Section Modulus calculation and optimization
Hood Section Modulus Calculation and Optimization
Section Modulus
- The ratio of total movement restricted by the section to the stress in the extreme fiber
- If the section modulus increases the movement of resistance increases and hence its load-bearing capacity.
Formula:
S = i/y
Where,
S = Section Modulus (mm3)
i = Moment of Inertia (mm4)
y = distance between the neutral axis and the extreme end of the object (mm)
Case 1: Calculating Section Modulus for Existing Hood
Creating External Boundry for Section Inertia Calculations
- Take the Clip section of the current Hood Inner Panel and Hood Outer Panel
- Specify the plane on which section needs to be made (In this case XY plane)
- Scroll down to Section Curve Setting > Select Save Copy of Section Curve to get the selected section.


- Now to edit the section we need to project the Section on the New Sketch on a parallel plane by selecting the external boundaries of the Hood Outer Panel and Hood Inner Panel.

- Now join both projected curves as shown in the image below, to calculate Section Inertia.

- Further, search for Section Inertia Analysis and select the current curve.
- Detailed information about Center of Gravity, Max Moment of Inertia, Min Moment of Inertia, Section length, and Section Aera will be displayed.



Calculations:
Inputs
Max Moment Of Inertia (imax)= 8.240963433x105 mm4
Mim Moment Of Inertia (imin) = 6.251384949x103 mm4
Distance between two extreme ends = 478mm
i.e: Distance between the neutral axis and the extreme end of the object (y) = 478/2 mm
y = 239 mm
Section Modulus for Existing Hood (S1) = Moment of Inertia (i)
Distance between the neutral axis and the extreme end of the object (y)
Therefore,
by considering min moment of inertia (imin)
S1 = 6.251384949x103 mm4 / 239 mm
S1 = 26.15642 mm3
Case 2: Calculating Section Modulus for Optimized Hood
- To improve section modulus, the area of the section needs to be increased,
- Offsetting the Projected curve of the Hood Inner Panel by 0.5mm.

Section Inertia Analysis

Calculations:
Inputs
Max Moment Of Inertia (imax)= 8.215689200x105 mm4
Mim Moment Of Inertia (imin) = 6.453749426x103 mm4
Distance between two extreme ends = 478mm
i.e: Distance between the neutral axis and the extreme end of the object (y) = 478/2 mm
y = 239 mm
Section Modulus for Optimized Hood (S2) = Moment of Inertia (i)
Distance between the neutral axis and the extreme end of the object (y)
Therefore,
by considering min moment of inertia (imin)
S2 = 6.453749426x103 mm4 / 239 mm
S2 = 27.00313 mm3
Conclusion:
1. Section Modulus of Case 2 is greater than Section Modulus of Case 1
2. Section Modulus is directly proportional to Moment of inertia and Section Area
i.e: As section area increases valve of Section Modulus increases.
3. Case 2 will have greater strength than Case 1 and will have increased load carrying capacity.