Problem statement:

Perform a static analysis on two models of plate with holes. You will have to create the model in Solidworks and perform the analysis.

The dimensions for the first case is as follows:

CASE 1

Length=300mm
Height=120mm
Thickness=30mm
Circular Hole at the center:
Diameter=60mm

The dimensions for the second case is as follows:

CASE 2

Length=300mm
Height=120mm
Thickness=30mm
Circular Hole at the center:
Diameter=60mm

Two holes of 30 mm diameter which are placed 90mm away from the central hole on both sides.

Apply a fixed relation to one of the short side of the plate and apply a force of 1000N on the other such that the plate is stretched.

Run the analysis and compare the results for stress, strain and displacement

Describe your findings in a detailed report.

Aim:

• To design the 3d models using solidworks.
• To run the simulation on the 3d models.
• To dicuss the obtain results.

Introduction:

In this project the effect of holes in stress, strain and displacment when the plate is stretched will be analyszed. we have two plates , one plate is having a hoel at the centre and another plate having three holes. A load of 1000N will applied .

Hence one side of the plate is fixed and another side the load is applied then the plate tends to be streched. Such that there will be change its length may happend and its variation may depends upon the property of the material. Here we going to observe how these values differs due to the presence of holes.

As expecting there will be major stress and strain acting with respect to the bigger hole which is placed at centre at both the cases.

Case(i):

Dimensions:

Length=300mm
Height=120mm
Thickness=30mm
Circular Hole at the center:
Diameter=60mm

3d model:

Model Information Model name: 1_hole Current Configuration: Default Solid Bodies Document Name and Reference Treated As Volumetric Properties Document Path/Date Modified Boss-Extrude1 Solid Body Mass:7.66286 kg Volume:0.000995177 m^3 Density:7700 kg/m^3 Weight:75.0961 N

Study Properties Study name Static 1 Analysis type Static Mesh type Solid Mesh Thermal Effect: On Thermal option Include temperature loads Zero strain temperature 298 Kelvin Include fluid pressure effects from SOLIDWORKS Flow Simulation Off Solver type FFEPlus Inplane Effect: Off Soft Spring: Off Inertial Relief: Off Incompatible bonding options Automatic Large displacement Off Compute free body forces On Friction Off Use Adaptive Method: Off Result folder SOLIDWORKS document

Units Unit system: SI (MKS) Length/Displacement mm Temperature Kelvin Angular velocity Rad/sec Pressure/Stress N/m^2

Material Properties Model Reference Properties Components Name: Alloy Steel Model type: Linear Elastic Isotropic Default failure criterion: Max von Mises Stress Yield strength: 6.20422e+08 N/m^2 Tensile strength: 7.23826e+08 N/m^2 Elastic modulus: 2.1e+11 N/m^2 Poisson's ratio: 0.28 Mass density: 7700 kg/m^3 Shear modulus: 7.9e+10 N/m^2 Thermal expansion coefficient: 1.3e-05 /Kelvin SolidBody 1(Boss-Extrude1)(1_hole) Curve Data:N/A

Loads and Fixtures Fixture name Fixture Image Fixture Details Fixed-1 Entities: 1 face(s) Type: Fixed Geometry Resultant Forces Components X Y Z Resultant Reaction force(N) -1000 0.00929125 -0.0053494 1000 Reaction Moment(N.m) 0 0 0 0 Load name Load Image Load Details Force-1 Entities: 1 face(s) Type: Apply normal force Value: -1000 N

Mesh information Mesh type Solid Mesh Mesher Used: Standard mesh Automatic Transition: Off Include Mesh Auto Loops: Off Jacobian points 4 Points Element Size 6.11655 mm Tolerance 0.305827 mm Mesh Quality Plot High Mesh information - Details Total Nodes 43557 Total Elements 28717 Maximum Aspect Ratio 3.8981 % of elements with Aspect Ratio < 3 99.9 % of elements with Aspect Ratio > 10 0 % of distorted elements(Jacobian) 0 Time to complete mesh(hh;mm;ss): 00:00:03 Computer name:

Resultant Forces Reaction forces Selection set Units Sum X Sum Y Sum Z Resultant Entire Model N -1000 0.00929125 -0.0053494 1000 Reaction Moments Selection set Units Sum X Sum Y Sum Z Resultant Entire Model N.m 0 0 0 0

Study Results Name Type Min Max Stress1 VON: von Mises Stress 36,743.121 N/m^2 Node: 25985 1,207,957.625N/m^2 Node: 26051 1_hole-Static 1-Stress-Stress1 Name Type Min Max Displacement1 URES: Resultant Displacement 0.000e+00 mm Node: 200 5.240e-04 mm Node: 141 1_hole-Static 1-Displacement-Displacement1 Name Type Min Max Strain1 ESTRN: Equivalent Strain 2.336e-07 Element: 6298 4.462e-06 Element: 7485 1_hole-Static 1-Strain-Strain1

Simulation plots : (stress, strain, displacecment plots)

Case(ii):

dimensions:

Length=300mm
Height=120mm
Thickness=30mm
Circular Hole at the center:
Diameter=60mm

Two holes of 30 mm diameter which are placed 90mm away from the central hole on both sides.

