IN %= 89.12

FROM THE BLOCK DIAGRAM WE OBSERVE THAT BATTERY IS SUPPLYING POWR TO THE MOTOR THAT IS CONTROLLED  BY CONTROLLER UNIT I.E INVERTER CIRCUIT

AUTOMATIVE OPERATES GENERALLY OPERATES ON DC WHILE GRID IS OPERATES ON AC

 SO CONVERTER IS NEEDE TO TRANSFER POWER TO THE BATTERY BECAUSE OF THE CAPABILITY OF EVVEHICLE THE EFFICIENCY IS MUCH MORE THAN CONVENTIONAL ENGINE.

MOTOR IS RESPONSIBLE FOR THE WHEELS AND BRAKES THROUGHT HE TRANSMISSION AND GEAR SYSTEM.

 7.B

 https://docs.google.com/spreadsheets/d/1vbG0o7VQLI7zgWmJEBKIwkBayVM2bNaaFA_9b32JphU/edit?usp=sharing

WE DONE THE EXCEL PARAMETERS CALCULATION