Challenge

Analysis & Design of RCC shear walls in the model using ETABS

Aim:

To analyze the given model and to extract the reinforcement details for the specified Rc wall and to detail, the Rc wall using AutoCAD with compliance to ductility IS 13920-2016 standard

Procedure:

  • Download the file from given challenge
  • Now open the file using Etabs 18

  • Now check the model

  • Now Run Analysis

  • Now start design check

  • Now select display info and choose PM failure

  • Now select display info and choose pier reinforcement ratios

  • Now right click on the shear wall to get the design details as shown

Calculations with IS13920-2016:

Overall height of wallh=21000mm, length of wall L=1500mm.

So the given RC wall is slender.

According to clause 10.8, the largest diameter that can be used in an RC wall should not exceed 1/10thof thickness of the wall

Therefore,300/10=30mm.So the thickness of the wall=300mm

We used a 25mm dia rebar in the detailing. So it is within the limit.

According to clause 10.9 maximum spacing of longitudnaVtransverse rebar should not exceed

  • 1/Sth of horizontallength=1500/5=300mm ii) 3 times of thickness(tw) =3x300=900mm iii) 450mm
  • So we need to adapt a spacing of 300mm both for vertical and horizontal rebar inside the RC wall.

=7524 sq. mm for the entire RC wall height. which will be 358 sq. mm/meter height of RC wall

  • Minimum horizontal reinforcement calculation as per table 1of 1513920-2016:

(Ph)min=0.0025+0.S(hw/Lw-2)(Ph-0.0025)

=0.01672of cross-section of RC wall

=1500*300*0.01672

  • We provided 16mm dia at 100mm c/c which gives =1000/100x2x201=4020sq .mm
  • Minimum boundary reinforcement calculation as per table 1of IS 13920-2016 (Pv,be)min=0.008

=0.008x300x300=720sq .mm

  • We provided 8 numbers 12mm dia rebar=8x113=904 sq.mm
  • Minimum web reinforcement calculation as per table-1of 1513920-2016 (Pv,web)min=0025

=0.0025x900x300=675 sq.mm

  • we provided 8 numbers 12mm dia rebar=8x113=904 sq.mm
  • Minimum overallRC wall vertical reinforcement calculation as per table 1 of ls13920- 2016

(Pvnot=t)min=0.0025+0.01375(tw/ Lw)

=0.00525 times of wall cross section

= 0.00525x1500x300=2363 sq.mm

  • We provided 24 numbers12mm dia rebar=24x113=2712sq.mm
  • Boundary element special confining reinforcement as per clause 14.4 of 1513920- 2016:

Ash=O.O5xSvxh(Fck/fy)

As per the drawing maximum spacing of confinement is 100mm.

h= minimum clear distance between longitudinal rebar=150mm

So Ash=45sq.mm

We already provided two closed links of 16mm dia=2x201=402 sq. mm

Conclusion: We have designed the specified RC wall and also the clauses from ductility code 1513920-2016 are verified for the RC wall detailing.

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