Project 1

1. Design a battery pack for a car roughly 150 Kw with 120 V. Use 3500 mAh 3.6V nominal NMC chemistry cell.

a. Design the battery pack configuration.

b. Draw the BMS topology for this battery pack.

Cell Specifications:

Nominal Voltage= 3.6V

Max. Voltage= 4.2V

Nominal cell capacity= 3500mAh = 3.5 Ah

Rated power=150kw

Rated voltage=120v

irst finding the motor current= (rated power *1000)/rated voltage

= (150*1000)/120

=1250A

a) Design the battery pack configuration.

for desiginig the Battery pack Configaration ,Firstly we have to fing the two parameters as followes :-

i) Number of cells connected in Series

ii) Number of cells connected in Parallel.

i) Number of cells connected in Series:-

For this solution let us Take the data from given:-.

Nominal volatge =3.6 v

Cell having capacity of cell(Ah)= 3500 mAh= 3.5 A

   Cells connected in series = Required voltage (V) /  Nominal cell Voltage(Ah)

From the data

Required Voltage :- 120 v

Nominal Voltage = 3.6 v

Therefore,

*** Cells connected in series = Required voltage (V) / Nominal cell Voltage(Ah) ***

The cells connected in series = 120 / 3.6

=33.3 cells

This Digits vallues are taken as rounding of caluctions as followes :-

When compare with rated voltage, the battery voltage is greater in case 2 then case 1.

i) Number of cells connected in Parallel:-

Formula for number of cells connectd in parallel:-

Formula:-


Number of cells connected in Parallel = Required Contuinous Current(I) / Cell Nominal Voltage(V)

Given data:-

Required Power = 150 KW

Required Voltage = 120 V.

NMC Battery detalis :-

Batatry capacity = 3500 mAh= 3.5 Ah

Battery Nominal Voltage =3.6V

We know that ,

          Power(P) = Current(I) * Voltage(V)

             from above formula


     **** Current(I) = power(P) / Voltage(V) ****

hence, From formula,

Current(I) = power(P) / Voltage(V)

= (150 *1000) / 120

Current(I) = 1250 Amps

NMC Battery detalis :-

Batatry capacity = 3500 mAh= 3.5 Ah

Battery Nominal Voltage =3.6V

Therefore,

Number of cells Connected in paralle :-

Formula:-



  Number of cells Connected in paralle = Required Current (I) / Cell Nominal Voltage(V)

from the data ,

Current(I) = 1250 Amps

Cell nominal Voltage = 3.6 V

then ,

Number of cells Connected in paralle = Required Current (I) / Cell Nominal Voltage(V)

=1250 / 3.6

=358 P

There fore

           

                  Number of cells Connected in paralle =358 P--------------(2)

From values (1) and (2)

            Number Of Cells Connected IN Series = 34S

            Number of cells Connected in paralle =358 P

So,

No.of cell in series= 34 S

no of cells in parallel=358p

b. Draw the BMS topology for this battery pack.

Basically BMS topology is classified into following foure(4) types:-

1)Centralised Topology;-

This Topology is used for only pack of 18 cells or less than 18 cells in a series only.

2)Master and Slave topology:-

This Topology is used for pack of 18 cells or grater than 18 cells in a series .

High Energy storage purpose

3)Modular Topology :-

This Topology is used for pack of 18 cells or grater than 18 cells in a series .

Large Energy storage purpose

4)Distributed Topology:-

This Topology is used for pack of 18 cells or grater than 18 cells in a series .

Very large Large Energy storage purpose

2.Build a 3S2P battery pack configuration with generic battery block using Matlab/Simulink.

Total number of cells in battery pack = no.of cells in series * no.of cells in parallel

= 3*2

=6 cel

result

Designed a battery pack for a car roughly 150 Kw with 120 V. Use 3500 mAh 3.6V nominal NMC chemistry cell.

designed a 3S2P battery pack configuration with generic battery block using Matlab/Simulink