Project on Concrete Mix Design for various grades of Concrete
M35:with flyash without admixture
1. F'ck=Fck+1.65S
S= 5 from table 8 in IS456:2000
=43.25 N/mm2
2.W/C ratio from table5 in IS 456:2000
0.45 from table based on experience we can adopt 0.40 0.40<0.45 hence ok.
3. Water content from table 2
20 mm aggregate that is 186 litre for 25-50mm slump
Then (6/100)x186=197 litres.
Admixture is adding then 29%is reduced
0.71x197=140 litre
4. Cement content
C=140/0.4 = 350kg/M3
Cementitious material =350x1.10=385 kg/M3
Water content=140 kg/M3
W/C 140/485 =0.364
Flyash 30percentage =385*30%=115 kg/M3
Cement=385-115=270kg/M3
5. By using table 3 in IS 456:2000 W/C ratio 0.6 fir every 0.1 decrease in w/c ratio 0.01 increased in volume of CA and FA
0.4=0.62
Vol of concrete is reduced 10%for pumpable concrete
0.9x0.62=0.56 for CA
1-0.56=0.44 FA
a) volume of concrete= 1m3
b) volume of cement= 270/3.15 x 1/1000= 0.086m3
c) flyash = 115/2.2 X1/1000= 0.052m3
d) volume of water = 140/1 X1/1000 =0.14m3
e) volume of aggregate= (1-(0.086+0.052+0.14))
= 0.722
g) 0.722x0.56*2.74*x1000= 1107 kg/M3
h) 0.722*0.44*2.74*1000= 870kg/M3
1:3.2:4.1
M50 without fly ash without admixture
1. F'ck=Fck+1.65S
S= 5 from table 8 in IS456:2000
=58.25 N/mm2
2.W/C ratio from table5 in IS 456:2000
0.45 from table based on experience we can adopt 0.40 0.40<0.45 hence ok.
3. Water content from table 2
20 mm aggregate that is 186 litre for 25-50mm slump
Then (6/100)x186=197 litres.
Admixture is adding then 29%is reduced
0.71x197=140 litre
4. Cement content
C=140/0.4 = 350kg/M3
5. By using table 3 in IS 456:2000 W/C ratio 0.6 fir every 0.1 decrease in w/c ratio 0.01 increased in volume of CA and FA
0.4=0.62
Vol of concrete is reduced 10%for pumpable concrete
0.9x0.62=0.56 for CA
1-0.56=0.44 FA
a) volume of concrete= 1m3
b) volume of cement= 350/3.15 x 1/1000= 0.111m3
c)volume of water = 140/1 X1/1000 =0.14m3
d) volume of aggregate= (1-(0.111+0.14))
= 0.75
g) 0.75x0.56*2.74*x1000= 1150 kg/M3
h) 0.75*0.44*2.74*1000= 904kg/M3
1:2.58:3.28