Challenge

Understanding the concepts on Degrees of Freedom

Aim:

  1. To compute Ln, Mn and Tn for each of the five modes from the given equations
  2. To calculate the effective modal mass Mn* and the modal mass participating ratio for the modes
  • To obtain the Base shear for each of the modes of vibration and combined base shear as per SRSS rule

Procedure:

Step 1:  Mn = ønTmøn

Mode 1:

Mode of vibration, T1 = 2 sec

                        M1 = ø1T1ø1
                   

Mode 2:

Mode of vibration, T2 = 0.6852 sec

                        M2 = ø2Tmø2
                   

Mode 3:

Mode of vibration, T3 = 0.4346 sec

                        M3 = ø3Tmø3
                   

Mode 4:

Mode of vibration, T4 = 0.3383 sec

                        M4= ø4Tmø4
                   

Mode 5:

Mode of vibration, T5 = 0.2966 sec

                        M5= ø5Tmø5
                   

Step 2: To find Ln

Ln =ønTmI

Mode 1:

Mode of vibration, T1 = 2 sec

                        L1 =ø1TmI


                   

Mode 2:

Mode of vibration, T2 = 0.6852 sec

                        L2 =ø2TmI
                   

 

Mode 3:

Mode of vibration, T3 = 0.4346 sec

                        L3 =ø3TmI                  

 

Mode 4:

Mode of vibration, T4 = 0.3383 sec

                        L4 = ø4TmI
                   

Mode 5:

Mode of vibration, T5 = 0.2966 sec

                        L5 =ø5TmI
                   

                   

Step 3: Finding Tn

Tn = Ln /Mn

T1 =L1/M1  = 1.067

T2 =L2/M2  = -0.33

T3=  L3/M3 = 0.178

T4 = L4/M4 = -0.09

T5 = L5/M5  = 0.04

Step 4: Finding Effective modal mass, Mn*

Mn* = Ln2 /Mn

M1* = L12 /M1 = 4.39M

M2* = L22 /M2 = 0.43M

M3* = L32 /M3 = 0.12M

M4* = L42 /M4 = 0.03M

M5* = L52 /M5 = 0.007M

Step 5: Finding Modal mass participating ratio

Modal mass participating ratio = Mn* / Mj

Mj = M+M+M+M+M = 5M

Modal mass participating ratio for Mode 1 = M1* / Mj  = 0.88

Modal mass participating ratio for Mode 2 = M2* / Mj  = 0.086

Modal mass participating ratio for Mode 3 = M3* / Mj  = 0.024

Modal mass participating ratio for Mode 4 = M4* / Mj  = 0.006

Modal mass participating ratio for Mode 5 = M5* / Mj  = 0.001

Step 6: To obtain the Base shear

Vbn = Mn* * An

For Mode 1

For T1 = 2 sec, A1 = 0.28g

Vb1 = M1* * A1 = 2.612

For Mode 2

For T2 = 0.6852 sec, A2 = 0.77g

Vb2 = M2* * A2 = 0.719

For Mode 3

For T3 = 0.4346 sec, A3 = 1.03g

Vb3 = M3* * A3 = 0.272

For Mode 4

For T4 = 0.3383 sec, A4 = 1.03g

Vb4 = M4* * A4 = 0.067

For Mode 5

For T5 = 0.2966 sec, A5 = 0.77g

Vb5 = M5* * A5 = 0.011

Step 7: Using SRSS rule

Vb = (Vb12+ Vb22+ Vb32+ Vb42+ Vb52)1/2

        = 3.2 kip

Result: 

  • Two modes are considered such that a model mass participating ratio of 90% is obtained. ie;  M1* / Mj  + M2* / Mj
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