Week 2 Challenge

Q1) When a tension member is subjected to axial tensile force, then the distribution of stress over the cross-section is uniform. The complete net area of a member is effectively used at the maximum permissible uniform stress.
Net sectional area of the tension member is the gross sectional area of member minus the sectional area of maximum number of holes.
An = Ag - sectional area of hole
An: Net sectional area of plate
Ag: Gross sectional area of the plate

>i)

>ii)

>iii)

Q2) SAG ROD DESIGN
Purlins are supported at 1/3^rd points by sag rods.
Centre to centre distance of Rafter spaced at 8 m
Spacing of purlin = 1.2 m,
Self weight of roofing (including thermal insulation)= 60 kg/m²
Wind pressure intensity = 150 kg/m²,
Slope of rafter = 15 degrees,
Live Load =75 kg/m².
Self weight of purlin as 100 kg/m.

Q3) DESIGN SECTION SIZE
Single angle member of length 5m to carry axial tensile force of 500 kN.
Yield strength fy of the material to be considered is 350 N/mm²

^{ALL THE CALCULTIONS ARE ROUNDED OFF TO APPROXIMATE NUMBERS}