Week 4 Challenge

1.Calculate dead load in design report based on IS code and apply dead load on the model

• Finishes of 50mm
• Slab as per design
• Brickwall 150mm thickness
• Roofing load based on purlin size
• Ceiling loading 0f 0.3KN per sq m

Ans)

Aim: To calculate dead load in the design report based on IS code and apply dead load on the model.

Tools Required:

->Manage Properties

->Slabs

->Properties tab

->Load

->Load cases

->Dead load

->Imposed load

->Area

->Full UDL

->Line

->Validation

Calculations:

DEAD LOAD :

Slab load = Model slab in software.

Finishes loading (50THK) = 0.05m x 24 KN/m^3 = 1.2 KN/m^2.

Brick wall with cement plaster thickness = 150mm.

Unit weight = 20 KN/m^3

Floor height (GF to FF) = 5.2 m

Brick wall loading = 15.6 KN/m

Floor height (FF to Roof) = 6.8 m

Brick wall loading = 20.4 KN/m

Roof loading = 1.5 KN/m^2

Procedure:

• Firstly, open the file which was created earlier.

• Go to the load tab and select the load cases option under that, the Load cases dialog box appears.

• Create new loads such as crane, seismic and wind load to the list of predefined loads.

• Now we have to create slabs for all the layers required.

• Based upon the dimension of the adjacent beams we have to select one-way or two-way slabs, that is to select the two-way option when the ratio between the values is less than 2 else select the one-way slab itself.

• Also while adding the slab do create slab S1 with one way and S2 with two way the major changes among the S1 and S2 is nothing but this itself.

• Now the parameters are select the bar type 10, bar spacing as 150mm, over depth as 200mm, and the grade as M25.

• Now at the bottom of our workspace, we find a dead load option in the drop-up dialog box.

• Under the load tab, we have to select the area and give the value of 1.2KN/m square and select all the slabs.

• Now we have to select Full UDL and apply the dead load to all the beams.

• Now select the Line tool under the load tab and draw the load of the wall in all the required floors.

• Do not forget to validate your model now and then to check your errors and correct them.

Result:

Hence, by following the above procedure, we will provide the dead loads to the slabs and beams for the structure.

_______________________________________________________________________________________________________________________________________________________

2.Calculate live load in design report based on IS code and apply live load on the model

• Assume the loading based on IS 875
• Roof loading
• Consider equipment loading as 5KN per sq m

Ans)

Aim: To calculate live load in the design report based on IS code and apply live load on the model.

Tools Required:

->Load

->Load cases

->Dead load

->Area.

Procedure:

• Firstly, open the file in which the dead loads were added.

• Now at the bottom of our workspace, we find imposed load option in the drop-up dialog box.

• Now we can provide live loads to the structure by selecting the load and assigning the value for it according to the IS Code.

• Click on the load's icon and select the area option under that.

• The live loads for the structure can be obtained from the IS building standard codes.

• Now under the property dialog box enter the required load for a different room.

Store room = 5 KN/m^2

Office = 3 KN/m^2

Rest room = 2 KN/m^2

Toilets = 2 KN/m^2

Pantry = 3 KN/m^2

Corridor = 4 KN/m^2

Equipment room = 10 KN/m^2

• Now set the loads with different values and apply them by clicking on the respective slabs.

• Now repeat the same process for all the remaining levels that is for the first and to the top of the roof level.
• Do not forget to validate your model now and then to check your errors and correct them.

Result:

Hence by following the above procedure we can apply live loads to the structure and calculate.

_______________________________________________________________________________________________________________________________________________________

3.Generate a calculation for 5T crane loading based on the following inputs

• Centre to Centre of wheel = 10m
• Weight of crab = 40 KN
• Number of wheels = 4
• Wheelbase = 2m

Ans)

Aim: To generate a calculation for 5T crane loading based on the following inputs.

Calculation:

Max wheel load

Maximum concentrated load on crane = 50 + 10 = 60 KN.

Self-weight of crane will act as uniformly distributed load of intensity

=40 / 10 = 4 KN/m.

Taking moment about B :

Ra x 10 – (60 x 9)- (4 x 5 x 10) = 0

10 Ra = 740.

Ra = 74 KN.

Rb x 10 –(60 x 1)-(4 x 10 x 5) = 0

10 Rb = 260

Rb = 26 KN.

Ra + Rb = 100 KN.

The reaction from the crane girder is distributed equally on two wheels at the end of the crane girder.

Maximum wheel load on each of the crane wheel = 74 / 2 = 37KN.

MAXIMUM BENDING MOMENT :

Assume self-weight of the gantry girder as 1.5 KN/m

Total dead load = ( Self-weight of rail + self-weight of gantry girder ) 300 + 1500 = 1800 N/m

Taking moment about D

Rc x 5.5 –(37 x 4.25)- (37 x 2.25) = 0

Rc x 5.5 = 240.5

Rc = 240.5 / 5.5

Rc = 43.72 KN.

Rd x 5.5 – (37 x 1.25)- (37 x 3.25) = 0

Rd x 5.5 = 166.5

Rd = 166.5 / 5.5

Rd = 30.27 KN.

Bending moment under wheel due to live load = Rd x 2

= 30.27 x 2

= 60.54 KN.

Bending moment due to impact = 0.10 x 60.54 ( 10 % increase due to MOT)

= 6.054 KNm

Total bending moment due to live load and impact load = 60.54 + 6.054

= 66.594 KNm.

Bending moment due to dead load = W x l x l / 2

= 1.8 x 5.5 x 5.5 / 2 = 27.22 KNm

Maximum bending moment = 66.594 + 27.22

= 93.814 KNm.

MAXIMUM SHEAR FORCE :

For maximum shear force, one of

Rc x 5.5 –(37 x 5.5)-(37 x 2.5) = 0

Rc = 9.25 + 20.35 / 5.5

Rc = 5.381 KN

The maximum shear force due to wheel load = 5.31 KN

LATERAL FORCES :

Lateral forces traverse to rails = 5% of the weight of crab and weight lifted

= 0.05 ( 40 + 10 )

= 2.5

Lateral forces on each side wheel F1 = 2.5 / 2 = 1.25 KN

Maximum horizontal reaction due to the lateral force by proportion at C

= Lateral force x reaction at C due to vertical load / maximum wheel load due to vertical load

= 1.25 x ( 43.72 / 37) = 1.44 KN

At D

2.5 – 1.44 = 1.06 KN

Bending moment due to lateral load by proportion

= (1.25 / 37) x 5.31

= 0.179 KNm.

Result:

Hence by following the above steps of the procedure we could generate the calculation for the 5T crane loading.

_______________________________________________________________________________________________________________________________________________________