Foundation Design using SAFE
1) AIM & INTRODUCTION: model an isolated footing using safe with respect to previous challenge
PROCEDURE:
Data required for SAFE Analysis & Design:
unfactored load =2000/1.5 = 1333.3 KN
Dead load breakup = 1333.3/2=666.7 KN
Live load breakup = 1333.3/2 = 666.7 KN
Sugrade modulus of soil = safe bearing x factor of ultimate /maximim settlement
= 150 x 3/0.05 = k =9000KN/m3
Rebar yield strength (fy) = 500N/mm2
Rebar ultimate strenth (fu) = say 5.75 N/mm2
Elastic modulus of M25 concrete = 25000 N/mm2
open safe - file - new model - single footing - provide all the necessary dimensions - design strips - add load combinations - show width under design strip pattern
Checks needed to be performed in safe analysis:
- Safe bearing capacity under service load
- Settlement under service load
- Two way shear check (punching shear )
- Ultimate bending moment
- flexural reinforcement design for footing slab
safe bearing :
show reaction forces - load combination - settlement - soil pressures - display contours in extrudeed form - user defined - scale factor - 1-apply
acceptable
settlement:
shape deformed shape - settlement - apply
it is okay
2 way shear:
show punching shear design
applied shape stress is less than capacity of the section , section pass in 2 way shear
ultimate bending moment:
switch on design strips - show strip forces - DCONU1 - apply - layer A&B -Apply
flexural reinforcement designshow slab button -input minimum reinforcement - apply
RESULT: modelled an isolated footing using safe with respect to previous challenge succesfully
REPORT FORMAT:







2) AIM & INTRODUCTION: model,analyse and design the pile cap using safe
PROCEDURE:
Data required for SAFE analysis & design:
unfactored load = 1175 KN
dead load breakup =1175/2 = 587.5 KN
Live load breakup = 1175/2 =587.5 KN
Point spring of file = A X E /L =196349 X 25000/16000 = 306796 KN/MM
K for safe analysis = 306.8 kn/mm
rebar yield strenth (fy) = 500N/mm2
rebar ultimate strength (fu) = say 575 N/mm2
Elastic modulus of M25 concrete =25000 N/mm2
number of piles required = unfactored load with self weight addition/individual pile capacity = 1175 x 1.1/200 = 6.5
consider 8 piles for symmetric placement of piles under pile cap
take center to center distance between piles = 3xpile diameter (1500mm)edge distance from pile center =1xpile diameter (500mm)
assume pile cap depth = 500 mm

safe designing :
checks need to be performed in SAFE analysis
- individual pile capacity under service load
- settlement under service load
- two way shear check (punching shear)
- flexural reinforcement design for footing slab
select - points - assign - support data - point springs
analyse the plan
punching check - ok
reactions - load combination - service - fz - apply
plan view - deformed shape - apply
show slab design - tick layer a and b - apply
RESULT: modelled,analysed and designed the pile cap using safe
REPORT FORMAT:





