Project 1_Analyze and design a steel building to 10T CRANE as per IS standard code using TEKLA STRUCTURAL DESIGNER.

Answer of the question

AIM: Aim is to Analyze and design a steel building to 10T CRANE as per IS standard code in TEKLA STRUCTURAL DESIGNER. Refer the attached plan and elevation. Provide bracings and moment connection for lateral stability.

Consider dead, live, equipment and wind loading. Consider the brick wall loading for 150mm thick and 1.5 KN per sq m for wall and roof cladding.

Assume wind loading basic speed as 39m/s

Report of each member to be generated and extract drawings of structural plans from the software

INTRODUCTION : We used Tekla software for design and analysis. first we create the modal then apply the loads like live load dead load wind load seismic load over it and to study the responce of the structure. in the last we checked all the members results.

PROCEDURE

Step-1

• Study the drawings of strucutural layout.
• Lounch TSD.
• Save the new files as Pramod-1
• Check Setting and unitss Design codes Strucutre defoults etc.

Step-2

Construction Levels:

• Go to Modal - Construcution lelvels Strucuty the section details drawings to enter heights of GF,FF, RBL and RL
• To find the height of roof level assume roof angle as 17 deg.
• tan 17 = Height of roof level assume angle as 17 deg.
• Tan17 = Height of the roof /(Span/2) = H/(38000/2).
• H = tan17*19000= 5808= 5.808m

Step-3

• Now We are creating Grid lines
• Draw 16 vertical grids of 6m spacing Number it accordingly.
• Create the Horzontal and vertical to appropriate spacing.

Step-4

• Now we are creating pedestals. go to manage property sets- New Members- Concrete column.
• Create a pedestal of size 500*1000mm, major alignment - centre and releases fixed top and bottom.

Step-5

• Now Start placing the column
• Select the levels. as Base level to GF Level.

Modelling the Steel Column:

• Check the section layout drawing. Notice that the interior columns are of different heights So create 2 additional levels next to RB level. As we have set the roof level at 5.81m from RBL , subtract 1m for the roof level = 4.81m
• Create the steel column of ISMB 550
• and go to ground floor level
• Click on Steel – Column
• From the properties, choose C1(MB 550) and then the levels from GF level till the roof beam level for outer grids and C2(MB 600), levels from GF to Int L1 for grid B and levels from GF to Int L2 for columns on construction lin.

Step-6

• Now Create the B1 of MB 550,
• this beam for all 6 m span.
• also create another B2 beam MB 600 for beams between A and B Grids.

Step-7

Similarly proceed to the level

Modal B3 MB 350 for secondary beams connecting primary beams.

Step-8

• Now we will create rafeters
• first model the grid line at the mid span for the apex of rafter.
• next oen 3d and do copies for all command.

Step-9

Next Model the Bracings:

Step-10

Crreate SLAB:

• first verify the slab type one way or two way next assign accordingly.
• create slab S1 for One way slab and S2 for two way slab.

Step-11

Wall And Roof Panel:

Select frame A and G frame 1 and 16 model the wall panels.

Step-12

Bracket for Crane Support:

• check the section drawing, brackets are placed at 950 + 2050 from the FF level
• So we need to create a construction level at 3000mm from the FF level.

Step-13

• Now add the Cantileverl beam of MB 550 is to be modelled as the bracket supporting the cranee.
• next model this beam from grid B to the construction line

Step-14

Application of loads:

A) Dead Load

• Under the load cases, add wind and seismic loads.
• Under combination select generate to genetate the losad combinaation.
• Lets now proceed with the Dead load calculations by opening a MS Excel file and calculating Floor finishes load, Brickwall load( from GF to FF and FF to RBL) and roof loading

Step-15

• now apply the floor finishes load of 1.2 kN/m2 to the other floors also
• Validate the model for any errors
• Check the applied dead loads in 3D view

Step-16

Live Load ::

Crane Load:

Now lets generate a calculation for 10T crane loading based on following inputs

• Crane capacity = 10T = 10000kg = 100 kN
• Centre to Centre of wheel = 14m
• Weight of crab = 40 KN
• Total Number of wheels = 4
• Wheel base = 2m
• No of wheels on each side = 2
• Weight of the crane = 60 kN

Span of the gantry girder(max c/c distance between 2 columns) = 6 m

Step-17

MAX Wheel load:

Concentrated load due to weight of the crab / trolley and crane capacity(weight lifted by the hook)

Lets find the loads one by one.

UDL due to Self weight of the crane = S.W of the crane / c/c between the wheels

• =60/14 = 4.3 kN/m

Concentrated load due to weight of the crab / trolley and crane capacity = 40 + 100 = 140 kN

• Minimum hook approach = 1m
• Applying the equilibrium equations,
• Ra + Rb = 140 + (4.3* 14) = 200 kN∑M b = 0
• (14 * Ra) – ( 140 * 13) – ( 4.3 * 14 * 7) = 0
• Ra = 160 kN
• Rb = 200 – 160 = 40 kN
• Max reaction is taken always
• Ra = 160 kN = Static wheel load
• This load is shared by 2 wheels , Load transferred by 1 wheel = 160/2 = 80 kN
• Adding 25% for Impact = 100 kN
• Factored load = 100 * 1.5 = 150 kN

Result : I completed the answer of the question.