Challenge

Section Modulus calculation and optimization

CALCULATION AND OPTIMIZATION OF SECTION MODULAS OF CAR HOOD

OBJECTIVE:

  • TO CALCULATE SECTION MODULAS OF PREVIOUSLY CREATED CAR HOOD DESIGN, WITH THE HELP OF HOOD CROSS-SECTION AND ANALYZE THE RESULT.
  • TO COME UP WITH NEW DESIGN TO IMPROVE THE SECTION MODULAS OF EXISTING HOOD IN ORDER TO OBTAIN BATTER RESULT.

INTRODUCTION:

IT IS DEFINED AS THE RATIO OF MOMENT OF INERTIA (I) AND THE DISTANCE FROM THE NEUTRAL AXIS TO ANY EXTREAM FIBER (Y).

THE SECTION MODULAS (Z/S) OF THE CROSS-SECTIONAL SHAPE IS SIGNIFICANT IN DESIGNING BEAMS. IT IS A DIRECT MEASURE OF THE STRENGTH OF THE BEAM. A BEAM THAT HAS A LARGER SECTION MODULAS THAN OTHER WILL BE STRONGER AND CAPABLE TO WITHSTANG LARGER LOAD.

FORMULA FOR CALCULATING SECTION MODULAS:

SorZ= I/Y

S or Z - SECTION MODULAS

I - MOMENT OF INERTIA

Y - LENGTH OF EXTREAM FIBER FROM NEUTRAL AXIS

CALCULATION OF SECTION MODULAS OF INITIAL HOOD DESIGN

TAKING CROSS-SECTION OF EXISTING HOOD DESIGN ALONG X-X AXIS IN NX-CAD TO CALCULATE MOMENT OF INERTIA

CROSS-SECTION OF HOOD

#SECTIONAL REPORT

AS WE REQUIRE TO FIND MINIMUF STRENGTH OF HOOD FOR MAXIMUM SAFETY WE NEED TO SELECT MINIMUM MOMENT OF INERTIA (MOI (MIN)).

THEREFORE,

Imin = 2.801985499e^5 MM^4

Y = 439.808033005

S = I/Y

= 2.801985499e^5/439.808033005

S1 = 637.0922842 MM^3

CALCULATION OF SECTION MODULAS OF OPTIMIZED HOOD DESIGN

TO IMPROVE THE VALUE OF SECTION MODULAS WE REQUIRE TO OPTIMIZE THE PRESENT HOOD DESIGN.

FOR THAT WE OFFSETED THE INNER PANEL OF THE HOOD BY O.75MM, INORDER TO INCREASE THE SECTIONAL AREA OF THE HOOD (AS THE OUTER PANELS ARE NOT ALLOWED TO MODIFY WE SELECTED THE INNER PANEL)

AS SECTION MODULAS IS DIRECTLY PROPOTIONAL TO THE SECTION OF BODY, INCREASING THE SECTION AREA WILL INCREASE THE SECTION MODULAS.

CROSS SECTION OF IMPROVED HOOD DESIGN

SECTIONAL REPORT

HERE WE CAN SEE THE MOMENT OF INERTIA IS INCREASED COMPARED TO PREVIOUS DESIGN.

CALCULATION SECTION MODULAS OF OPTIMIZED DESIGN

Imin = 2.85357050e^5 MM^4

Y = 439.808033005

THEREFORE,

S2= I/Y

= 2.85357050e^5/439.808033005

S2= 648.82182 MM^3

HERE WE CAN CLEARLY SEE THAT S2>S1 WHICH IS,

S1 = 637.0922842 MM^3 > S2= 648.82182 MM^3

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