Challenge

Week 6 Challenge

  • Introduction:

Client Name (_______________________________________) has awarded Company Name ____________________________________ for Project Name(_____________________________________________________________________________________________________________________________________________________________________________________________________________________.

Company Name (______________________) has appointed INFRAENGG Design Agency’s name (__________________) as the “Design Consultant” to carry out the Detailed Design of the project corridor.

  1. Schedule of Spans & Dimensions:

 

Calculate the design Pipes loads for the bridges to be designed as follow: -

 

Solution :

 

 

 

Items

Symbol

Qty.

Unit

Location

Narmada

Span

3.0

m

The length of Bridge

24.0

m

Type of Pipe

K-9

Class

Diameter of NB DI  Pipe P1

0.7

m

Diameter of NB DI  Pipe P2

0.2

m

Unit weight of the Pipe 200 mm Dia.

A

30.6

Kg/m

Unit weight of the Pipe 700 mm Dia.

B

173.9

Kg/m

Height from top of pedestal to top of Bridge

3.25

m

Height from bottom of bridge to top of Bridge

2.5

m

Column Size (Assumed)

1.0x1.0

m

Dead load of Pipe:

Weight of 200 mm dia pipe

734.4

Kg

Weight of 700 mm dia pipe

4173.6

Kg

Live load of Pipe:

Unit weight of Water

10

Kg/m3

Weight of 200 mm Dia pipe

C

0.31

Kg/m

Weight of 700 mm Dia pipe

D

3.85

Kg/m

Total Load on the structure:  in kg/m

200 mm dia pipe(A+C)

30.91

Kg/m

700 mm dia pipe(B+D)

177.75

Kg/m

Total Load on the structure:  in KN/m

   

200 mm dia pipe(A+C)

 

0.0309

KN/m

700 mm dia pipe(B+D)

 

0.1777

KN/m

 

This load are acting on the structure as UDL

  1. General Arrangement:

 

The following steel truss  geometry figure is given below.

 Plan of the Structure:-

1. Structure -Geometry Model:-

2. Properties Assigned:-

3. Suppoert assigned:-

4. Load Assigned:-

5. Run the Model:-

6. Maxi. Moment along Z:-

Shear Force Diagram:

Bending  Moment Diagram along Z direction: apllied self- weight

Bending  Moment Diagram along X direction:

Report the following Structure:-

1.Beam End Forces from hight to low:

Beam L/C Node Axial Force kN Shear-Y kN Shear-Z kN Torsion kN-m Moment-Y
 kN-m
Moment-Z kN-m
190 2 82 -3.792 -1.441 0.005 0 0.009 3.661
140 2 53 -2.43 1.125 0 0 -0.001 3.235
139 2 52 -1.729 1.125 0 0 0.001 2.565
61 2 75 -1.091 -1.512 -0.204 0.029 -0.184 2.384
81 2 81 -1.091 -1.512 0.204 -0.029 0.184 2.384
175 2 45 -1.094 0.811 5.363 -0.05 0.555 2.274
187 2 51 -1.094 0.811 -5.363 0.05 -0.555 2.274
111 2 57 -1.121 1.031 -1.808 -0.059 0.201 2.07
117 2 63 -1.121 1.031 1.808 0.059 -0.201 2.07
142 2 66 -1.121 1.141 -1.808 -0.059 -0.341 1.744
154 2 72 -1.121 1.141 1.808 0.059 0.341 1.744
83 2 37 9.277 -0.299 -0.065 0 -0.121 1.305
190 2 81 3.792 1.722 -0.005 0 0.007 1.084
178 2 75 -1.775 0.55 0.002 0 -0.004 1.005

2.Beam End Forces from  low  to hight :

Beam L/C Node Axial Force kN Shear-Y kN Shear-Z kN Torsion kN-m Moment-Y
 kN-m
Moment-Z kN-m
176 2 74 3.792 -1.441 0.005 0 -0.009 -3.661
140 2 55 2.43 1.125 0 0 0.001 -3.235
139 2 54 1.729 1.125 0 0 -0.001 -2.565
187 2 81 1.094 -0.76 5.363 -0.05 -0.195 -2.384
175 2 75 1.094 -0.76 -5.363 0.05 0.195 -2.384
117 2 51 1.121 -0.958 -1.808 -0.059 0.563 -2.269
111 2 45 1.121 -0.958 1.808 0.059 -0.563 -2.269
154 2 63 1.121 -1.031 -1.808 -0.059 0.201 -2.07
142 2 57 1.121 -1.031 1.808 0.059 -0.201 -2.07
170 2 72 1.125 -1.567 0.461 -0.009 -0.332 -1.745
158 2 66 1.125 -1.567 -0.461 0.009 0.332 -1.745
2 2 2 -9.277 -0.299 -0.065 0 0.121 -1.305
176 2 75 -3.792 1.722 -0.005 0 -0.007 -1.084
188 2 81 1.775 0.55 0.002 0 0.004 -1.005
14 1 16 -2.188 0 -0.009 0 -0.013 0

3. Maximum Reaction alog Y Direction:-

Max.  Reaction Force along Y Direction 
Node L/C Force-X kN Force-Y kN Force-Z kN Moment-X kN-m Moment-Y kN-m Moment-Z kN-m
44 2 -1.036 13.555 -0.142 -0.032 -0.001 0.376
44 1 -0.113 1.584 -0.027 -0.006 0 0.045

1.Beam End Forces from hight to low:1.Beam End Forces from hight to low:

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