Challenge

Section Modulus calculation and optimization

Section Modulus calculation and optimization

The section modulus is a concept in structural design that measures the bending strength of a cross-section.

It’s a area of moment od inertia about the neutral axis and to the distance of outermost fiber from the neutral axis

Z = I/y

Z is section modulus

I is moment of inertia

y is distance from the neutral axis to end

Example:

Rectangular bar

For stronger Axis,

I1 = bd3 / 12

Z1 = I1 / y1 = (bd3 / 12) / (d/2) = bd2/6

For weaker Axis,

I2 = b3d / 12

Z2 = I2 / y2 = (db3 / 12) / (d/2) = db2/6

For Hood,

y=d/2

d=875.9309

y=875.9309/2 = 438 mm

For first case,

Imax = 9.0958944*107 mm4 Imin = 2.93894039*105 mm4

y= 438 mm y= 438 mm

Zmax = Imax / y Zmin = Imin / y

Zmax = 9.0958944*107 / 438 Zmin = 2.93894039*105 / 438

Zmax = 207*103 mm3 Zmin = 0.67*103 mm3

For second case,

Imax = 9.1127054*107 mm4 Imin = 2.9020776*105 mm4

y= 438 mm y= 438 mm

Zmax = Imax / y Zmin = Imin / y

Zmax = 9.1127054*107 / 438 Zmin = 2.9020776*105 / 438

Zmax = 208*103 mm3 Zmin = 0.6*103 mm3

Conclusion:

The greater the section modulus, the greater the bending resistance of a structural element.

Drive link: https://drive.google.com/file/d/13Y2T9Qzil2OOf6ZudoUARTdpyyGOcBDy/view?usp=drive_link

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