Challenge

Project-1: Powertrain for aircraft in runways

Question 1:

Aim: To explain the Total weights of Different Aircrafts

Total weights of Different Types of Aircrafts

Thw toatal weight or Maximum Gross Takeoff Weight includes mainly three factors

  • Passengers
  • Fuel
  • Cargo

the aircraft weight itself called kerb Weight or Empty Weight it also considered for calculating Total Takeoff Weight

Lets see the Total weight of different aircrafts

Aircraft Empty Weight Max Fuel Weight Max Cargo Weight Max Gross Takeoff weight
Antanov AN-225 285000kg 300000kg 190000kg 640000kg
Airbus A380-800 277000kg 254000kg 84000kg 575000kg
Boeing 747-800 220100kg 194000kg 134000kg 447700kg
Airbus A340-500 168000kg 175000kg 54000kg 372000kg
Boeing 777-300ER 168000kg 145500kg 67100kg 352000kg
Boeing 787-10 135500kg 101500kg 57300kg 254000kg
Boeing 737-900 44700kg 24000kg 20200kg 85000kg
Airbus A320-100 42600kg 22100kg 20000kg 68000kg
Embraer190 28800kg 13000kg 13100kg 48000kg
Gulfstream G650 24500kg 21900kg 3000kg 45200kg
Bombardier CRJ900 21850kg 8900kg 2760kg 36500kg
Bombardier O400 17800kg 5300kg 8500kg 28000kg
Learjet 75 6300kg 2750kg 1300kg 9700kg
Cessna Citation CJ4 4700kg 2650kg 1000kg 7800kg
Beechcraft King Air B100 3200kg 1450kg 1900kg 5400kg
Diamond DA50 RG 1450kg 155kg 560kg 2000kg
Beechcraft Bonanza G36 1150kg 200kg 385kg 1660kg
Cessna 206H 990kg 235kg 520kg 1630kg
Sirrus SR22 1000kg 220kg 430kg 1630kg
Cessna 172R 770kg 170kg 255kg 1100kg

the above table indicates Total Weight for different Aircrafts we can observe that the minimum Total Gross Weight of the plane should be 1Tonn

The Cargo Weight means the weight of cargo passengers crew food etc.,

Question 2:

Aim: To Explain the Difference between the Ground speed and the Air speed

Groundspeed is the speed of the aircraft directly over the ground. It is a vector quantity. Higher the ground speed the faster you reach your destination. Airspeed is the speed of the aircraft relative to the speed of surrounding air in which the aircraft is flying.

Actually, there are many types of airspeed. They are namely

  • Indicated Airspeed,
  • Calibrated Airspeed,
  • True airspeed and,
  • equivalent airspeed.

True airspeed is the speed of the aircraft relative to the airmass in which it is flying. It is the airspeed of the aircraft used for exact navigation.

If the airspeed is positive, that is, moving in the direction of aircraft, the aircraft will have a higher groundspeed. This is known as Tailwind.

On the other hand, if it is moving opposite to the direction of aircraft, that is negative wind, it will decrease the aircraft's groundspeed. This is known as Headwind.

Thus,

Groundspeed= Airspeed + Windspeed.

For example, if an aircraft is moving at airspeed of 500 mph and there is a tailwind of 265 mph, then ground speed of the aircraft will be 765 mph.

Again, if it is 265 mph headwind, then groundspeed would be only 235 mph.

During takeoff, the ground speed of the aircraft is not important. It is the airspeed which is important. During takeoff, airspeed will be the speed of the air flowing over the wings to generate lift.

if an aircraft can takeoff at 200 mph airspeed and there is a headwind of 50 mph, then it will have to attain a groundspeed of 200–50= 150 mph, to get a airspeed of 200 mph. Thus plane can use a shorter length of runway to takeoff. If there it would be tailwind, the plane will have to use a longer length of runway to takeoff.

If the air is moving in the direction of aircraft, wind is considered to be Positive and if air moving against the aircraft, it is considered to be Negative.

