Challenge

Analysis & Design of RCC shear walls in the model using ETABS

Answer to the question

Question:

The etabs file for a G+6 building is provided. Run the analysis and design the RCC shear walls (show in the etabs model). The following challenge deals specifically with the shear wall of size 300x1500 at grid A-11 in the structural model.

  • Extract values of longitudinal steel ratio, boundary element length and shear reinforcing ratio from the design results.
  • Provide cross sectional steel arrangement of the shear wall from its base up to terrace, in compliance with provisions of IS 13920 – 2016. AutoCAD application can be used for this exercise. Alternatively, it can be drawn by hand as well.
  • Provide elevation drawings of the reinforcement details of the shear wall from base up to terrace.

Answer:

AIM: Aim to the question is To run the analysis and design the RCC shear walls shown in the etabs model.

INTRODUCTION:

In this question, we need to Extract values of longitudinal steel ratio, boundary element length and shear reinforcing ratio from the design results. Provide cross-sectional steel arrangement of the shear wall from its base up to the terrace, in compliance with provisions of IS 13920 – 2016. AutoCAD application can be used for this exercise. Alternatively, it can be drawn by hand as well. Provide elevation drawings of the reinforcement details of the shear wall from the base up to the terrace.

PROCEDURE:

STEP-1

  • Open the ETABS file
  • After the analysis click Concrete frame design

STEP-2

  • Need to check there is any failures occurs
  • Click Shear wall design tool
  • Select Display info and choose PM failure

STEP-3

  • Click any wall and check the details
  • Here there is no failure occurs all the values of reinforcement ratio is within 4%

STEP-4

Shear Reinforcing

  • Go to concrete frame design
  • Click Display design info
  • Choose Shear reinforcing

STEP-5

Boundary element width

  • 1) Go to concrete frame design
  • 2) Click Display design info
  • 3) Choose Pier edge or boundary zone width

STEP-5

Longitudinal Reinforcement:

  • 1) Go to concrete frame design
  • 2) Click Display design info
  • 3) Choose Pier longitudinal reinforcing

RESULT & CALCULATIONS

Flooor:

te = 300mm

le = 1500mm

Boundary od element =

600

450

450

300

Height of enter wall hw = 10500

clause 10.1.6 (Table wall)

minimum reinforcement in Rc sheare walls when the total height of the wall devided by the length in more than 2if it similar blender wall we need to calculated,

Horizontal min, Reinforcement = Pn min.

Vertical B.E. reinforcement = Pv BE min.

Minimum web reinforcement, Pv web min

Net reinforcement, Pv net min.

So ,

Pn min = 0.025+ 0.5 ()`(hw)/(Lw) -2`(pn-0.025)`

lv be min = 0.0080

lv web= 0.025

lv net = 0.025 + 0.01375 `((tw)/(lw))`

= 0.025 + 0.01375 `((300)/(1500))`

For Longitudinal Reinforcement:

lw = Lw - 2 tw

= 1500- 2(600)

= 300

From ETABS:

The required Revar area, Av = 13128 mm^2

So,

Minimum Vertical Reinforcement lv,

= `(13128)/(C.S. area' of Steel)`

= `(13128)/(1500X300)`

lv = 0.029 >0.0080

From Is 13920,

Ash= 0.05 Sv h `(fck)/(fy)`

Minimum No. of Bar = 8

So Ash = `π/4 d^2`

= `π/4 8^2`

Ash= 50.24 `mm^2`

Now, 50.24 = 0.05 x 100x h `((25)/(500))`

50.24 = 0.025h

h = 200.96

use `ϕ` = 25mm

= `((13128)/((π/4)*25^2))`

= `((13128)/(490.625))`

= 28 bar

For Shear= Reinforcement

For 2 legged 16 mm Dia bar

Ash =`π/4 d^2`

= `π/4 16^2`

= 803.84 `mm^2`

Provide 6 No. of 12 mm in web.

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