Challenge

To calculate the dead , live and wind load for RC residential structure and to apply them using TSD

1.

Aim:

To calculate the dead load as per the design and IS code specifications

Given data:-

thickness of the floor finish is 50mm

assume the thickness of the exterior wall as 230mm

assume the thickness of the interior wall as 150mm

Calculation of dead load

  • dead load due to floor finish
  • thickness of the floor finish is 50mm
  • assume the unit weight of the material as 24kn/m^3
  • dead load = 0.05 x 24 =1.2 kn/m^2

dead of the slab due to its self weight is taken directly by the model

dead load of the brick wall

  • assume the unit weight of the brick material as 20kn/m^3
  • height of the floor level is 3.5m
  • dead of the exterior brick wall is 0.23 x 3.5 x 20 =16 kn/m
  • dead load of the roof is taken as 1.5kn/m^2
  • dead of the interior brick wall is 0.15 x 3.5 x 20 =10.5kn/m

To define the load cases

go to load from the tool bar

click on the loadcases

add the loadcases in the given dialogue box

To assign the loads to the model

Floor finish and brick wall load applied at the ground floor level

Floor finish and brick wall load applied at the first floor level

Loading applied at the roof level

2.

Aim

To calculate the live loads and apply them on to the model

Live loads are obtained from the IS code 875 part 2

office room = 2kn/m^2

toilets = 2kn/m^2

commom area = 3kn/m^2

staircase = 3kn/m^2

conference room = 5kn/m^2

To apply these loads on to the model

3.

Aim:

To calculate the wind loads and apply them on to the model

Given data:

  • basic wind speed is given as 50m/s
  • assume the design period as 50years
  • consider the terrain category as 2
  • length of the structure is 19.225
  • width of the structure is 13.32
  • height of the structure is 7.5

ratio of wall and roof coefficients

  • wall coefficient l/w = 19.225/13.32 = 1.44
  • roof coefficient = h/w = 7.5/ 13.32 = 0.56

design wind speed

Vb is given as 50m/s

  • risk coefficient = 1 (for design life of 50 years with basic wind speed as 50m/s)
  • terrain roughness = 1 ( for catergory 2 structures below the height od 10m)
  • topography factor = 1 ( for roof slope of less than 3 degrees)
  • importance factor = 1 ( for other structures)

Vb = 50 x 1 x 1 x1 x 1= 50

Design wind pressure

  • Pz = 0.6 x 50^2= 1500 n/m^2
  • Pz = 1.5 kn/m^2

Wind load calculations:

+ Cpi - Cpi
external pressure coefficients 0.7 0.7
internal pressure coefficients 0.5 -0.5
net pressure 0.2 1.2
load factor 1.5 1.5
wind load 0.3 1.8
+ Cpi - Cpi
external pressure coefficients -0.25 -0.25
internal pressure coefficients 0.5 -0.5
net pressure -0.75 0.25
load factor 1.5 1.5
wind load -1.125 0.375
+ Cpi - Cpi
external pressure coefficients -0.6 -0.6
internal pressure coefficients 0.5 -0.5
net pressure -1.1 -0.1
load factor 1.5 1.5
wind load -1.65 -0.15

h/w = 0.78

+ Cpi - Cpi
external pressure coefficients -0.88 -0.4
internal pressure coefficients 0.5 0.5
net pressure -0.13 -0.9
load factor 1.5 1.5
wind load -0.195 -1.35

Result:

wind loads are calculated manually

4.

Aim:

To apply the above calculated wind loads on to the model

To define the load cases

go to load from the menu toolbar

select on the load cases

then add all the above wind load cases

To assign the loads on the model

Result:

wind loads have been applied to the model

Your portfolio, next

Ship work like this
in your own course.

Talk to a career counsellor

Free 20-minute call. We'll map the right course to where you want to work.

By submitting you agree to our Terms and Privacy Policy.

Talk to a career counsellor

Free 20-minute call. We'll map the right course to where you want to work.

By submitting you agree to our Terms and Privacy Policy.