Week 6 Challenge

This method for form-finding and analysis of hyperelastic tensegrity structures based on a special strut finite element and unconstrained nonlinear programming. The strut element can function as a hyperelastic truss element with an initial cut in its undeformed length or as a strut element that shows constant force irrespectively…

This method for form-finding and analysis of hyperelastic tensegrity structures based on a special strut finite element and unconstrained nonlinear programming. The strut element can function as a hyperelastic truss element with an initial cut in its undeformed length or as a strut element that shows constant force irrespectively…

Project Name - Education Centre RoadAssume - Calendar as 6 x 24 and start date on 22nd feb 2021 AIM OF THE PROJECT -  1. Develop the project schedule as per the criteria above2. Use 3-Tier timescale with Year / Month / Weeks3. Define and Add resources4. Add a budget to your project - INR 6 cr.5. Assign a baseline…

AIM OF THE PROJECT  Skill-Lync wants to construct a school as a part of its corporate social objective. You are the project manager. Develop a realistic schedule to construct a main school building (G+2). It will have a parking facility with internal roads and main building complete with architectural, furniture and…

           AIM & INTRODUCTION- Model a PEB Warehouse & Design  using STAAD. Pro with following given data BUILDING INPUT     Length 630 (inside sheet to C/L of column) + (2 X 8045 + (19 X 8000) of columns) + 630 (C/L of column to inside of sheeting) = 169350 …

AIM & INTRODUCTION :- Main frame with Lean (Grid-2) & Gable frame without Lean (Grid-15) of Proposed Coil center is to be modeled and designed with given inputs- Given Inputs- Building Width = 30 m out to out of steel                     Building Length  =…

Q1) ISOLATED FOOTING Isolated footing for a column 300 mm x 450 mm, carrying axial load of 1500 kN and Mu = 150 kNm ( Reversible) . The safe bearing capacity of the soil is 200 kN/m2 at a depth of 1 metre from ground level. Grade of concrete - M 25 and Grade of steel - Fe 415.  Open stadd foundation,…

ANALYSIS AND DESIGN OF PIPE RACK STRUCTURESQ1) Friction load determination  Given data : A pipe carrying LNG rests on the shoe having vertical force of 125 kN. Friction load on the axis and friction force are required to be determined if there is TEFLON pad between shoe and pipe support. Friction…

Q1. Purlin & Girts number determination Given data :  Rafter span = 50 m Bay spacing = 8 m Roof slope = 1 in 10 Height of column = 12 m Brick wall height = 2 m Purlin spacing = 1.2 m Girt spacing = 1.5 m Frame designed according to the dimensions specified. Number of purlins on one side of the frame…

Q1)  Design of dual slope (pitched) roof frame   Given data :  A 3 hinged pitched roof frame of a steel building. No wind load acting on the walls and roof.The slope of the roof is 1 in 10 and the roof is accessible for maintenance purpose (assume 75 kg/m2) only. Given bay spacing…

Q1) Application of loads  Go to general, then loads and definitions. Add all the required loads according to the structure. A Load case as DL for Dead Load Apply Self weight Apply member load of 3 kN/m on the rafter Apply member load of 6 kN/m on the secondary beams Apply point load of 20 kN at node intersecting inclined…

Q1) Modelling of a structure exercise Bay spacing 5 m Span of Truss 30 m Shape of Truss – Pratt Truss Slope of truss 20 degree Height of the column 15 m Floor Beams at 5 m from base Secondary beams at 1.5 c/c Length of the building 50 m Column Supporting Floor Beam @ 6 m c/c Along the frame  Create…

Q1) Chequered Plate design Chequer plates offer an easy access for vehicles and combine a closed surface with an anti slip effect. They are ideally suitted for platforms or as a design element. (because it is anti-corrosive and it doesn't require painting so it is low maintenance) A chequered plate…

>Plate girder (PG) provides maximum flexibilty and economy.>PGs can be tapered, cranked , or haunched. >It can also have web opened for service to accomodate services. Q1) SHEAR RESISTANCE OF WEB The presence of thick flange improves the shear buckling strength of plate girder. The effective position…

Q1) SECTION CLASSIFICATION OF BEAMS A beam is a structural element that is capable of withstanding load primarily by resisting against bending.Based on yield and plastic moments , sections are classified as :>Plastic>Compact>Semi compact>Slender  i) ISMB 500 - It is an I section , rolled and develops…

Q1) EFFECTIVE LENGTH DETERMINATION It is length between the points of contraflexure of a buckled column. It depends upon the support conditions. It depends upon end condition height of column and does not depends upon span of beam it supports.Height of column is 10 m and it is effectively restrained in mid height…

Q1) When a tension member is subjected to axial tensile force, then the distribution of stress over the cross-section is uniform. The complete net area of a member is effectively used at the maximum permissible uniform stress.Net sectional area of the tension member is the gross sectional area of member minus the…

Q1 ) We are given two TRUSSES to compare.Trusses are used in bridges, buildings, and many other infrastructure. Generally a truss has 3 fundamental member> Upper chord> Lower chord > Middle member Joining the both to transfer loads.The two types of trusses are given to us>TRUSS A : Pratt truss>TRUSS…

