Challenge

Project on Concrete Mix Design for various grades of Concrete

AIM 

       To calculate  the concrete mix design for M35 Grade concrete with fly ash

INTRODUCTION 

       Concrete mix design is a systmatic process of choosing economical relative proportation of various ingrediants from available mterial that gives the concrete of desired workability. The process of selecting suitable ingrediants of concrete of required strebgth, ductality, workability  as economical as possible is  known as concrete mix design.  It depends on quality and quantity of cement, water and aggregates.

STEPS:

     1.   Target mean strength of concrete = 35 + (1.65 * 5 ) = 43.25N/mm^2

     2.   Selection of water cement ratio

           From table 5 os IS 456 : 2000 for severe exposure Maximum water cement ratio = 0.4

           Based on experience adopt water cement ratio as 0.40

               0.40<0.45, hence O.K

     3.   Selection of water content

           From table 2 of IS 10262 :2009 , maximum water cement ratio of 20 mm aggregate = 186 litre

           Estimated  water content = 186+6%*186 = 197 litre

           As super plasticizer is used, the water content can be reduced upto 30%

           Based on trails of water content on reduction of 25% is achieved with plasticizer

           Hence arriced water content = 197*0.75 = 148 litres

     4.   Calculaton of cement content

           water cement ratio = 0.4

           cementitious material = 148/0.4 = 370 kg/m^3

             370>320 , Hence O.K

           Now to proportion mix containing fly ash the following steps are adopted

           a. The percentage of fly ash needs to be decided based on the project requirement and quality of materials

           b. In some cases increase in the cementitious material can be warrented.Increase in 10% of material is adopted

           Cementitious material content =  370*1.10 = 407 kg/m^3

           Water content = 140kg/m^3

           water cement ratio = 140/407 = 0.34

           Fly ash at 30% total cementitious material = 407*30% = 122kg/m^3

           Cement (opc)  = 407-122 = 285kg/m^3

           Saving cement using fly ash = 407-285 = 122kg/m^3

           Fly ash being utilized = 122kg/m^3

     5.   Proportion of coarse and fine aggregate

           From table 3 of IS 10262 : 2009 volume of coarse aggregate corresponding to 20 mm size aggregate and fine aggregate zone 1 for water cement ratio of 0.5 = 0.6

          At present water cement ratio is = 0.40

          The corrected volume of coarse aggregate for water cement ratio = 0.40 = 0.62

          For pumpable concrete reduced by 10%

          Volume of coarse aggregate = 0.62*0.9 = 0.56

          Volume of fine aggregate = 1-0.56 = 0.44

    6.   Mix calculations 

         a.  Volume of concrete = 1m^3

         b.  Volume of cement = 285/3.15*1000 = 0.090 m^3

         c.  Volume of Fly ash = 122/2.2*1000 = 0.055 m^3

         d.  volume if water = 148/1000 = 0.148 m^3

         e. Volume of chemical admixture = 7/1.145*1000 = 0.006 m^3

         f. Volume of aggregate = a-(b+c+d+e) = 0.701 m^3

         g. Mass of coarse aggregate = 0.701*0.56*2.74*1000 = 1075.61kg/m^3

         h. Mass of fine aggregate =  0.701*0.44*2.74*1000 = 845.12kg/m^3

    7.    Mix proportions

           Cement            = 285 kg/m^3

           Fly ash             = 122  kg/m^3

           Water               = 148  kg/m^3

           Fine aggregate  = 845.12  kg/m^3

          Coarse aggregate= 1075.61  kg/m^3

          Chemical admixtures = 7  kg/m^3

          water cement ratio = 0.34

          Trial mix ratio = 1 : 2.96 : 3.77

     8.   The slump must be measured and the water content,  dosage of admixture shall be adjusted for achieving the required slump on trial.  The  mix proporation shall be reworked for the actual water content and checked for durability requirements.

     9.   Two more trials having variation of 10%  of water cement ratio  shall  be carried out and a graph between water cement ratio and corresponding strengths shall be plotted to work out the mix proportions for the given target strength for field trials.  However durability shall be met.

RESULT:

           Concrete mix design of given M35 concrete grade is  1 : 2.96 : 3.77

AIM : 

      To calculate  the concrete mix design for M50 Grade concrete without fly ash

INTRODUCTION 

       Concrete mix design is a systmatic process of choosing economical relative proportation of various ingrediants from available mterial that gives the concrete of desired workability. The process of selecting suitable ingrediants of concrete of required strebgth, ductality, workability  as economical as possible is  known as concrete mix design.  It depends on quality and quantity of cement, water and aggregates.

STEPS:

     1.   Target mean strength of concrete = 50 + (1.65 * 5 ) = 58.25 N/mm^2

     2.   Selection of water cement ratio

           From table 5 os IS 456 : 2000 for severe exposure Maximum water cement ratio = 0.4

           Based on experience adopt water cement ratio as 0.40

               0.40<0.45, hence O.K

     3.   Selection of water content

           From table 2 of IS 10262 :2009 , maximum water cement ratio of 20 mm aggregate = 186 litre

           Estimated  water content = 186+6%*186 = 197 litre

           As super plasticizer is used, the water content can be reduced upto 30%

           Based on trails of water content on reduction of 25% is achieved with plasticizer

           Hence arriced water content = 197*0.75 = 148 litres

     4.   Calculaton of cement content

           water cement ratio = 0.4

           cement content = 148/0.4 = 370 kg/m^3

             370>320 , Hence O.K

5.   Proportion of coarse and fine aggregate

           From table 3 of IS 10262 : 2009 volume of coarse aggregate corresponding to 20 mm size aggregate and fine aggregate zone 1 for water cement ratio of 0.5 = 0.6

          At present water cement ratio is = 0.40

          The corrected volume of coarse aggregate for water cement ratio = 0.40 = 0.62

          For pumpable concrete reduced by 10%

          Volume of coarse aggregate = 0.62*0.9 = 0.56

          Volume of fine aggregate = 1-0.56 = 0.44

    6.   Mix calculations 

         a.  Volume of concrete = 1m^3

         b.  Volume of cement = 370/3.15*1000 = 0.117 m^3

         c.  volume if water = 148/1000 = 0.148 m^3

         d. Volume of chemical admixture = 7/1.145*1000 = 0.006 m^3

         e. Volume of aggregate = a-(b+c+d) = 0.729 m^3

         f. Mass of coarse aggregate = 0.729*0.56*2.74*1000 = 111.8.5kg/m^3

         g. Mass of fine aggregate =  0.729*0.44*2.74*1000 = 878.8kg/m^3

    7.    Mix proportions

           Cement            = 370 kg/m^3

           Water               = 148  kg/m^3

           Fine aggregate  = 878.8  kg/m^3

          Coarse aggregate= 1118 5  kg/m^3

          Chemical admixtures = 7  kg/m^3

          water cement ratio = 0.4

          Trial mix ratio = 1 : 2.37 : 3.02

     8.   The slump must be measured and the water content,  dosage of admixture shall be adjusted for achieving the required slump on trial.  The  mix proporation shall be reworked for the actual water content and checked for durability requirements.

     9.   Two more trials having variation of 10%  of water cement ratio  shall  be carried out and a graph between water cement ratio and corresponding strengths shall be plotted to work out the mix proportions for the given target strength for field trials.  However durability shall be met.

RESULT:

           Concrete mix design of given M50 concrete grade is  1 : 2.37 : 3.02

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