Question 3:

Aim: To Why is it not recommended to use aircraft engine power to move it on the ground at Airport.

Aircraft towing equipment is typically used for the towing and pushback process to avoid some of the significant hazards posed by aircraft engines. When an aircraft's engine is activated, the thrust can create a high-speed wind that can easily cause damage to the airport terminal, surrounding ground vehicles, jetway, baggage and most importantly, ground personnel.

Suppressing the use of engines is especially important when towing a large aircraft, as their more powerful thrust capabilities can become exceedingly dangerous. Engine thrust can easily send any loose items airborne, turn the tiniest grains of dust into hazardous projectiles and create debris that can cause damage to multi-million dollar engines. Additionally, aircraft engines consume a great deal of fuel and generate extreme noise that can be harmful to ground personnel. Using a pushback tug for aircraft is simply a more economical and safer option than running the engines.

the power hazaerd areas are shown in below diagram

the power hazard area where aircraft thrust makes million dollor equipment damage

Typically, most aircraft cannot move in reverse without the help of aircraft towing equipment. Planes are not designed with a reverse option that pilots can use for backward movement, so pushback tugs for aircraft are the only option when moving aircraft to hanger or away from the terminal building. This is because aircraft are not outfitted with gears or transmission for propulsion – power for movement is derived solely from the engines through thrust. When aircraft tugs are used to tow planes, an airline can maximize safety and optimize efficiency with on-ground operations.

While most commercial airliners with jet engines have thrust-reversing capabilities, they can only be used as additional braking power during landing. In addition to the problems mentioned above associated with using aircraft engines, reverse thrust also has what is known as the lowest-speed-of-operation limit. If reverse thrust is used below the speed of 80kts, it's very likely the engines will become heavily damaged.

Question 4:

Aim: How an aircraft is pushed to runway when its ready to take off.

Pushback is when an aircraft is pushed backwards away from the airport gate by vehicles called tugs or tractors.
Closer to departure, an aircraft tug will park right in front of the nose wheel.
The tug might be directly attached to the plane's nose gear with a tow bar, or could be a "wheel-lift" tug. These tugs cradle the nose gear, then lift it up before moving the plane. That gives the tug driver control over the plane's direction during pushback.
New taxi technologies are appearing, like pilot-controlled tugs, and electric motors mounted to the plane's landing gear. Both promise to save fuel, and reduce airport noise.

Question 5:

Aim: Learn about take off power, tyre design, rolling resistance, tyre pressure, brake forces when landing.

Take of power required to keep the aircraft in the air without fail:

  • The take off power required mainly depends upon the kinetic energy of the vehicle and the height i.e, potential energy of the aircraft.

  • The total energy of an aircraft flying in the atmosphere can be calculated from the below energy equation:

E = ½ m v2 + mgh

here m = total mass of the aircraft

v = velocity with which air craft is moving.

g = acceleration due to gravity

h = height at which aircraft is moving

  • A Boeing 737-300 has a maximum takeoff weight of 5.65 × 104 kg, a cruise altitude of h = 10,195 m, and cruise speed of 221 m/sec. Inserting these numbers into the above equation, we obtain 7.03 GJ for the energy at cruise conditions. [3] However, the engines mounted onto the wings of the plane are required to provide additional energy per time, power, in order to keep the aircraft flying at a constant altitude and speed.
  • The extra power needed to overcome the drag acting on the airplane can be given by the following equation :

P = (dh/dt) m g

Here dh/dt = the decent speed required to keep the plane's speed constant if the engines fail.

m = mass of the aircraft

g = acceleration due to gravity

Tyre Design :

Aircraft tires can easily be taken for granted. Their simplistic appearance may lead some to a false feeling of complacency. Many technicians are not aware of the critical design factors that go into every aircraft tire in use today. Seemingly minor flaws can lead to disastrous results, and inadequate maintenance practices can cause shortened tire life and even cause unsafe operating conditions.
When one considers the forces that aircraft tires endure, it seems amazing that engineers were ever able to develop these special products. Some tires are subjected to speeds as fast as a race car while at the same time supporting more weight than the largest land moving machines. They go through cyclic exposure to varying temperatures and pressures. These factors make aircraft tire design a critical process and tire maintenance an ever important step in safe aircraft operation.

