Challenge

Project 2

ANS 1. WIDTH OF THE INDUSTRIAL BUILDING= 30 m.

LENGTH OF THE INDUSTRIAL BUIDING= 50m.

EAVE HEIGHT = 9 m.

BAY SPACING = 6 m.

SOIL TYPE = MEDIUM.

ROOF SLOPE= 1 in 12.

AREA OF THE BUILDING= 50*30

= 1500 M2.

NUMBER OF BAYS= 30/6 = 5 BAYS.

LOAD COMBINATION= DEAD LOAD + LIVE LOAD + WIND LOAD + CRANE LOAD.

AS THE LOCATION OF OUR BUILDING IS IN CHENNAI THE EARTHQUAKE LOAD WILL BE SIGNIFICANTLY LESS THAN THE EARTHQUAKE LOAD SO WE CAN IGNORE EARTHQUAKE LOAD.

DEAD LOAD= SELF WEIGHT OF THE STRUCTURE. IT INCLUDES THE WEIGHT OF ROOFING, GI SHEETS, GANTRY GIRDER, CRANE GIRDER, PURLIN, SAG BRACING.

DEAD LOAD DISTRIBUTED OVER ROOF= 0.438 KN/M.

TOTAL DEAD LOAD= 0.438*1500.

= 657 KN.

TOTAL LIVE LOAD = 0.75 KN/M2 (NO EXCESS TO ROOF IS PROVIDED).

= 075-0.04 = 0.71 KN/M2. (REDUCTION OF 0.02 FOR EVERY 1DEG SLOPE ABOVE 10 DEGREES).

= 0.71*1500.

= 1065 KN.

LIVE LOAD ACTING ON THE RAFTER= 4.5 KN/M.

AS WE HAVE BAY SPACING = 6M.

FROM HERE WE WILL GET LENGTH OF ONE RAFTER= 4.245 M.

NOW IN ONE BAY SPACING WE ARE USING 2 RAFTERS.

THEN OUR TOTAL LENGTH OF RAFTERS WILL BE 42.43 METRES.

LIVE LOAD DUE TO RAFTERS = 42.43*4.5

= 190.9 KN = 191 KN.

CRANE LOAD-

THE DEAD LOAD OF CRANE SYSTEM ALONG WITH GANTRY GIRDER = 7KN. (OVER COLUMN BRACKETS)

CASE VERTICAL CRANE LIVE LOAD(KN) HORIZONTAL CRANE LIVE LOAD(KN)

LEFT CORBEL RIGHT CORBEL

CL1 124.33 47.61 16.50

CL2 47.61 124.33 16.50

CL3 124.33 47.61 -16.50

CL4 47.61 124.33 -16.50

WIND LOAD-

BASIC WIND SPEED = 39m/sec.

WIND LOAD OVER THE ROOF AND SIDE WALLS COMES IN DIFFERENT COMBINATIONS-

CASE SIDE WALL(KN/M) PEB RAFTER(KN/M)

LEFT RIGHT

WIND ANGLE= 0+ 2.61 -2.35 5.74

WIND ANGLE= 90+ -3.65 -3.65 5.74

WIND ANGLE=0 4.70 -0.26 3.65

WIND ANGLE=90- -1.57 -1.57 3.65.

NOW THERE ARE 16 LOAD COMBINATIONS THAT CAN BE CREATED.LET US HAVE A LOOK AT THEM-

1. 1.5 DL +1.5 LL + 1.5CL1.

2. 1.5DL + 1.5 LL + 1.5 CL2.

3. 1.5 DL+ 1.5 LL + 1.5 CL3

4. 1.5DL + 1.5 LL + 1.5 CL4

5. 1.5 DL+ 1.5 WL (ANGLE= 0+)

6. 1.5 DL+ 1.5 WL (ANGLE= 90+)

7. 1.5 DL + 1.5WL(ANGLE= 0-)

8. 1.5 DL+ 1.5 WL(ANGLE = 90-) CONTD....