3d model:

Model Information Model name: 3_hole Current Configuration: Default Solid Bodies Document Name and Reference Treated As Volumetric Properties Document Path/Date Modified Boss-Extrude1 Solid Body Mass:7.33629 kg Volume:0.000952765 m^3 Density:7700 kg/m^3 Weight:71.8957 N

Study Properties Study name Static 2 Analysis type Static Mesh type Solid Mesh Thermal Effect: On Thermal option Include temperature loads Zero strain temperature 298 Kelvin Include fluid pressure effects from SOLIDWORKS Flow Simulation Off Solver type FFEPlus Inplane Effect: Off Soft Spring: Off Inertial Relief: Off Incompatible bonding options Automatic Large displacement Off Compute free body forces On Friction Off Use Adaptive Method: Off Result folder SOLIDWORKS document

Units Unit system: SI (MKS) Length/Displacement mm Temperature Kelvin Angular velocity Rad/sec Pressure/Stress N/m^2

Material Properties Model Reference Properties Components Name: Alloy Steel Model type: Linear Elastic Isotropic Default failure criterion: Max von Mises Stress Yield strength: 6.20422e+08 N/m^2 Tensile strength: 7.23826e+08 N/m^2 Elastic modulus: 2.1e+11 N/m^2 Poisson's ratio: 0.28 Mass density: 7700 kg/m^3 Shear modulus: 7.9e+10 N/m^2 Thermal expansion coefficient: 1.3e-05 /Kelvin SolidBody 1(Boss-Extrude1)(3_hole) Curve Data:N/A

Loads and Fixtures Fixture name Fixture Image Fixture Details Fixed-1 Entities: 1 face(s) Type: Fixed Geometry Resultant Forces Components X Y Z Resultant Reaction force(N) -1000.01 0.00448138 0.00518388 1000.01 Reaction Moment(N.m) 0 0 0 0 Load name Load Image Load Details Force-1 Entities: 1 face(s) Type: Apply normal force Value: -1000 N

Mesh information Mesh type Solid Mesh Mesher Used: Standard mesh Automatic Transition: Off Include Mesh Auto Loops: Off Jacobian points 4 Points Element Size 5.41326 mm Tolerance 0.270663 mm Mesh Quality Plot High Mesh information - Details Total Nodes 63127 Total Elements 42009 Maximum Aspect Ratio 4.0188 % of elements with Aspect Ratio < 3 99.8 % of elements with Aspect Ratio > 10 0 % of distorted elements(Jacobian) 0 Time to complete mesh(hh;mm;ss): 00:00:12 Computer name:

Resultant Forces Reaction forces Selection set Units Sum X Sum Y Sum Z Resultant Entire Model N -1000.01 0.00448138 0.00518388 1000.01 Reaction Moments Selection set Units Sum X Sum Y Sum Z Resultant Entire Model N.m 0 0 0 0

Study Results Name Type Min Max Stress1 VON: von Mises Stress 2.892e+03 N/m^2 Node: 2262 1.164e+06 N/m^2 Node: 39455 3_hole-Static 2-Stress-Stress1 Name Type Min Max Displacement1 URES: Resultant Displacement 0.000e+00 mm Node: 442 5.665e-04 mm Node: 60534 3_hole-Static 2-Displacement-Displacement1 Name Type Min Max Strain1 ESTRN: Equivalent Strain 2.807e-08 Element: 41612 4.334e-06 Element: 17972 3_hole-Static 2-Strain-Strain1

Simulation comparision plots : (stress, strain, displacecment plots)

Experimental setup:

• Need to design the 3d model with exact dimensions.
• Create new static simulation.
• Provide the fixed geometry at one end
• Prove the load of -1000N.
• Create the very fine mesh
• allow the simulation to run.
• Thus the stress, strain and displacment plots are obtained.

Obserations:

• stress and strain are maximum at model having one hole.
• Displacement is greater in model having three hole.
• As the number of holes increases the stress and strain tends to decrease.
• Maximum stress and strain are occuring at the mid of the sides of bigger centre hole.

Conclusion:

• 3d model is created with proper dimensions.
• Simulation is runned at solidworks.

• results are analyzed.

• With design study the case ii plate will be more effecient as the stress and strain gets minimized across the larger hole only due to the presence of smaller holes at adjacent holes. Also it will having lesser weight and mass than the case(i).