The architectural drawings of a G+3 RCC building is provided to us. Hostel block in an academic institute in Guwahati, AssamThe walls are made of AAC blocks , density = 6kN/m^3.The buildings rests on type 3 soil. The ground floor level is at a height of 2 meters above the existing site level. Grade…

Q1   Given a square isolated footing with a column size : 400x400Compression axial load for the load combination of (1.5DL + 1.5LL ) = 2000KNThe safe bearing capacity is 150kN/m^2 at a depth of 2m below E.G.L Grade of concrete M25  Taking unfactored load assumption as 2000/2 =1333.3kNDEAD load = 1333.3/2…

To design a square footing for any column , we first need to calculate the gross soil pressure for footing area. GIVEN DATA :Column size : 400x400Compression axial load : 2000 KNSoil bearing capacity : 150 KN/m2Depth : 2 mConcrete grade : M25 GROSS SOIL PRESSURE = Unfactored load with surcharge + self weight of footing…

We have been provided the architectural drawings for a G+7 residential building in zone 5. The floor plan is the same for all 7 floor levels.Parking is given in the ground floor. Brickwalls are made of AAC blocks.Finishes – floor tiles of 75 mm thickness. Live loads as per IS 875 part 2.Water tank of 20…

 A G+6 building is provided. We have to design the RCC shear wall. The shear wall of size 300x1500 at grid A-11 in the structural model. After running the analysis , the longitudinal steel ratio, boundary element length and shear reinforcement ratio are as follows: The total elevation height of the building from the…

We are provided with a G + 4 building beam layout plan. Beam dimensions given as 450 X 650 , being 500mm depth.We need to design the RC columns along two spans to ensure the ductility reinforcement, the structure to be safe and economical according to IS code 456- 2002 and IS code…

We are provided with a G + 4 building beam layout plan. Beam dimensions given as 300 X 500 , being 500mm depth.We need to design the RC beams along two spans to ensure the ductility reinforcement, the structure to be safe and economical according to IS code 456- 2002 and IS code 13920-2016. Grid A and Grid 3…

Here we study the factors influencing the dynamic characteristics, natural period , mode shape of oscillations of different buildings and compare their analysis results with respect to seismic forces. We are given 10 buildings with different structural configurations. They are:MODEL A - 2 Storey building with column dimensions…

A 25 storey building is modelled in ETABS software with specifications given as: >Ground floor or plinth floor level can be taken at a height of 1.5 metres from the base. >Each of the successive 25 storeys has a storey height of 3 metres. Total height of the building 76.5m.>Beams : 300 × 400 mm>Columns…

1) The building shown in question gives three option of a plan with same dimensions of layout, column, and walls. The given data: 20 × 35 m plot area ,columns of size 5 × 5 m, shear walls 250mm thick.Considering the first alternative:The restraint of floor shrinkage -  In this option…

1) Talking about the layout given , It is been investigated on factors such as symmetry , redundancy, ductility and bi-directional stiffness along both X-axis and Y-axis.Symmetry  - Symmetry is defined as all directions following a specific pattern . Along X-axis , if layout is folded into half horizontally, we will…

GIVEN DATA  :  5 Storey structure, 5 transational degree of freedom, each mass 'm' , T1 = 2 sT2 = .6852 sT3 = 0.4346 sT4 = 0.3383 sT5 = 0.2966 s  DETAILED CALCULATION PDF ID ATTACHED BELOW The following calculations can be derived from the above data:MODAL PROPERTYL1= 4.121mL2 = -1.327mL3 = 0.683mL4…

1) In general , static means stationary and dynamic means constant movement. It is important to perform analysis on a building to find the response of the structure when its subjected to loads. There are two types of analysis done on structures, for designing a building with all safety measures, to find its all safety…

1) a. For the encircled failure some observations can be drawn out. They are: Bottom of the beam shows the failure although top is safe and fine well connected to slab and column without any cracks. Reinforcement bars can be seen through and concrete is shedded off. Crack developed from bottom to top can be a sign…

1) Navisworks is a software joined to revit for building modeling to have better design and information about the building and its management process. It work on real time bais. First download and install navisworks freedom and exporters of the same version  as revit. Open the file to export , drop down to NWC project…

1) Dynamo is real time working software to create complex designs using nodes, coordinates and parameters. For a sinusoidal curve first create 3 integer sliders for start and end. Link them to a range box with start point first , end point second and step to the third one. Create two point coordinates ad link them to code…

1) To start a construction project of a multiunit residential apartment , a large number of factors are to be considered. A residential unit should contain a living space, kitchen , bathroom/water -closets, storage room, bedrooms, balcony , parking space, terrace , stairs, escalator , generator, etc. My project being a…

1) To create ceiling at first floor, copy all the walls, components to first floor level , go to architecture tab select ceiling option and sketch the path around which ceiling is to be created.  2) While creating roofs make sure to make them to the top of the building, i.e. above the topmost floor then change the…