To calculate the dead , live and wind load for RC residential structure and to apply them using TSD
1.
Aim:
To calculate the dead load as per the design and IS code specifications
Given data:-
thickness of the floor finish is 50mm
assume the thickness of the exterior wall as 230mm
assume the thickness of the interior wall as 150mm
Calculation of dead load
- dead load due to floor finish
- thickness of the floor finish is 50mm
- assume the unit weight of the material as 24kn/m^3
- dead load = 0.05 x 24 =1.2 kn/m^2
dead of the slab due to its self weight is taken directly by the model
dead load of the brick wall
- assume the unit weight of the brick material as 20kn/m^3
- height of the floor level is 3.5m
- dead of the exterior brick wall is 0.23 x 3.5 x 20 =16 kn/m
- dead load of the roof is taken as 1.5kn/m^2
- dead of the interior brick wall is 0.15 x 3.5 x 20 =10.5kn/m
To define the load cases
go to load from the tool bar
click on the loadcases
add the loadcases in the given dialogue box

To assign the loads to the model
Floor finish and brick wall load applied at the ground floor level

Floor finish and brick wall load applied at the first floor level

Loading applied at the roof level


2.
Aim
To calculate the live loads and apply them on to the model
Live loads are obtained from the IS code 875 part 2
office room = 2kn/m^2
toilets = 2kn/m^2
commom area = 3kn/m^2
staircase = 3kn/m^2
conference room = 5kn/m^2
To apply these loads on to the model

3.
Aim:
To calculate the wind loads and apply them on to the model
Given data:
- basic wind speed is given as 50m/s
- assume the design period as 50years
- consider the terrain category as 2
- length of the structure is 19.225
- width of the structure is 13.32
- height of the structure is 7.5
ratio of wall and roof coefficients
- wall coefficient l/w = 19.225/13.32 = 1.44
- roof coefficient = h/w = 7.5/ 13.32 = 0.56
design wind speed
Vb is given as 50m/s
- risk coefficient = 1 (for design life of 50 years with basic wind speed as 50m/s)
- terrain roughness = 1 ( for catergory 2 structures below the height od 10m)
- topography factor = 1 ( for roof slope of less than 3 degrees)
- importance factor = 1 ( for other structures)
Vb = 50 x 1 x 1 x1 x 1= 50
Design wind pressure
- Pz = 0.6 x 50^2= 1500 n/m^2
- Pz = 1.5 kn/m^2
Wind load calculations:
| + Cpi | - Cpi | |
| external pressure coefficients | 0.7 | 0.7 |
| internal pressure coefficients | 0.5 | -0.5 |
| net pressure | 0.2 | 1.2 |
| load factor | 1.5 | 1.5 |
| wind load | 0.3 | 1.8 |
| + Cpi | - Cpi | |
| external pressure coefficients | -0.25 | -0.25 |
| internal pressure coefficients | 0.5 | -0.5 |
| net pressure | -0.75 | 0.25 |
| load factor | 1.5 | 1.5 |
| wind load | -1.125 | 0.375 |
| + Cpi | - Cpi | |
| external pressure coefficients | -0.6 | -0.6 |
| internal pressure coefficients | 0.5 | -0.5 |
| net pressure | -1.1 | -0.1 |
| load factor | 1.5 | 1.5 |
| wind load | -1.65 | -0.15 |
h/w = 0.78
| + Cpi | - Cpi | |
| external pressure coefficients | -0.88 | -0.4 |
| internal pressure coefficients | 0.5 | 0.5 |
| net pressure | -0.13 | -0.9 |
| load factor | 1.5 | 1.5 |
| wind load | -0.195 | -1.35 |
Result:
wind loads are calculated manually
4.
Aim:
To apply the above calculated wind loads on to the model
To define the load cases
go to load from the menu toolbar
select on the load cases
then add all the above wind load cases

To assign the loads on the model




Result:
wind loads have been applied to the model