Section Modulus calculation and optimization
AIM
To Use the Section from Hood design and calculate the Section Modulus using the formula
S = I/y
Where,
S = Section Modulus
I = Moment of Inertia
y = distance between the neutral axis and the extreme end of the object
PROCEDURE:
The data are collected from taking the master section using the mid plane
Front crash Original:
Front crash 1.5mm offset:
Side Crash Original:
Side Crash 1.5mm offset:
SECTION VIEW PIC:
OBSERVATION
SAMPLE CALCULATION
CASE1)FRONT CRASH ORIGINAL
Imin (in Meters)=2.032*10^6 m
Imax(in Meters)=7.357*10^8 m
Imin (in mm)=2032000 mm
Imax (in mm)=735700000 mm
Total Dist=877.395 mm
Y=Total Dist./2 = 438.6975 mm
S=I/Y
Smin=Imin/Y ; Smax=Imax/Y
Smin=2032000/ 438.6975 => 4631.893 mm
Smax=735700000/438.6975 => 1677009.784mm
Savg=(4631.893+1677009.784)/2 => 840820.838mm
CASE2)FRONT CRASH 1.5MM
Imin (in Meters)=2.353*10^6
Imax(in Meters)=8.291*10^8
Imin (in mm)=2353000
Imax (in mm)=829100000
Total Dist=877.395
Y=Total Dist./2 = 438.6975
S=I/Y
Smin=Imin/Y ; Smax=Imax/Y
Smin= 2353000/438.6975 => 5363.604
Smax=829100000/438.6975 =>1889912.753
Savg=(5363.604+1889912.753)/2 =>947638.178
By Comparing both the cases
840820.838mm <947638.178mm
CASE1)SIDE CRASH ORIGINAL
Imin (in Meters)=1.333*10^8 m
Imax(in Meters)=6.452*10^5 m
Imin (in mm)=645200 mm
Imax (in mm)=133300000 mm
Total Dist=485.429 mm
Y=Total Dist./2 = 242.7145 mm
S=I/Y
Smin=Imin/Y ; Smax=Imax/Y
Smin=645200/ 242.7145 => 2658.267 mm
Smax=133300000/242.7145 => 549204.930mm
Savg=(2658.267+549204.930)/2 => 275931.598mm
CASE2)SIDE CRASH ORIGINAL
Imin (in Meters)=1.4958*10^8 m
Imax(in Meters)=7.582*10^5 m
Imin (in mm)=758200 mm
Imax (in mm)=149580000 mm
Total Dist=485.429 mm
Y=Total Dist./2 = 242.7145 mm
S=I/Y
Smin=Imin/Y ; Smax=Imax/Y
Smin=758200/ 242.7145 => 3123.834 mm
Smax=149580000/242.7145 => 616279.620mm
Savg=(3123.834+616279.620)/2 => 309701.727mm
By Comparing both the cases
3123.834mm <616279.620mm
CONCLUSION
WE HAVE PERFORMED DIFFERENT SECTION MODULUS OUT OF WHICH THE OFFSETTED HAVE HIGHRER SECTION MODULUS SO THAT IT WILL RESIST IN HIGHER BENDING MOMENT.