Challenge

Project 1 - Creation of user defined data type to implement the user interfaces for working with ‘Set’ (Mathematical Set theory) using Linked List

In this project, interfaces for mathematical Set Theory are implemented using C programming language. User can give the input like two list of data and this program will give the output as the union and intersection of these two lists

#include <stdbool.h>

#include <stdio.h>

#include <stdlib.h>

// Link list node

struct Node

{

int data;

struct Node* next;

};

/* A utility function to insert a

node at the beginning ofa linked list*/

void push(struct Node** head_ref,

int new_data);

/* A utility function to check if

given data is present in a list */

bool isPresent(struct Node* head,

int data);

/* Function to get union of two

linked lists head1 and head2 */

struct Node* getUnion(struct Node* head1,

struct Node* head2)

{

struct Node* result = NULL;

struct Node *t1 = head1, *t2 = head2;

// Insert all elements of

// list1 to the result list

while (t1 != NULL)

{

push(&result, t1->data);

t1 = t1->next;

}

// Insert those elements of list2

// which are not present in result list

while (t2 != NULL)

{

if (!isPresent(result, t2->data))

push(&result, t2->data);

t2 = t2->next;

}

return result;

}

/* Function to get intersection of

two linked lists head1 and head2 */

struct Node* getIntersection(struct Node* head1,

struct Node* head2)

{

struct Node* result = NULL;

struct Node* t1 = head1;

// Traverse list1 and search each element

// of it in list2. If the element is

// present in list 2, then insert the

// element to result

while (t1 != NULL)

{

if (isPresent(head2, t1->data))

push(&result, t1->data);

t1 = t1->next;

}

return result;

}

/* A utility function to insert a

node at the beginning of a linked list*/

void push(struct Node** head_ref,

int new_data)

{

// Allocate node

struct Node* new_node =

(struct Node*)malloc(

sizeof(struct Node));

// Put in the data

new_node->data = new_data;

/* link the old list off the

new node */

new_node->next = (*head_ref);

/* Move the head to point to the

new node */

(*head_ref) = new_node;

}

/* A utility function to print a

linked list*/

void printList(struct Node* node)

{

while (node != NULL)

{

printf("%d ", node->data);

node = node->next;

}

}

/* A utility function that returns true

if data is present in linked list

else return false */

bool isPresent(struct Node* head,

int data)

{

struct Node* t = head;

while (t != NULL)

{

if (t->data == data)

return 1;

t = t->next;

}

return 0;

}

// Driver code

int main()

{

// Start with the empty list

struct Node* head1 = NULL;

struct Node* head2 = NULL;

struct Node* intersecn = NULL;

struct Node* unin = NULL;

/* Create a linked lists

5->15->4->20 */

push(&head1, 20);

push(&head1, 4);

push(&head1, 15);

push(&head1, 5);

/* Create a linked list

8->4->2->5 */

push(&head2, 5);

push(&head2, 2);

push(&head2, 4);

push(&head2, 8);

intersecn = getIntersection(head1,

head2);

unin = getUnion(head1, head2);

printf("First list is ");

printList(head1);

printf("Second list is ");

printList(head2);

printf("Intersection list is ");

printList(intersecn);

printf("Union list is ");

printList(unin);

return 0;

}

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