Designing aircraft tires is a very intense undertaking. Once an aircraft manufacturer goes to the tire manufacturer with the size and weight requirements, the tire manufacturer begins the process of designing a tire that meets the needs of the aircraft manufacturer as well as all regulatory requirements — including foreign regulations in many cases.
Engineers are challenged with designing tires with cool running, heat-resistant materials while simultaneously exceeding tire service requirements. Tire prototypes are put through rigorous tests that simulate cycles of landings, take-offs, and taxi operations. It is only after the tires pass all mandatory tests and meet the requirements of the aircraft manufacturer and airworthiness authorities that the tires are put into production.
Two types of tires are used in aircraft applications — bias-ply tires and radial tires. Although both types of tires share some similarities in design, there are differences that need to be noted.

Bias-ply tire construction :

Radial-ply tire construction :

ROLLING RESISTANCE IN AIRCRAFT :

Rolling resistance, sometimes called rolling friction or rolling drag, is the force resisting the motion when a body (such as a ball, tire, or wheel) rolls on a surface. It is mainly caused by non-elastic effects; that is, not all the energy needed for deformation (or movement) of the wheel, roadbed, etc., is recovered when the pressure is removed. Two forms of this are hysterises losses and permanent (plastic) deformation of the object or the surface (e.g. soil). Another cause of rolling resistance lies in the slippage between the wheel and the surface, which dissipates energy.

The rolling resistance force will be given by the equation as :

F = μ*mg

here :

μ = rolling resistance coefficient

m = total mass of aircraft

g = acceleration due to gravity

But when we consider the extreme condition the surace when considered with a snow we take many considerations into account :

When taking off from a runway covered with slush, standing water or snow, the required take-off ground-run distance will be longer than on a dry runway. This is the result of the fact thatslush, standing water and snow on the runway will generate a rolling resistance that increasesthe total resistance on the aircraft during the ground-run.

Snow is a porous, permeable aggregate of ice grains, which can be single crystals, or closegroupings of several crystals. Air and water vapor surround the crystals. Snow is a complicatedmaterial because of the variety of forms it can take and because it is thermodynamicallyunstable, which means that the physical properties of the snow can change with time (known assnow metamorphism). A large number of different types of snow are known. A possibleclassification of these types including typical densities, is given as follows:

•New snow (50-200 kg/m3)

•Powder snow (200-450 kg/m3)

•Compacted snow (450-700 kg/m3)

•Wet snow (300-700 kg/m3)

All these types of snow are compressible. This means that the volume changes when the snow isloaded. This volume change becomes evident as surface compaction. Density is probably themost useful single parameter of snow properties because e.g. structural characteristics showsome correlation with density. The compression strength of snow, and thus its bearing capacity,also appears to be strongly influenced by its density. Below a density of 400 kg/m3 the bearingcapacity of snow is usually very low resulting in large volume changes of the snow when it isloaded. At higher densities higher loads are required to compress the snow. Whenever snow issubjected to loads e.g. by moving the snow with a bulldozer or running a tire over it, the snowbecomes stronger than natural snow of the same density. This is a result of bond growthbetween the ice crystals. As already pointed out, snow is metamorphic. Environmentalinfluences like wind, temperature fluctuations, and rain can change the characteristics of snowwithin days and even within hours.

The total rolling resistance of an aircraft rolling along a snow-covered runway is given by:

Drolling = Dr+Dc+Dd

In which Dr is the rolling resistance on a dry hard surface. The equations presented in this paperfor Dc and Dd are for single tires. A complete aircraft has at least 3 tires, one on each mainlanding gear and one on the nose landing gear. To obtain the total aircraft rolling resistance dueto snow, the resistance Dc and Dd for each single tire have to be calculated and summed.

TYRE PRESSURE :

An aircraft tire or tyre is designed to withstand extremely heavy loads for short durations. The number of tires required for aircraft increases with the weight of the aircraft, as the weight of the airplane needs to be distributed more evenly. Aircraft tire tread patterns are designed to facilitate stability in high crosswood conditions, to channel water away to prevent hydroplaning, and for braking effect.

Aircraft tires also include fusible plugs (which are assembled on the inside of the wheels), designed to melt at a certain temperature. Tires often overheat if maximum braking is applied during an aborted takeoff or an emergency landing. The fuses provide a safer failure mode that prevents tire explosions by deflating in a controlled manner, thus minimizing damage to aircraft and objects in the surrounding environment.

The below image shows the comparision between the car and aircraft tyre pressure comparision :

CAR TYRE AIRCRAFT (1) AIR CRAFT (2)
Typical (737 NLG) (737 NLG) (F-16 Blk 40 MLG)
Size P205/75 R15 27x7.75 R15 27.75x8.75R14.5
Outside Diameter 27.2 inch 27 inch 27.75 inch
Selection Width 8.1 inch 7.75 inch 8.75 inch
Max Inflation 35 psi 200 psi 320psi
Max Load 1,598 lbs 9,650 lbs 21,500 lbs.
Speed Rating 106 mph 225 mph 259 mph
Operation Continuous Intermittent Intermittent
Temperature Equilibrium No Equilibrium No Equilibrium

By the above variation we can assume that what will be the pressure of aircrafts with respect to the normal 4 wheeler vehicles.

BRAKES FORCES WHILE LANDING :

Early aircraft had a single braking system with no backup or redundancy. This was seen as impractical by the operators and unacceptable by the regulating authorities so manufacturers were soon incorporating more robust braking systems into their designs. Some of the earlier solutions simply addressed the loss of the primary hydraulic pump and incorporated hand pumps or electrically driven hydraulic pumps to provide an alternate source of hydraulic pressure. These solutions did not address failures due to loss of fluid and were deemed inadequate. To overcome this, some manufacturers such as Convair incorporated a compressed air system into their designs for emergency braking. While it achieved the requirement of providing an independent means of activating the brakes, it was limited in that it did not allow for differential braking and in that the tank contained a finite amount of compressed air. Braking redundancy in most large passenger aircraft today is achieved by multiple, independent hydraulic systems backed up by accumulators. These systems allow for several layers of failure without resulting in total loss of braking capability.

Break System Enhancements

Anti-skid, auto-brake, brake temperature indicators and brake fans are all systems which enhance the performance of the aircraft brakes.

Anti skid Breaking System:

The anti-skid system, through various mechanisms, compares the speed of the aircraft with the rotational speed of each main wheel. If the speed of any wheel is too slow for the existing aircraft speed, the brake on that wheel (or wheels) is released momentarily to allow the wheel speed to increase and prevent the wheel from skidding. The system is fully automatic and is active from immediately after initial wheel spin up on landing (during which time brake activation might (or might not) be inhibited) down to a design limited minimum speed; usually about 15 knots. Anti-skid systems are designed to minimise aquaplanning and the potential tyre damage which can occur when a wheel is locked or rotating at a speed which does not correspond to the speed of the aircraft. Anti-skid removes the possibility of reverted rubber skids caused by locked wheels. An anti-skid system also greatly improves stopping distance on substandard surfaces such as gravel or grass and is particularly effective on surfaces contaminated with frozen contaminants such as ice or slush by ensuring maximum effective breaking.

Auto Brake System:

Auto-brake systems can be used on takeoff where they will provide maximum braking in the event of a rejected take-off and on landing where they will provide a scheduled rate of deceleration (dependent upon the auto-brake level selected) using only a single brake application. These features combine to optimize the brake usage with respect to the requirement and to minimize brake wear.

