Challenge

Week 8 Challenge

OPEN STAAD PRO

THE STAAD MODEL 1-7LOAD .STD HAS BEEN UPDATED WITH LOADING AND DESIGN PARAMETERS AND ADDED AS AN ATTACHMENT

STEP 1.

GO TO LOADING IN RIBBON TOOL BAR

CLICK LOAD CASES DETAILS

CLICK PRIMARY

DEFINE LOAD 1 WITH LOADING TYPE DEAD LOAD

AND TITLE AS = DL

STEP 2.

DEFINE LOAD 2 WITH LOADING TYPE LIVE LOAD

AND TITLE AS = LL

STEP 3.

GO TO DEAD LOAD

CLICK ADD

GO TO SELFWEIGHT

CLICK SELFWEIGHT LOAD

TICK DIRECTION AS Y

AND FACTOR AS =-1

GO TO DEAD LOAD

CLICK ADD

GO TO NODAL LOAD

CLICK NODE

PUT FY AS = -20 KN

GO TO DEAD LOAD

CLICK ADD

GO TO MEMBER LOAD

CLICK UNIFORM FORCE

PUT W1= -3 KN/M

AND DIRECTION AS = GY

GO TO DEAD LOAD

CLICK ADD

GO TO MEMBER LOAD

CLICK UNIFORM FORCE

PUT W1= -6 KN/M

AND DIRECTION AS= GY

STEP 4.

GO TO LIVE LOAD

CLICK ADD

GO TO MEMBER LOAD

CLICK UNIFORM FORCE

PUT W1= -4 KN/M

AND DIRECTION AS =GY

GO TO LIVE LOAD

CLICK ADD

GO TO MEMBER LOAD

CLICK UNIFORM FORCE

PUT W1= -7.5 KN/M

AND DIRECTION AS = GY

STEP 5.

CLICK LOAD CASES DETAILS

CLICK DEFINE COMBINATIONS

WITH LOAD NUMBER AS 101

AND NAME AS 1.5DL+1.5LL AND TYPE AS NORMAL

PUT LOAD FACTOR AS 1.5 FOR DL AND 1.5 FOR LL

  • Apply Self weight

. Apply point load of 20 kN at node intersecting inclined member on the top chord.(DL)

  • Apply member load of 3 kN/m on the rafter(DL)

  • Apply member load of 6 kN/m on the secondary beams (DL)

  • Apply member load of 4 kN/m on the rafter(LL)

  • Apply member load of 7.5 kN/m on the secondary beams(LL)

STEP 6.

GO TO ANALYSIS IN RIBBON TOOL BAR

DEFINE COMMAND

TICK ALL

CLICK ADD

STEP 7.

RUN ANALYSIS

GO TO POST PROCESSING MODE

SELECT LOAD AS 1.5DL+1.5LL

STEP 8 .

Find Maximum Force and Minimum Force for member and present the STAAD result.

Maximum Moment in the Secondary beam for 1.5DL+1.5LL case

GO TO RESULT SETUP

TICK GROUP AND SELECT AS SECONDARY BEAM

GO TO BEAM RESULTS

CLICK LOAD AS 1.5DL+1.5LL

RANGE AS GROUP SECONDARY BEAM

OK

RESULT 1.

The Maximum Moment in the Secondary beam for 1.5DL+1.5LL case is in beam no 105

BENDING MOMENT VALUE IS

M@Z=53.113 KNM

STEP 9 .

Find the Maximum Axial force on the inclined bracing and identify the member having the maximum force for 1.5DL+1.5LL case

GO TO RESULT SETUP

TICK GROUP AND SELECT INCLINED BRACING

GO TO BEAM RESULTS

CLICK LOAD AS 1.5DL+1.5LL

RANGE AS GROUP INCLINED BRACING

OK

GO TO BEAM RESULTS

CLICK LOAD AS 1.5DL+1.5LL

RANGE AS GROUP INCLINED BRACING

OK

RESULT 2.

The Maximum AXIAL FORCE in the INCLINED BRACING for 1.5DL+1.5LL case is

BEAM NO 68

MAX FX= -93.972 KN TENSION

BEAM NO 168

MIN FX= -196.080 KN TENSION

STEP 10 .

Identify Bottom chord of Truss having Maximum shear Force & Maximum moment for 1.5DL+1.5LL case and present the values.

GO TO RESULT SETUP

TICK GROUP AND SELECT BOTTOM CHORD

GO TO BEAM RESULTS

CLICK LOAD AS 1.5DL+1.5LL

RANGE AS GROUP BOTTOM CHORD

OK

GO TO BEAM RESULTS

CLICK LOAD AS 1.5DL+1.5LL

RANGE AS GROUP INCLINED BRACING

OK

RESULT 3.

The Maximum BENDING MOMENT in the BOTTOM CHORD for 1.5DL+1.5LL case is

BEAM NO 110

M@Z=9.680 KNM

The Maximum SHEAR FORCE in the BOTTOM CHORD for 1.5DL+1.5LL case is

BEAM NO 110

SHEAR FORCE IN Y AXIS

F@Y= 6.029 KN

SHEAR FORCE IN Z AXIS

BEAM NO 1

F@Z= 0.521 KN

SOLUTION3.

