Project 4
AIM:
For a vehicle of gross weight 300 kg, the motor ratings are 1200Wh, 65V. The range is 225km and the maximum speed is 60kmph. Calculate the capacity of the battery pack required and the number of series-parallel connections. Give a stepwise discussion on how a battery pack is built.
Note: Choose any relevant lithium ion datasheet
THEORY:

Given Data,
Vehicle Weight=300kg
Motor Rating=1200wh.65V
Range=225Km
Max Speed=50 kmph
First we have to calcualte Motor Current
Power = V*I
1200 = 65*I
I = 1200/65
I = 18.46 A
Current withdrawn By Motor 18.46 Amp
Assure Current Loss 1-10%
After loss new motor current
18.46*1.05=19.38 amp
Now Calculate the Power requried at max speed
At 60kmph power= Voltage*Current
Power= 65*19.38
power=1260w
Now calculate Travel Foctor
Travel Factor= Total Range/ Total Speed
Travel Factor = 225/60
Travel Factor= 3.75
To calculate Power based on Travel Factor
Power requried = Power*Travel Factor
power requried=1260*3.75= 4725 = 4.7 kw
Now calculate Battery pack capacity based of efficiency
Battery pack efficiency 85-95%
we Consider 85%
Required Battery Pack Capacity= 47/0.85 = 5.52 kw
To Calculate Battery pack efficiency based on motor efficieny
Total Battery Pack capacity = 5.52/0.85 = 6.49 kwh
Now we have to find how many connections comes in series and parallel
Series Connection
Motor Voltage 65 V
Cell Volatge 3.7v
No of series cells. 65/3.7 = 18
18 cells in series
Parallel Connection
Motor Current 19.38 A
Cell current 2.8 A
No of parallel cells 19.35/2.8 = 7nos.
7 Cells in parallel
How to design a battery pack /step by step method

Functions needed from a BMS

conclusion: