Challenge

Section Modulus calculation and optimization

AIM:

Section modulus calculation and optimization

OBJECTIVE:

Use section of the Hood and calculate the section modulus.

Vary the section in such a way that new section is an improved version of previous section.

THEORY:

Section modulus is to find the geometric property for a given cross-section used in the design.

Calculate the section modulus using the formula S=I/Y

S= Section modulus

I= Moment of Inertia

Y= Distance between neutral axis and the extreme end of the object

Section Modulus Calculation:

For studying the section modulus we need the cross section of hood.

Study 1:

1. Hood Design:

Moment of Inertia (MOI), Imax = 4.808047941 x 10^6 [mm^4]

Moment of Inertia (MOI), Imin = 1.402843414 x 10^4 [mm^4]

Distance between the neutral axis and the extreme end of the object, y = 878.6407 mm / 2 = 439.320 mm

Section Modulus, S = Moment of Inertia (MOI), I / Distance between the neutral axis and the extreme end of the

object (y)

For Maximum (MOI),

S = (4.808047941 x 10^6 mm^4) / (439.320 mm)

Smax = 10.944295 x 10^3 mm^3

For Minimum (MOI),

S = (1.402843414 x 10^4 mm^4) / (439.320 mm)

Smin = 0.0319321545 x 10^3 mm^3

Study 2:

Decreased the distance between the outer panel and inner panel to 1mm. MOI as shown below

Moment of Inertia (MOI), Imax = 4.822224063 x 10^6 [mm^4]

Moment of Inertia (MOI), Imin = 1.406290856 x 10^4 [mm^4]

Distance between the neutral axis and the extreme end of the object, y = 878.6407 mm / 2 = 439.320 mm

Section Modulus, S = Moment of Inertia (MOI), I / Distance between the neutral axis and the extreme end of the

object (y)

For Maximum (MOI),

S = (4.822224063 x 10^6 mm^4) / (439.320 mm)

Smax = 10.97656 x 10^3 mm^3

For Minimum (MOI),

S = (1.406290856 x 10^4 mm^4) / (439.320 mm)

Smin = 0.00320106 x 10^3 mm^3.

CONCLUSION:

Section Modulus of Hood of the car was calculated and optimized section modulus with some changes or optimization and found some better results.

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