Analysis & Design of RCC shear walls in the model using ETABS
Aim:
To analyze the given model and to extract the reinforcement details for the specified Rc wall and to detail, the Rc wall using AutoCAD with compliance to ductility IS 13920-2016 standard
Procedure:
- Download the file from given challenge
- Now open the file using Etabs 18

- Now check the model

- Now Run Analysis

- Now start design check

- Now select display info and choose PM failure


- Now select display info and choose pier reinforcement ratios


- Now right click on the shear wall to get the design details as shown

Calculations with IS13920-2016:
Overall height of wallh=21000mm, length of wall L=1500mm.
So the given RC wall is slender.
According to clause 10.8, the largest diameter that can be used in an RC wall should not exceed 1/10thof thickness of the wall
Therefore,300/10=30mm.So the thickness of the wall=300mm
We used a 25mm dia rebar in the detailing. So it is within the limit.
According to clause 10.9 maximum spacing of longitudnaVtransverse rebar should not exceed
- 1/Sth of horizontallength=1500/5=300mm ii) 3 times of thickness(tw) =3x300=900mm iii) 450mm
- So we need to adapt a spacing of 300mm both for vertical and horizontal rebar inside the RC wall.
=7524 sq. mm for the entire RC wall height. which will be 358 sq. mm/meter height of RC wall
- Minimum horizontal reinforcement calculation as per table 1of 1513920-2016:
(Ph)min=0.0025+0.S(hw/Lw-2)(Ph-0.0025)
=0.01672of cross-section of RC wall
=1500*300*0.01672
- We provided 16mm dia at 100mm c/c which gives =1000/100x2x201=4020sq .mm
- Minimum boundary reinforcement calculation as per table 1of IS 13920-2016 (Pv,be)min=0.008
=0.008x300x300=720sq .mm
- We provided 8 numbers 12mm dia rebar=8x113=904 sq.mm
- Minimum web reinforcement calculation as per table-1of 1513920-2016 (Pv,web)min=0025
=0.0025x900x300=675 sq.mm
- we provided 8 numbers 12mm dia rebar=8x113=904 sq.mm
- Minimum overallRC wall vertical reinforcement calculation as per table 1 of ls13920- 2016
(Pvnot=t)min=0.0025+0.01375(tw/ Lw)
=0.00525 times of wall cross section
= 0.00525x1500x300=2363 sq.mm
- We provided 24 numbers12mm dia rebar=24x113=2712sq.mm
- Boundary element special confining reinforcement as per clause 14.4 of 1513920- 2016:
Ash=O.O5xSvxh(Fck/fy)
As per the drawing maximum spacing of confinement is 100mm.
h= minimum clear distance between longitudinal rebar=150mm
So Ash=45sq.mm
We already provided two closed links of 16mm dia=2x201=402 sq. mm
Conclusion: We have designed the specified RC wall and also the clauses from ductility code 1513920-2016 are verified for the RC wall detailing.