Section Modulus calculation and optimization

Section Modulus:

Section modulus (S) is defined as the ratio of the moment of inertia(I) of a section to the distance between the neutral axis and the extreme end of the object(Y).

The formula for the section modulus is given as: S= I/Y

SECTION #1:

• For this calculation, I have taken my hood design as a reference.
• In regards to the values, find the hood's inertia using NX Cad's section inertia analysis tool.
• Moreover, gauge the hood's length.
• Then, the Section modulus is calculated by using given formula. i.e,

S= I/Y

Where,

S= Section modulus,

I(min.)=Moment of inertia(min.) = 2.752858041*10^⁵[mm^4]

Y= Distance from neutral axis to extreme end = (L/2) = 876.6146/2 = 438.3073

S = 2.75285*10^⁵ / 438.3073

S = 628.064 mm^³

In order to calculate the strength of the hood panel, I have optimized the hood section area by shifting the hood inner panel downward by 0.5 mm.

SECTION #2:

• For this calculation, I have taken my hood design as a reference.
• In regards to the values, find the hood's inertia using NX Cad's section inertia analysis tool.
• Moreover, gauge the hood's length.
• Then, the Section modulus is calculated by using given formula. i.e,

S= I/Y

Where,

S= Section modulus,

I(min.)=Moment of inertia(min.) = 2.820636129*10^⁵[mm^4]

Y= Distance from neutral axis to extreme end = (L/2) = 876.6146/2 = 438.3073

S = 2.82063*10^⁵ / 438.3073

S = 643.528 mm^³

Section #1:

S = 628.064 mm^³

Section #2:

S = 643.528 mm^³

1. Section #2 has a higher section modulus value than Section #1.
2. The moment of inertia and section modulus values rise as the section area is raised by 0.5 mm. This implies that material strength and load also rise.