Week -2

CONCLUSION-

1. As changing Temperature of themister, voltage and current parameter of heater changes.

So, Thermister temperature (T) = Current (I) / Voltage (V)

From Scope block, the value of Voltage at Temperature below 27°©, is below 0.54 V.

Heating Voltage (V) = Current (I) / Thermister temperature (T) 

As per given problem condition, we provider threshole value for switching circuit is voltage output as 0.55V. 

So, we conclude that at time span from 10 sec to 30 sec, cooling fan will ON and time span from 0 sec to 10 sec & 30 sec to 50 sec, cooling fan remain OFF position.