Challenge

Modelling of 25 storey building with the specified properties using ETABS

1. Aim: To model a 25 storey building on E-tabs with structural properties as in the given question.

Introduction: To model a 25 storey building on E-tabs with structural properties as in the given question.

Procedure:

  • Open the Etabs software and select the New model option.

  • Select the settings option and change

  • Select the settings option and select the units related to the drawing.

  • Then New tab will appear on the screen.
  • Now select the custom grid and story data option.

  • Then the dialogue box will get open.

  • Change the grid data ordinates as per the grids given in the question.
  • Then click ok.

  • Now select the Edit story data option.

  • Change the story otions as per the required floors.
  • Then make the master story floor as first floor.
  • Now make the siliar floor to first floor for the remaining floors.
  • The plinth height should be 1.3 as per the given question and remaining floor heights should be 3m.

  • Now as per the given question, we need 25storeys of building.
  • Then click the right cick and we get the options to add the story.
  • Select the add story option.
  • And select the Keep existing story height option.

  • Then we can see the dialogue box open.
  • In that select the number of storeys to be added and click ok.

  • Now we can see the total 25 stories floor options.

  • Change the 25story as roof.
  • Then click ok.

  • Then click ok.

  • Now we can see the page open and grids open in the drawing.
  • There are 2 views open in the drawing as plan and elevation views.

  • Go to define option and apply material properties to te grids.
  • Click on the add new material option.

  • Then add the concrete material with the grade of M30 as in the given question.

  • Then change the mateial name as M30 and click ok.

  • Now add the another material as rebar for HYSD grade 415 and click ok.

  • Now we can see the 2 materials added and click ok.

  • Now go to the define option and select the section properties option and select frame section for creating beams and columns.

  • Select Add new property option.

  • Then select the beam in the concrete option.

  • After selecting a dialogue box will appear.
  • Now give the property name as beam a=with size given in the question.
  • And change the material property.

  • Now click on the modify/show rebar option.
  • Then select the M3 design for beam and click ok.

  • Now we can the beam size property.
  • We have to add column property in the same way.
  • Click on add new property.

  • Select concrete option for columns.

  • Mention column size as in the given question and select the material as M30.
  • Then give the section dimensions as depth and width.
  • Now click on modify/rebar option.

  • Select column design type and give the valies for longitudinal and confinement bars.
  • Then click ok.

  • Now we can see the both beam and column placed in the property.

  • In the same way select slab section option.

  • Click on Add new property option.

  • Select the property name as slab 150 and slab material as M30.
  • Then give the slab thickness and click ok.

  • Now we can see the slab name option.

  • Noe go to the define option and select load pattern option.

  • Then a dialogue box wil appear on the screen.
  • Now click on the add new load and give the loads which are existing in the strucure.
  • Then click ok.

  • Now select Mass source option in the define tab.

  • Now we can see all the loads which are given in the load cases.

  • Now select the Mass source option.

  • Select add new source option.

  • Add the loads for dead load, live load and wall for load pattern.
  • Click ok.

  • Now we can see the new mass source which we have created.

  • Now select quick draw column option.
  • Select column size property.

  • Now apply the column to the grids.

  • by using the option replicate we can easily apply the cloumns.

  • A dialogue box will appear on the screen.
  • Give the proper values and click ok.

  • Now we can see the columns given to the grids.

  • Now select the beam option as in the property option.

  • Now we can get all the beams applied to the grids.

  • Now select the slab option from the options.

  • select the slab area in the grids.

  • Now we can see the slabs applied on the grids in the plan view and 3d view.

  • Now we have to select all the beams for that go to the select option and select frame section in the properties.

  • Select beam size.

  • Now we can see all the beams are selected.

  • Then assign the loads and select the frame loads and apply distributed load to the beams.

  • Apply the load as wall and give the load as 10kn/m.

  • Now we can see the load applied on the grids.

  • In the same way select slab section option.

  • Select S150 option.

  • Apply uniform loads to the slabs.

  • Give the load as 3 which is in the given question.

  • Select the slab 150 portion and click Ok.

  • Now give diaphragms option to the slabs.

  • Now select d1 option.

  • we can see the diapgram applied to the grids.

  • Now click on run analysis option.

  • then we can see the process going.

  • Select display option and select show table option.

  • Select the structure option table.

  • Now we can see the table for modal periods.

  • Now select modal load participation rations.

  • Now we can see the table.

Result:

  • For fundamental Translational natural period in the x-direction and exercise resut is 4.41
  • Torsional irregularity in Y-direction and exercise result is 4.22
  • For vertical irregularity as per IS 1893-2016(part-1) table-6 exercise result for first three modes is yes.
  • For vertical irregularity as per IS 1893-2016(part-1) table-6 exercise result for fundamental lateral natural periods in tw principal plane directions are away from each way is no.
  • For Inter storey drift exexercise result is no.

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