WE WILL TAKE FIRST ONE AS IT WILL GIVE THE MAXIMUM VALUE OF THE LOAD COMBINATIONS.

LIVE VERTICAL LOAD IN THE RIGHT AND LEFT CORBEL= 124.33+47.61

= 171.9 KN.

HORIZONTAL LIVE LOAD= 16.50 KN.

TOTAL DEAD + LIVE LOAD DUE TO CRANE LOAD= 7+ 171.9

= 179 KN.

TOTAL LOAD IF WE WERE TO TAKE THE COMBINATION NUMBER 1.

= 1.5 DL+ 1.5 LL+ 1.5 CL1.

= 1.5*657+ 1.5*1256+ 1.5*179.

= 985.5+ 1884+268.5

= 3138 KN.

DESIGN FOR FOOTING-

AXIAL LOAD= 3138 KN.

MOMENT LOAD= 16.5*9

= 148.5 KNM.

WE WILL BE USING M20 GRADE OF CONCRETE AND STRENGTH OF REINFORCEMENT= 500N/MM2.

BEARING CAPACITY OF SOIL= 200KN/M2.

FOR SAFETY PURPOSES WE WILL ASSUME IT AT 250 KN/M2.

TOTAL LOAD= 1.5*3138

= 3451.8 KN.

AREA OF FOOTING= 3451.8/250

= 13.8M2.

TAKING 10PERCENT INCREASE IN AREA, WE GET AREA= 15.1879 M2.

TAKING IT TO BE SQUARE FOOTING , SIDE OF FOOTING= 3.8972M

= 4.5M.

Pmax= 3451.8/4.5*4.5+ 148.5/(4.5*4.5)

= 178 KN <200KN/M2. HENCE SAFE.

ANS 2. DESIGN FOR GANTRY GIRDER-

UNIFORMLY DISTRIBUTED LOAD ON CRANE GIRDER= 100/9

= 11.11KN.

CONCENTRATED LOAD = 250+40= 290KN.

MINIMUM HOOK APPROACH = 1M.

LOAD ON EACH WHEEL= 145 KN.

IMPACT LOAD FOR AN ELECTRIC GIRDER= 25 PERCENT OF MAX LOAD.

= 36.25KN.

WE CAN TAKE IT TO BE 50 KN.

WAYS TO CALCULATE THE MAXIMUM BENDING MOMENT-

UNIFORMLY DISTRIBUTED LOAD ON GANTRY GIRDER= 100+0.2

= 100.2 KN.

MAXIMUM BENDING MOMENT= 100.2*1.5

= 150.3 KNM.

THIS BM WILL OCCUR AT THE WHEEL WHICH IS NEARER TO THE CENTRE OF TROLLEY.

SHEER FORCE IS MAXIMUM WHEN ONE OF THE WHEELS IS AT THE SUPPORT-

DRAG FORCE= 5 PERCENT OF 50.1

= 2.5 KN.

TRANSVERSE FORCE ON EACH WHEEL= 10 PERCENT OF (290/4).

= 7.25 KN.

GENERALLY I SECTION IS CHOSEN FOR THE DESIGN OF GANTRY GIRDER.

ECONOMIC DEPTH OF I SECTION= L/12 = 583.3 MM.

WIDTH OF FLANGE= L/35= 200MM.

Zp req. = 1.40*Mu/fy.

= 0.507 mm4.

CHECK FOR DEFLECTION-

MAXIMUM DEFLECTION= L/750.

= 9.3MM.

THE MAXIMUM DEFLECTION OF THE GANTRY GIRDER CANNOT EXCEED 9.3MM.

WE CAN LOOK UP FOR THE VALUES OF I SECTION IN THE STEEL TABLE AND THEN DETERMINE THE SHEER FORCE ACTING ON THE GIRDER.

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