Project 2
Aim:- Using MATLAB/simulink and the drive cycle from the attached excel sheet, find-
- The max heat generation of the battery
- The SOC of the battery at 2 *104second of the battery operation
Consider the battery resistance is 0.5 mOhm, delta time is 0.1 and entropic factor is 2
Answer:-
- The max heat generation of the battery :-
Answer:-
-> The maximum current in the drive cycle is -0.896 at 2 minutes(120 seconds)
--> maximum heat generated =I^2Rt=(-0.896^2)*2*120=192.676 milli Joule
-->The total heat generated =Joule heat+Entropic heat
=192.676 milli+2(192.676 milli)
=74.248 milli joules.
Averege heat is calculated by taking average value of current and time
--> average of time =1929/26=74.19sec
-->Average value of current =-24.7184/26=-0.9507
--> Therefore joule heat generated=I^2Rt=(-0.9507^2)*2*74.19=134.11milli Joule
--> Total heat generated=Joule heat+Entropy heat=134.11 milli+2(134.11 )=0.402 milli Joule
2) The SOC of the battery at 2 *104second of the battery operation.
Answer:-





