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1. Design a battery pack for a car roughly 150 Kw with 120 V. Use 3500 mAh 3.6V nominal NMC chemistry cell. a. Design the battery pack configuration. Answer : Given data : Power(P)=150 Kw Voltage(V)=120 V Nominal Current(I)=3.5A Nominal Voltage(V)=3.6 V To find the Number of cell in series …
Somaraju Vijay Kumar
updated on 28 Feb 2023
1. Design a battery pack for a car roughly 150 Kw with 120 V. Use 3500 mAh 3.6V nominal NMC chemistry cell.
a. Design the battery pack configuration.
Answer :
Given data :
Power(P)=150 Kw
Voltage(V)=120 V
Nominal Current(I)=3.5A
Nominal Voltage(V)=3.6 V
To find the Number of cell in series = Rated Voltage / Nominal Voltage
Number of cell in Series = 120 / 3.6
Number of cell in Series = 33.33 =34
Number of cell in Parallel = Continous Current / Nominal Current
To find the Continous Current = ?
P= VI
I=P/V
I=150/120 = 1.25 A
Number of cell in Parallel = Continous Current / Nominal Current
Number of cell in Parallel = 1.25/3.5
Number of cell in Parallel = 0.35=1
b. Draw the BMS topology for this battery pack.
Master Topology : Battery pack which more 18 number cell in series were used in mater slave topology.
Working: when serieslly convert energy storage battery cent to the AFE(slave-1) first connected ES cell data sent to the slave-2 totally connected first and second slaves data trafer to MCU
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2. Build a 3S2P battery pack configuration with generic battery block using Matlab/Simulink.
Answer :
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