Challenge

Section Modulus calculation and optimization

Aim:

To find the section modulus of the hood and optimization to improve the overall section modulus.

Objective:

calculate the section modulus using the formula S= I/y by using the Hood design.

Section Modulus:

The section modulus (S) is geometry property of the cross section used for designing beams and flexural members. It does not represent anything physically.

Formula of section Modulus: It may be defined as the ratio of total moment resisted by the section to the stress in the extreme fibre which is equal to yield stress.

Which is equal to yield stress.

Therefore

S=I/y, Where

S= Section modulus (mm^3)

I = Moment of inertia of the section to the stress in the extreme end of the object (mm^4)

Y= Distance between the neutral axis and extreme end of the object (mm).

Calculation:

Section Modulus :

Case 1:

  • Here we are considered the innerpannel section of the to analysis the section inertia analysis after doing the we got the desired results shown in the above image

I (MAX) = 4.590567193e+04(mm^4)

I (MIN) = 4.332774364 (mm^4)

As per the section modulus equation,

S = I/Y

I = MOI (min) Value is considered

Y = Total distance / 2

Y=479.5191/2

Y=239.75

Therefore,

S = 43327.74364 mm^3 /239.75 mm

S1 = 180.74313mm^3

Case 2:

  • Here we are considered an section of inner pannel at the cureved region and by doing the analysis we got the desired results shwon below

I (MAX) = 7.054060364e+03 (mm^4)

I (MIN) = 5.018879483 (mm^4)

As per the section modulus equation,

S = I/Y

I = MOI (min) Value is considered

Y = Total distance / 2,

Total distance ,Y= 258.095 mm

Therefore,

S = 50188.79483/258.095 mm

S2= 194.458 mm^3

Results:

The difference between the above both the cases of section modulus is 14.458mm

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