Section Modulus calculation and optimization

SECTION MODULUS CALUCULATION AND OPTIMIZATION

SECTION MODULUS:

It is a way of quantifying a cross-section of a given geometry. It is directly proportional to the area moment of inertia of the cross-section. Higher the section modulus, the more the moment of inertia, more stiffness and thus more resistance to deformation and bending. Section modulus can be improved by varying the geometry of the cross-section. In other words, stiffness can be improved by just improving the geometry without the need for adding extra material.

Section Modulus(S) Calculation:

S= I / Y

Where, S – Section Modulus,

I – Area Moment of inertia or Second Order Moment of inertia.

Y(Max)- Distance of Extreme Layer from Neutral Axis.

Section#: 1

Hollow
CG: (-0.000000000, 752.497005892, -932.060983507) [mm]
MOI (Max):8.132824511e+05[mm⁴]
MOI (Min):3.465912701e+03[mm⁴]
Principal Directions:
Max: (0.000000000, 0.980974686, 0.194135686)
Min: (0.000000000, -0.194135686, 0.980974686)
Length:2.023651745e+03mm
Area:40.471420603[mm²]

Distance of Extreme Layer from Neutral Axis (Y) - 986.9mm/2= 439.45mm

Section Modulus (s) = I / Y =34659.12701/ 439.45= 78.86 [mm^3]

From the section#: 1, using Minimum Moment of Inertia and extreme distance of layer, we got the section modulus(S) value is 78.8[mm^3].

Section 2

Section#: 1

Hollow
CG: (-0.000015035, 752.404123108, -931.916930683) [mm]
MOI (Max):8.731655291e+05[mm⁴]
MOI (Min):3.468580829e+03[mm⁴]
Principal Directions:
Max: (0.000000575, 0.980974130, 0.194138500)
Min: (-0.000000059, -0.194138500, 0.980974130)
Section Length:2.078200342e+03mm
Section Area:41.560593999[mm²]

Distance of Extreme Layer from Neutral Axis (Y) - 986.9mm/2= 439.45mm

Section Modulus (s) = I / Y =34817.32829/ 439.45= 79.22 [mm^3]

From the section#: 1, using Minimum Moment of Inertia and extreme distance of layer, we got the section modulus(S) value is 79.22[mm^3].