THE UPDATED STAAD FILE NAMED 4.STD IS RECTIFED AND ADDED AS AN ATTACHEMENT

BEAM NO 71 AND 102 SHOULD BE MERGED AND NODE SHOULD BE DELETED AND MEMBER SHOULD BE ASSIGNED AS TRUSS MEMBER

BEAM NO 70 AND 101 SHOULD BE MERGED AND NODE SHOULD BE DELETED AND MEMBER SHOULD BE ASSIGNED AS TRUSS MEMBER

BEAM NO 34 AND 100 SHOULD BE MERGED AND NODE SHOULD BE DELETED AND MEMBER SHOULD BE ASSIGNED AS TRUSS MEMBER

BEAM NO 33 AND 99 SHOULD BE MERGED AND NODE SHOULD BE DELETED AND MEMBER SHOULD BE ASSIGNED AS TRUSS MEMBER

RUN THE ANALYSIS

NO WARNING WILL BE DISLAYED

SOLUTION 4.

Design Parameter exercise

GO TO DESIGN IN RIBBON TOOL BAR

CLICK DEFINE PARAMETERS

SELECT CODE AS IS 800 INDIAN CODE

CLICK BEAM

TICK (.01)PERFORM DESIGN AT ENDS AND 1/12 SECTION LOCATIONS ALONG MEMBER LENGTH

ADD

ASSIGN TO VIEW

ASSIGN

CLICK FU

ULTIMATE TENSILE STRENTH OF STEEL

ADD

ASSIGN TO VIEW

ASSIGN

CLICK FYLD

YIELD STRENGTH OF STEEL

ASSIGN TO VIEW

ASSIGN

CLICK KY

K VALUE IN LOCAL Y AXIS USUALLY MINOR AXIS PUT VALUE =1.2 FOR EXTERNAL COLUMNS

USING ASSIGN TO SELECTED BEAMS ASSIGN TO EXTERNAL COLUMNS

CLICK KZ

K VALUE IN LOCAL Z AXIS USUALLY MAJOR AXIS PUT VALUE =1.2 FOR EXTERNAL COLUMNS

USING ASSIGN TO SELECTED BEAMS ASSIGN TO EXTERNAL COLUMNS

CLICK KY

K VALUE IN LOCAL Y AXIS USUALLY MINOR AXIS PUT VALUE =2 FOR INTERNAL COLUMNS

USING ASSIGN TO SELECTED BEAMS ASSIGN TO INTERNAL COLUMNS

CLICK KZ

K VALUE IN LOCAL Z AXIS USUALLY MAJOR AXIS PUT VALUE =2 FOR INTERNAL COLUMNS

USING ASSIGN TO SELECTED BEAMS ASSIGN TO INTERNAL COLUMNS

CLICK KY

K VALUE IN LOCAL Y AXIS USUALLY MINOR AXIS PUT VALUE =0.85 FOR DIAGONAl MEMBERS

USING ASSIGN TO SELECTED BEAMS ASSIGN TO DIAGONAL MEMBERS

CLICK KZ

K VALUE IN LOCAL Z AXIS USUALLY MAJOR AXIS PUT VALUE =0.85 FOR DIAGONAL MEMBERS

USING ASSIGN TO SELECTED BEAMS ASSIGN TO DIAGONAL MEMBERS

CLICK LY

LENGTH IN LOCAL Y AXIS FOR SLENDERNESS RATIO VALUE KL/R = 3.2 FOR TOP CHORD

USING ASSIGN TO SELECTED BEAMS ASSIGN TO TOP CHORD

CLICK LY

LENGTH IN LOCAL Y AXIS FOR SLENDERNESS RATIO VALUE KL/R = 3 FOR BOTTOM CHORD

USING ASSIGN TO SELECTED BEAMS ASSIGN TO BOTTOM CHORD

CLICK LX

EFFECTIVE LENGTH FOR LATERAL TORSIONAL BUCKLING =1.5 M

USING ASSIGN TO SELECTED BEAMS ASSIGN TO PRIMARY BEAM

CLICK LY

LENGTH IN LOCAL Y AXIS FOR SLENDERNESS RATIO VALUE KL/R = 5 M FOR SECONDARY BEAM

USING ASSIGN TO SELECTED BEAMS ASSIGN TO SECONDARY BEAM

CLICK MAIN

ALLOWABLE SLENDERNESS LIMIT FOR COMPRESSION MEMBER =180

ADD

USING ASSIGN TO SELECTED BEAMS ASSIGN TO EXTERNAL AND INTERNAL COLUMN

CLICK TMAIN

ALLOWABLE SLENDERNESS LIMIT FOR TENSION MEMBER =400

ADD

USING ASSIGN TO SELECTED BEAMS ASSIGN TO DIAGONAL MEMBERS

CLICK RATIO

PERMISSIBLE RATIO OF ACTUAL TO ALLOWABLE STRESS =1

ASSIGN TO VIEW

CLICK TRACK

TICK 2 PRINT THE DESIGN OUTPUT AT MAXIMUM DETAIL LEVEL

ASSIGN TO VIEW

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