Project 2

 Using MATLAB/simulink and  the drive cycle from the attached excel sheet, find-

1. The max heat generation of the battery 

2. The SOC of the battery at 2 *104second of the battery operation

We know that the total heat generation,

Total Heat generated By battery = Joule Heat +Entopic Heat

So,

Joule Heat = Power * Time

             H = I²Rt

Where,

H - Joule Heat

I - Current

R - Resistance

t - Time

Entropic Heat,

dS = δQ/δT

Where,

δQ - Heat Transfer

δT - Absolute Temperature

Entropy Heat = 2 * Joules Heat

There fore, 

 Total heat generated = I²Rt + 2* I²Rt = 3I²Rt

From the given table of data,

Maximum  current = -0.896 A

Resistance = 0.5 mΩ

time = 120sec = 0.03333333 hrs

Total heat generated by the battery Pack = 3 * (-0.896)² * (0.5) * 0.03333 = 48.166mJ

Maximum Heat generated by battery pack =48.16 mJ

Simulink model :-

For creating the Simulink model we are using the following blocks:-

1. From Spreadsheet :- To Give the Signal to As input to the Other blocks.
2. Controlled current source:-Converts the Simulink input signal into an equivalent current source. The generated current is driven by the input signal of the block.
3. Battery:- Implements a generic battery model for most popular battery types. Temperature and aging (due to cycling) effects can be specified for Lithium-Ion battery type.
4. Bus selector:-This block accepts a bus as input which can be created from a Bus Creator, Bus Selector or a block that defines its output using a bus object.
5. Series RLC branch:-Implements a series branch of RLC elements. Use the 'Branch type' parameter to add or remove elements from the branch.
6. Powergui:-Set simulation type, simulation parameters, and preferences.

     g.Scope:-To plot the output signals in graphical view

The resulting scope view is given below,

>> From the Above graph we consiste two parameters graphical view

Top Plo,

>> From This grapph we can says the the given drive cycle is consisites a -ve cureent in always 

>>And this value is moslty from -1.112 Amps to -0.868 Amos 

>>maximum Current is 0.868 amps 

>>This means this car cgetting the regenrative mode.

Bottom plot (SOC %):-

>>From the Grapgh we can conclude that The SOC% is always 100 % 

>>because the vehicle in regerative breaking mode 

>>In this Mode The Battery gets Charged always

>>due to this reason The Soc % is Always 100 %