Reinforcement Detailing of Beams from ETABS output

AIM: RESONS FOR FAILURE OF THE MIDDLE ALONG GRID A POSSIBLE WAYS TO SOLVE

 PROCEDURE: CALCULATE VAUE OF MAX SHEAR FORCE IN ANY ONE  OF SPAN  

AS PER IS 13920-2016

LOGITUDENAL REINFORCEMENT OF BEAM AT GRID -3 FROM ETABS (mm2)

shorter reinforcement of beam at grid 3 from etabs (am2/100mm)

logitudenal reinforcement of beam at grid 3 from etabs(mm2)

sherat reinforcement of beam at grid 3 from etabs )xm2/100)

SWAY AT RIGHT AND LEFT AS PER IS 13290

right

Mas=174kMm                               

Mas=174kMm

Mbh=293kNm

Lab=4.725m

Vub=46kn

vub=230kn

left

Mah=234kMm                               

Mbs=155kMm

Vd+1=70kn

Lab=4.725m

Vua=185kn

Vub=45kn

SWAY SHEAR

EXISTING SHEAR CAPACITY AS PER DRAWING (AS PER IS 456 2000)

Vus=0.875FyAsvd/Sv

Fy=415N/mm2

ASv=151mm2

d=450mm

sv=100mm

Vus=245kn

hence shear in drawing is ok as per is 456 200

RESULT: S PER ALL THE  ARE DONE