Challenge

Section Modulus calculation and optimization

SECTION MODULUS OF INERTIA :  It is the ratio of area moment of inertia about the neutral axis and to the distance of outermost fiber from the neutral axis. 

                                                    Z = I / Y

                   Z = section modulus,

                   I = area moment of inertia,

                   Y = distance from neutral axis to the outermost fiber.

FIRST SECTION MODULUS OF INERTIA 

SECOND SECTION OF MODULUS

 Y = distance from neutral axis to the outermost fiber.

        RESULT : Y = 348.2 

Z = I/Y = 1.0/348.2 = 0.28 N-m

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