Week 12 Challenge

DWT = 52500

Speed = 60 km/hr

Length = 294 m

Hydrodynamic coefficient = 1.25

Sol:-

Barge Collision Energy

KE = 500 * Ch * W * V2 (As per IRC 6 Page No. 78 )

Where

W = Berge Displacement Tonnage (T)

V = Barge impact Speed (m/s)

KE = Barge Collision Energy (N-m)

Ch = Hydrodynamic coefficient

KE = 500*1.25*52500*60*60*(1000/3600)

=9.1*10 KE POWER 9 N-m

Barge Damage Depth

Ab = 3100* ({1+1.3*10(-7)*KE}0.5-1) (As per IRC 6 Page No. 79 )

=3100*(1+1.3*10Ke Pawer -7*9.1*10 Ke Power)0.5-1)

=103654.198 mm

Barge Collision Impact Factor

For Ab>100 mm Pb= 6.0* 10ke power 6 +1600*(ab) ,in N (As per IRC 6 Page No. 79 )

= 6.0* 10ke power 6 +1600*103654.198=171346 kn

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