Project 1
1.Design a battery pack for a car roughly 150 Kw with 120 V. Use 3500 mAh 3.6V nominal NMC chemistry cell.
a. Design the battery pack configuration.
b. Draw the BMS topology for this battery pack.
2. Build a 3S2P battery pack configuration with generic battery block using Matlab/Simulink.
Solution :-
Given data:-
Required Power = 150 KW
Required Voltage = 120 V.
Battery detalis :-
Batatry capacity = 3500 mAh= 3.5 Ah
Battery Nominal Voltage =3.6V
- a) Design the battery pack configuration.
For designing the Battery pack Configuration ,Firstly we have to find the two parameters as follows :-
- i) Number of cells connected in Series
- ii) Number of cells connected in Parallel.
- i) Number of cells connected in Series:-
For this solution let us Take the data from given:-.
Nominal voltage =3.6 v
Cell having capacity of cell (Ah)= 3500 mAh= 3.5 A
Formula:-
Cells connected in series = Required voltage (V) / Nominal cell Voltage (Ah)
From the data
Required Voltage :- 120 v
Nominal Voltage = 3.6 v
Therefore,
The cells connected in series = 120 / 3.6
=33.3 cells
This Digits values are taken as rounding of calculation
Rounding of calculation:-
When compare with rated voltage, the battery voltage is greater in case 2 then case 1.
So,
No of cell in series= 34 S
Number Of Cells Connected IN Series = 34S -------------(1)
- ii) Number of cells connected in Parallel:-
Formula for number of cells connectd in parallel:-
Formula:-
Number of cells connected in Parallel = Required Continuous Current(I) / Cell Nominal Voltage(V)
Given data:-
Required Power = 150 KW
Required Voltage = 120 V.
Batatry capacity = 3500 mAh= 3.5 Ah
Battery Nominal Voltage =3.6V
We know that ,
Power(P) = Current(I) * Voltage(V)
hence, From formula,
Current(I) = power(P) / Voltage(V)
= (150 *1000) / 120
Current(I) = 1250 Amps
Therefore,
Number of cells Connected in parallel:-
Formula:-
then,
Number of cells Connected in parallel = Required Current (I) / Cell Nominal Voltage (V)
=1250 / 3.6
=358 P
There fore
Number of cells Connected in paralle =358 P--------------(2)
From values (1) and (2)
Number Of Cells Connected IN Series = 34S
Number of cells Connected in paralle =358 P
We can conclude that
The Battery pack Configaration = 34S358P
Battery pack Configaration image :-
Fig--> Battery Pack Configaration (34S358P)
- Draw the BMS topology for this battery pack:-
BMS Topology:-
Fig :-BMS TOPOLOGY BLCOK DIAGRAM
Basically BMS topology is classified into following foure(4) types:-
1)Centralised Topology;-
This Topology is used for only pack of 18 cells or less than 18 cells in a series only.
2)Master and Slave topology:-
This Topology is used for pack of 18 cells or greater than 18 cells in a series .
High Energy storage purpose
3)Modular Topology :-
This Topology is used for pack of 18 cells or greater than 18 cells in a series .
Large Energy storage purpose
4)Distributed Topology:-
This Topology is used for pack of 18 cells or grater than 18 cells in a series .
Very large Large Energy storage purpose
Solution:-
From the Architecture of BMS we can said that the "AFU" Allowes ony 18 cells connected in series per one unit of modulae.
Hence ,
we required series cells is 34 cells
There fore we are dividing these 34 celss as 2 slave sets with 1 number of MCU master unit as followes
Slave 1= 17 cells
Slave 2= 17 cells
Based on this cells connected in series and Architecture of BMS we Choose the Master and Slave topology of BMS for this Ev battery pack Topology design.
BMS Topology MODEL :-
Master and Slave Topology:-
Above Model is For BMS Topology of 34s358P battery pack Configuration model
This Topology consistes a 2 numbers of slave of AFU units with each AFU units slave Consists a 17 numbers Of Cells connectd in series.
Conclusion :-
We can conclude from above calculations
The battery Pack configaration is 34S358P
Battery BMS Topology is "Master and Slave” Topology is designed and explained they regarding BMS topology.
2)Build a 3S2P battery pack configuration with generic battery block using Matlab/Simulink.
Aim
The main aim is design a given battery pack configuration by using the Matlab /Simulink Tool.
Given data :-
Battery pack configuration = 3S2P
Simulink model :-
For creating the Simulink model battery pack configuration we are used following blocks:-
Battery :-
scope:-
Procedure :-
Batteries in 3S2P configuration in Matlab/Simulink. That is 3 cells should be connected in series and 2 cells should be connected in parallel.
Total number of cells in battery pack = No. of cells in series * No. of cells in parallel
= 3 * 2 = 6 cells
step 1
Arrangement of 6 cells:-
The figure 1 shows the arrangement of 6 cells.
We have to place total number of cells in battery pack (6 cells)
Figure 1: Arrangement of 6 cells
Parallel connection:-
The figure 2 shows the batteries connected in parallel.
For parallel connection, batteries are connected from terminals to same terminals of other batteries that is positive terminal (+) of one battery is connected with positive (+) terminal ofother battery and negative terminal (-) of one battery with negative terminal (-) of other battery
Figure 2 : Battery connected in parallel connection
Step 2
Series and parallel connection:-
The figure 3 shows the battery connected in series and parallel combination. Batteries are connected from terminal to
terminal in a way that the positive (+) terminal of one battery is connected with the negative (-) terminal of the other
battery and negative terminal (-) of one battery is connected with the positive terminal (+) of the other battery.
Figure 3 : Battery connected in series and parallel combination
Model Explanation:-
The voltage measurement block is connected across the battery pack to measure the battery pack voltage. The scope output used for the battery pack consists of SOC (State of Charge), Current and voltage. The controlled current signal is given as the load to the battery pack. The constant blockis determined with battery capacity and it is given to the controlled current block.
The parameter given inside the battery is given below:-
- Nominal voltage of a cell 7.2V
- Rated capacity of a cell 5.4Ah
- Maximum voltage of a cell 8.3V
Therefore ,
Nominal voltage of the battery pack = no. of cell in series * nominal voltage of a cell
= 3 * 7.2v
= 21.6 V
Rated capacity of the battery pack = no of cell in parallel* rated capacity of a cell
= 2 * 5.4Ah
= 10.8Ah
The model is for an 21.6V 7 with 10.8Ah battery capacity
Overall voltage of the battery pack = maximum voltage of the battery * no. of cells in series
= 8.3V * 3
= 25 v
Overall voltage = 25 V
Total Battery pack model:-
Output Scope results :-
Voltage scope :-
Overall voltage of the battery pack = maximum voltage of the battery * no. of cells in series
= 8.3V * 3 = 25 V
>>From the Above Plot is we can observe that the the total battery pack voltage is reduced bt 10% of the initial value.
Battery pack details:-
From the Above graph we can observe that the
Top Plot is (Voltage):-
The voltage is around 8.3V. The increasing and decreasing voltage is with respect to the regenerative braking
Middle Plot (Current):-
The current signal is determined by the load and the decrease in current is due to regenerative braking.
Bottom Plot(SOC%):-
The SOC (state of charge) is started to reduce from 100% to 99 % corresponding to the load given
Conclusion :-
The battery pack configuration(3S2P) with generic battery block using Matlab/Simulink is created.
note : i already done this project due to website issue it gone thats why i re do the project