Question 6:

Aim: To calculate the force and power required to push / pull an aircraft by a towing vehicle With necessary assumptions.

the towing vehicles are used to pushback the aircrafts to the runways or to hangers

as the airport has a plain concrete surface the vehicle is acted by only rolling resistance force and air drag force

although the minimal number of forces the aircraft weighs a massive ammount of weight the towing vehicle needs to generate high amount of power

when coming to the acceleration the towing vehicle does not need tro accelerate as the aircraft may sturdle so we are not considering the acceleration force

Rolling rasistance force `F_(rr)`:

`F_(rr)=mu_(rr)xxmxxg`

where `mu_(rr)`is rolling resistance constant

m is Total Gross weight of the vehicle

g is the coefficient of gravity

Total gross weight = weight of the Towing vehicle + Take off weight of the aircraf

`F_(rr)=0.02xx(35000+164000)xx9.81`

Air drag Force `F_(ad)`

`F_(ad)=1/2rhoAC_dv^2`

`rho` = 1.225 kg/m^3

A( frontal area)= hieght of tghe aircraft*width of the aircraft

A=15.80*43.90=693.62 m^2

`C_d`air drag coeficient 0.0265

the towing vehicles does not need to rush as the nose gear of the aircraft may damage

so, assuming that the towing vehicle moves at the speed of 20kmph

V = (20*5/18)=5.56m/s

`F_(ad)=1/2xx1.225xx693.62xx0.0265xx(5.56)^2`

now the total forces acting on the towing vehicle

`F_T = F_(rr)+F_(ad)`

the total power required by the towing vehicle is

`P_T=F_Txxv`

now lets make a model in SIMULINK to calculate the above forces

we can observe the total forces acting on a towing vehicle

as well as

total power required to overcome these forces in the displays

Question 7:

Aim: Design an electric powertrain with type of motor, it’s power rating, and energy requirement to fulfill aircraft towing application in Simulink. Estimate the duty cycle range to control the aircraft speed from zero to highest. Make all required assumptions. Prepare a table of assumed parameters. Draw a block diagram of powertrain.

let us consider a towing vehicle as indicated as above

with

`F_T =39390N`

`P_T=219000W`

let us assume that the towing vehicle tows for 20 min which is equal to 0.35H

then the energy consuming is

`E_t=P_Txxt`

`=>E_t=219xx0.35

`=>E_t=76.65kwh`

consider radius of the wheel to be 0.813m

calculating the motor torque as`tau =(F_Txxr)/(Gxxeta_g`

considering the gear efficiency 95%

then`eta_g=0.95`

the common gear ratio to achieve such big loads is 27

then the `tau = (39390xx0.813)/(27xx0.95)`=1248.6Nm

the speed of the motor is calculated as `omega=P_T/tau`=219000/1248.6=175.39rad/sec

the motor required for the towing application is an stalled motor so that it has to exhibit high amount of torque throught the operation

basically this motor is designed for low speed and high torque application

let us simulate the DC Drive with load torque as calculated above

DC Voltage Source 48v
controlled Pwm generator 48v,1000Hz
H-bridge 48v,440v
BLDC 440v, 1300N*m, 200RPM
Load Torque as calculated 1248.6 N*m

above mentioned are the considered values let us see the output results

Results:

By observing the above results the required torque is achieved by the considered motor

we can observe high current and voltage due to stalled condition the starting torque requires high currents

the torque is maintained same throught the simulation which is the major consideration for stalled motors used for towing application

Duty cycle of the Aircraft to reach zero to highest speed:

