Challenge

Week 3 Sheet metal Bending challenge

Objective: To perform sheet metal bending simulations for the following cases:

  1. Case 1: With Aluminum Alloy 1199, Copper Alloy NL and Magnesium Alloy NL
  2. Case 2: With Aluminum Alloy 1199 and friction coefficient 0.19
  3. Case 3: With Aluminum Alloy 1199 and finer mesh size for the sheet

Procedure:

  1. Contacts:
  2. Meshing:
    1. Case 1 (Sheet Mesh Size 1 mm):
    2. Case 2 (Sheet Mesh Size 1 mm):
    3. Case 3 (Sheet Mesh Size 0.5 mm):

Analysis:

  1. Case 1:
    1. Aluminum Alloy 1199
      1. Directional Deformation:
      2. Equivalent Elastic Strain:
      3. Equivalent Stress:
    2. Copper Alloy NL
      1. Directional Deformation:
      2. Equivalent Elastic Strain:
      3. Equivalent Stress:
    3. Magnesium Alloy NL
      1. Directional Deformation:
      2. Equivalent Elastic Strain:
      3. Equivalent Stress:
  2. Case 2:
    1. Directional Deformation:
    2. Equivalent Elastic Strain:
    3. Equivalent Stress:
  3. Case 3:
    1. Directional Deformation:
    2. Equivalent Elastic Strain:
    3. Equivalent Stress:

Result:

Cases Material Friction Coefficient Directional Deformation (mm) Equivalent Elastic Strain (mm/mm) Equivalent Stress (MPa)
Maximum Minimum Maximum Minimum Maximum Minimum
Case 1 Aluminum Alloy 1199 0.1 2.3453 -12.433 0.0015718 1.226×10^-13 62.573 2.4519×10^-8
Copper Alloy NL 0.1 2.7977 -11.655 0.0017309 1.1018×10^-12 135.33 2.2001×10^-7
Magnesium Alloy NL 0.1 2.536 -11.338 0.0027907 1.0219×10^-12 89.014 2.0436×10^-7
Case 2 Aluminum Alloy 1199 0.19 2.3219 -12.387 0.0015928 1.1711×10^-13 59.559 2.3422×10^-8
Case 3 Aluminum Alloy 1199 0.1 2.3757 -12.355 0.0016608 7.6484×10^-14 82.652 1.5292×10^-8

Conclusion: The directional deformation and stress are maximum for Copper Alloy NL, lesser for Magnesium Alloy NL and least for Aluminum Alloy 1199. Strain is maximum for Magnesium Alloy NL, lesser for Copper Alloy NL and least for Aluminum Alloy 1199. As friction coefficient increases, the directional deformation and stress decrease whereas strain increases. Thus, the Young's Modulus of the material plays an important role in it.

Your portfolio, next

Ship work like this
in your own course.

Talk to a career counsellor

Free 20-minute call. We'll map the right course to where you want to work.

By submitting you agree to our Terms and Privacy Policy.

Talk to a career counsellor

Free 20-minute call. We'll map the right course to where you want to work.

By submitting you agree to our Terms and Privacy Policy.