Analysis & Design of RCC shear walls in the model using ETABS
Aim:
To analysis and design the RCC shear walls shown in the etabs model.
Step 1:
1) Open the ETABS file
2) After the analysis click Concrete frame design
Step 2:
1) Need to check there is any failures occurs
2) Click Shear wall design tool
3) select Display info and choose PM failure
Step 3:
1) Click any wall and check the details
2) Here there is no failure occurs all the values of reinforcement ratio is within 4%
Step 4:
Shear Reinforcing
1) Go to concrete frame design
2) Click Display design info
3) Choose Shear reinforcing
Step 5:
Boundary element width
1) Go to concrete frame design
2) Click Display design info
3) Choose Pier edge or boundary zone width
Step 6:
Longitudinal Reinforcement:
1) Go to concrete frame design
2) Click Display design info
3) Choose Pier longitudinal reinforcing
Detailing Guideline for shear wall:
1. Minimum Reinforcement for Shrinkage & Temperature
2. Ultimate limit state design rebar requirement
3. Ductility rebar requirement
- Classification of shear wall as per IS-13920-2016 Clause 10.1.4 Slender Wall
`underset (w) h / underset (w) L`= 21000/1500
= 14>2
- Minimum net vertical reinforcement as per IS-13920-2016 Table-1 (iii) 2363 `mm^2`
= 0.0025+0.01375(300/1500)
- Minimum vertical reinforcement within boundary element Table-1 (iii)
= 1400`mm^2` on left (600mm width boundary element)
= 1080`mm^2` on right (450mm width boundary element)
- Minimum horizontal reinforcement in shear wall as per IS-13920-2016 Table-1(iii)
( `rho underset (h)` ) min =0.0025+0.5`(underset (w) h / underset (w) L -2)(rho underset (h)-0.0025)`
( `rho underset (h)` )= 750/(300/1500)=0.0025, `underset (w) h`=21000, `underset (w) L`=1500
( `rho underset (h)` ) min = 0.0025+0.5(21/15-2)x0
( `rho underset (h)` ) min = 0.0025 which is same 750 `mm^2`/m
- Maximum diameter of rebar for shear wall as per IS-13920-2016 Clause 10.1.8
1/10th of wall thickness = 300/10=30mm
Commercial rebar diameter 25mm shall be adopted.
- Confining Reinforcement within boundary element as per IS-13920-2016 Clause 10.4.4
`underset (sh) A = 0.05 underset (v) S h underset (ck) f/ underset (y)f`
`underset (v) s` =150mm, h=1000mm
`underset (sh) A= 452 mm^2`