Consider the Airplane that can lift off at 200kmph

the airspeed and wind speed is considered randomly to calculate groundspeed

`"Groundspeed"="Airspeed"-"Windspeed"`

let us create a excel spread sheet to calculate and plot the aircraft liftoff or takeoff speed

we can observe that the lift off is taken at groundspeed 200kmph from the plot

comercial vehicles can go maximum speeds upto 550kmph

by observing the above plot we can say that

the duty cycle of the range of aircraft speed from zero to highest is calculated as

the range of zero to highest speed of the aircraft is achieved with the thrusters which are engines

but let us assume that both the engines are replaced by electric motors and fuel tank with battery pack

lets calculate the required motor parameters

`N=v/(0.1885xxD_m)`

N is speed of the motor in rpm

D_m is diameter of the propeller in meters

Torque of the Motor is calculated as

`tau_m= (F_Txxr)/(Gxxeta_g)`

where `tau_m`torque of the motor

`F_T`is Total forces acting on aircraft

`G`is gear ratio

`eta_g`efficiency of gears

Total required power of the Motor

`P_m=(tau_mxxN_m)/9.5488`

lets assume that the aircraft is travelling from one place to another place in one hour

then the energy required by the aircraft is

`E=P_mxxt`

t is time travelled

E is energy required by the motor which is come under battery capacity

lets assume auxilary loads and there are two motors employed on both sides so

it has to supply for both motors

`E=(P_m1+P_m2+P_a)xxt`

where E is energy required by the aircraft or required battery capacity

Pm1 is left wing motor power

pm2 is right wing motor power

pa is power required for auxilary loads

Now, the Duty cycle of the Power electronic converter for the range of aircraft speed from zero to highest is calculated as follows

`D= P_("out")/P_("in")`

`P_("in")`is battery power supplied

`P_("out")`is the output power delivered to both motors and other auxilary loads of the aircrafts

Thus the Duty cycle of the range of aircraft speed from zero to highest is calculated

Table for assumed parameters:

mass of the aircraft 164000
mass of the Towing vehicle 35000
Total Gross Weight 199000
Rolling resistace constant 0.02
gravitational coeficient 9.81
Rolling resistace Force Frr 39043.8
Air density ρ 1.225
Frontal area 693.62
Air drag Coefficient Cd 0.0265
velocity of the vehicle 5.56
Airdrag Force Fad 348.0351896
Total Forces acting on a Towing vehicle FT 39391.83519
Total Power required by the Towing vehicle to overcome the acting Forces on it PT in kW 219.0186037
Total time required to pushback aircraft t in hrs 0.35
Energy Required By the Towing Vehicle to pushback aircraft in kWh 76.65651128
gear ratio considered G 27
Gear efficiency ɳg 0.95
Radius of the Towing vehcle wheel in m 0.813
Torque Required by the Motor τm 1248.559922
Angular velocity of the motor Ѡm in rad/sec 175.4169742
Energy required by the Motor or Battery Capacity in kWh 76.65651128
Battery Power Required 219.0186037
Duty Cycle of the Power electronic converter of an Towing Vehicle in % 100

BlockDiagram of PowerTrain of an Towing Vehicle:

we can observe the block diagram of power train for Towing Vehicle

the power comes from the charging station taken to the power electronic converter and fed to the battery

after charging the battery feds to the power electriniv converter which acts as an dc-dc converter and feds to motor

the motor with gear ratio powers the wheel with required torque

The Parameters required by an Towing vehicle to pushback an aircraft is calculated in excell sheet also and attached

Towing_vehicle_parameters_calculater

Conclusion:

  • The total weight of various types of aircrafts are listed.
  • The difference between ground speed and air speed explained.
  • Why is it not recommended to use aircraft engine power to move it on the ground at Airport is explained.
  • How an aircraft is pushed to runway when its ready to take off is explained
  • Take off power, tyre design, rolling resistance, tyre pressure, brake forces when landing of an Aircraft is explained.
  • The force and power required to push / pull an aircraft by a towing vehicle is derived.
  • The model for the calculated force and power using Simulink is developed.
  • An electric powertrain with type of motor, it’s power rating, and energy requirement to fulfill aircraft towing application in Simulink.
  • The duty cycle range to control the aircraft speed from zero to highest is estimated using excel sheet.
  • A table of assumed parameters is prepared.
  • A block diagram of powertrain Drawn.
Your portfolio, next

Ship work like this
in your own course.

Talk to a career counsellor

Free 20-minute call. We'll map the right course to where you want to work.

By submitting you agree to our Terms and Privacy Policy.