Challenge

Section Modulus calculation and optimization

Section Analysis: It is the Ratio of Total moment resisted by section to stress in extreme fibre

It gives an idea that how much load can handle for certain things.

Formula for Section Modules: S=I/Y where,

S= Section Module

I= Moment of Inertia

Y= Distance between neutral Axis to extreme end of Object.

I (max)= 8.339408617*10^5mm4

I(min)= 7.921297937*10^3mm4

Y= 484.5887/2= 242.29435mm

S(max)= I(max)/Y

= 8.339408617*10^5mm4/242.29435

= 0.034418502193716*10^5

S(min)=I(min)/Y

= 7.921297937*10^3mm4/242.29435

= 0.0326928710347559*10^3

So the strength various from max0.034418502193716*10^5 to min 0.0326928710347559*10^3

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If we increase the area of inertia will change the strength according to that lets see,

After offestting the lower extracted curve to outside the results are here:

I(max)= 8.299903858*10^5mm4

I(min)= 8.283026286*10^3mm4

S=I/Y

S(max)= I(max)/Y

= 8.299903858*10^5mm4/242.29435

= 0.0342554577025837*10^5mm4

S(min)=I(min)/Y

=8.283026286*10^3mm4/242.29435

= 0.034185800395263*10^3mm4

Conclusion: When increses the area of Sections so the strength of Part will be changes.

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