Challenge

Project 1_Analyze and design a steel building to 10T CRANE as per IS standard code using TEKLA STRUCTURAL DESIGNER.

Aim - To analyze and design a steel building to 10T crane as per IS standard codeusing Tekla structural Designer

Procedure -

  • Initially open the Tekla Structural Designer Software
  • Click on New option to create new model
  • Using Grid lines and Quick parallel grid line option horizontal grids and vertical grids was drawn.

  • In the model toolbar select construction level dialogue box
  • Construction level dialogue box appears and name each level as Base,Ground floor,First floor,Roof floor and Roof top and also assigned the height to each level.

  • Now to add pedestal columns in gthe Home menu click on Manage Property setd option and the manage property sets dialogue box appear
  • Click on New followed by members ans select concrete column
  • Rename it as PD1 and also apply properties

  • Now using column option in the ribbon tab under model menu,Column was placed at locations as required.Column was placed at base floor upto ground floor

  • Similarly,creats steel column under manage property sets option
  • Rename it as C1 and also apply properties

  • Now using column option in the ribbon tab under the model menu column was placed at locations as required.Column wa placed at Ground floor upto Roof floor

  • Similarly,create beam under manage property setd option

  • Now using beam option in the ribbon tab under the model menu beams was placed at locations as required
  • Beams at Ground level

  • Beam at first floor

  • Beam at Roof floor

  • Rafter beam was designed using manage property set option,Click on New followed by members and select steel beam
  • Rename it as Rafter and apply properties

  • Now Rafter beam was applied using the beam option in the ribbon tab under the model menu and beams was placed at locations as required
  • Both the ends of Rafter was set fully fixed

  • Steel bracing was designed next for that click on manage property sets option and manage property sets dialogue box appear.Click on new followed by members and select Steel Brace .
  • Reanme it as Bracing and apply properties
  • Also select section size of ISA 75X75X8 for designing

  • Now steel brace were applied using the brace option in the ribbon tab under the model menu and braces was placed at locations by selecting opposite corners points.then select X brace option and drawn

  • Slab properties was designed using manage property sets option,in that select new followed by members and select slabs followed by general slab item and apply properties
  • Now using the slab on beam option in model menu the slabs was applied on all floors
  • Slab on Ground floor

  • Slab on First floor

  • Slab on Roof floor

  • Wall panel and Roof panel was applied using wall panel option and roof panel option from model menu
  • 3D view of wall panel and Roof pane

Load Calculations -

Initially based on IS 875 part 1, all the dead load in the steel structures were calculated as follows

1) Unit weight of concrete = 24

2) Finish load = 0.05*24 = 1.2

3) Brick wall loading = 0.15*20*5 = 15 kn/m

4) Brick wall loading = 0.15*20*7 = 21 kn/m

5) Brick wall loading (roof floor to roof top ) = 0.15*20*4.8 =14.4 kn/m

6) Roof loading on purlins = 1.5 kn/m

7) Ceiling loading = 0.3 kn/m

  • On the load tab click on load cases option at the top left corner to open the loading dialogue box

  • In order to add new loading like imposed,wind,seismic and crane load .click on add option in loading dialogue box and add them and select type from the drop down list

  • For applying dead load first select dead load option from the drop down list at the bottom left side
  • Open 2d view ground floor of the level within which you want to apply load
  • In the loading list,select an appropriate load case
  • In the Load tab,click on Area load
  • In the property windows,adjust the load details according to need and click on that panel which you want to apply
  • Load was applied in all floors and roofs

  • For Roof load was applied as Full UDL

Wind Load Calculations -

Crane Load Calculations -

Maximum concentrated load on crane = 100+35 =135 kn

Self-weight of crane will act as uniformly distributed load of intensity = 160/20 = 8 KN/M

Taking moment about B-

Ra x 20-(135) x (20 x 10) =0

20Ra = 297000

Ra = 208.25 KN

Taking moment about A -

Rb x 20-(135)x(1-8)(20x10) = 0

20Rb = 189000

Rb = 86.75 KN

Ra+Rb = 100KN

The reaction from crane girder is distributed equally on two wheels at the end of the crane girder

Maximum wheel load on each of the crane wheel = 208.25/2 = 104.125 KN

Maximum Bending Moment -

Assume self weight the the gantry girder as 1.5 KN/m

Total dead load = (self weight of rail+self weight of gantry girder) 0.3+1.5 = 1.8 KN/m

Taking Moment about D -

Rc x6 -104.125x(20.25+3)-104.125x2.25 =0

6Rc = 2655.187

Rc = 24655.187/6

Rc = 130.15 KN

Taking Moment about C -

Rd x6-104.125 x(0.75+3)-104.125 x0.75 =0

Rd x6 = 468.56

Rd = 468.56/6

Rd = 78.09 KN

Bending moment under wheel due to live load = Rd x2 = 78.09 x 2 = 156.18 KNm

Bending moment due to impact = 0.10 x 156.18 ( 10% increase due to MOT) = 15.618 KNm

Total bending moment due to live load and impact load = 156.18 + 15.618 = 171.798 KNm

Bending moment due to dead load = Wl *l/2 =1.8 x 6 x 6/2 = 8.1 KNm

Maximum bending moment = 171.798 + 8.1 = 179.89 KNm

Maximum Shear Force -

For maximum shear force

Rc x 6-104.125 x6-104.125 x3 = 0

Rc = 937.125/6

Rc = 156.18 KN

The maximum shear force due to wheel load = 156.18 KN

Lateral forces -

Lateral forces traverse to rails = 5% of the weight of crab and weight lifted

= 0.05 (135) = 6.75 KN

Lateral forces on each side of wheel F1 = 6.75/2 = 3.375 KN

Maximum horizontal reaction due to lateral force by proportion at C = Lateral force x reaction at c due to vertical load / Maximum wheel load due to vertical load

= 3.375 x (130.15/104.125) = 4.21 KN

At D -

=3.375 x (78.09/104.125) = 2.53 KN

4.21+2.54 = 6.74 kn

Bending moment due to lateral load by proportion = 3.375 x (15.18 / 104.125) = 5.06 KNm

  • Now ceate new wind load with both +Cpi and -Cpi values using wind wizard option under load tab
  • Also add seismic load at last
  • Analyze the structrure and do necessary changes to correct the errors

  • Add basic wind pressure data

  • Select terrain category as open terrain scattered obstructions

  • Select topography for wind pressure

  • Check the result value

  • Generate load combinations using generate option

Result -

1st order non linear analysis -

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