Challenge

Week 2 Challenge

SOLUTION 1

A....

CHAIN BOLTING=

PLATE SIZE =260*20 MM

FOR A 20 MM BOLT

BOLT DIAMETER= 22 MM

NET AREA =(B-N*D@0)*T

NET AREA =(260-4*22)*20=3440 MM^2

SOLUTION 1

B.....

ZIG ZAG BOLTING

PLATE SIZE =260*20 MM

FOR A 20 MM BOLT

BOLT DIAMETER= 22 MM

PATH AD= TWO HOLES

PATH BF= TWO HOLES

PATH CEG = THREE HOLES

PATH ACEG =FOUR HOLES AND ONE STAGGER

PATH BCEG =FOUR HOLES AND ONE STAGGER

PATH ACF =THREE HOLES AND TWO STAGGER

PATH BCD =THREE HOLES AND TWO STAGGER

PATH ACD = THREE HOLES AND TWO STAGGER

PATH BCF= THREE HOLES AND TWO STAGGER

PATH AD AND BF=TWO HOLES

A@N=(B-N*D@0)T=(260-2*22)20=4320 MM^2

PATH CEG = THREE HOLES

A@N=(B-N*D@0)T=(260-3*22)20=3880 MM^2

PATH ACEG =FOUR HOLES AND ONE STAGGER

A@N=[(B-N*D@0+SIGMA(P^2/4*G)]T=[(260-4*22)+60^2/4*60]20=3740 MM^2

PATH BCEG =FOUR HOLES AND ONE STAGGER

A@N=[(B-N*D@0+SIGMA(P^2/4*G)]T=[(260-4*22)+50^2/4*60]20=3648.33 MM^2

PATH ACF OR BCD =THREE HOLES AND TWO STAGGER

A@N=[(B-N*D@0+SIGMA(P^2/4*G)]T=[(260-3*22)+60^2/4*60+50^2/4*60]20=4388 MM^2

PATH ACD = THREE HOLES AND TWO STAGGER

A@N=[(B-N*D@0+SIGMA(P^2/4*G)]T=[(260-3*22)+60^2/4*60+60^2/4*60]20=4480 MM^2

PATH BCF= THREE HOLES AND TWO STAGGER

A@N=[(B-N*D@0+SIGMA(P^2/4*G)]T=[(260-3*22)+50^2/4*60+50^2/4*60]20=4296.67 MM^2

THE MINIMUM NET AREA IS FOR PATH BCEG =3648 MM^2.

SOLUTION 1

C.....

DATA GIVEN

ANGLE SECTION(200*100*12)

BOLT SIZE =20 MM

GAUGE**=g1+g2-t

GAUGE**=70+60-12

GAUGE**=118 MM

A@N=A@G-SIGMA(D@H*T)+SIGMA[(P^2/4*G)]T

A@G=288*6=1728 MM^2

PATH AC=

NET AREA=(1728-2*22)12

NET AREA =1464 MM^2

PAT ABC

NET AREA =1728-3*22*12+[(50^2/4*90+50^2/4*118)]12

NET AREA =1082.8932 MM^2

THE MINIMUM NET AREA IS FOR PATH ABC=1082.89 MM^2.

SOLUTION 2

SAG ROD PROBLEM

SELF WEIGHT OF ROOF=60KG/M^2=588.399 N/M^2

DEAD LOAD ON ROOF=588.399*1.2=706.0788 N/M

SELF WEIGHT OF PURLIN =100 KG/M=980.665 N/M

LIVE LOAD =75 KG/M^2=735.49875 N/M^2

LIVE LOAD ON PURLIN =735.49875*1.2=882.5985 N/M

TOTAL GRAVITY LOAD =706.0788+980.665+882.5985=2569.3423 N/M

WIND LOAD =150 KG/M^2=1470.9975 N/M^2

WIND LOAD (NORMAL TO ROOF)=1470.9975*1.2=1765.197 N/M

COMPONENT OF GRAVITY LOAD (PARALLEL TO ROOF)=2569.3423*SIN15=664.9947 N/M

PULL ON SAG ROD=664.9947*8/3=1773.3192 N

FACTORED LOAD=1773.3192*1.5=2659.9788 N

REQUIRED NET AREA=T@DN*GAMMA@M1/(0.9*F@U)

NET AREA=2659.9788*1.25/0.9*410=9.01 MM^2

PROVIDE A 16 MM DIAMETER SAG ROD BETWEEN PURLINS

NOTE =THE PROVIDED ROD SHOULD NOT BE LESS THAN 16 MM IN DIAMETER

SOLUTION 3

GIVEN DATA

T=500 KN

FACTORED T=500*1.5=750 KN

FY= 350 N/MM^2

FU=490 N/MM^2

L = 3000 MM

ASSUMING.

FOR A 20 MM BOLT

BOLT DIAMETER= 22 MM

PITCH =40 MM

GAUGE= 40 MM

EDGE DISTANCE =40 MM

A@G(REQ)=TDG*GAMMA@M0/FY=750*10^3*1.1/350=2357.14 MM^2

INCREASING AREA BY 40 PERCENT WE GET

A@G(REQ)=3300 MM^2=33 CM^2

LAMDA=KL/R

KL=3000 MM

R=350 FROM TABLE (FROM TABLE 3 OF IS800-2007)

LAMDA=KL/R

350=3000/R

R=8.571 MM =0.85 CM

SELECTING ANGLE 200*200*12 MM (INCREASING SINCE FAILING IN RUPTURE)

AREA PROVIDED =46.61 CM^2=4661 MM^2

R MIN PROVIDED=3.92 CM=39.2 MM

AREA PROVIDED> A@G(REQ)

4661 MM^2>3300 MM^2

ASSUME 20 MM DIA BOLT OF 12 NUMBER THAT IS 4 BOLT IN 3 ROWS EACH

DESIGN STRENGTH DUE TO YIELDING

TDG=FY*AG/GAMMA@MO=350*4661/1.1=1483045.455 N OR 1483.045 KN

TDG>T

1483.045 KN>750 KN HENCE SAFE.

DESIGN STRENGTH DUE TO RUPTURE

TDN=ALPHA*AN*FU/GAMMA M1

ALPHA=0.8

AN=A1+KA2

A1=(200-12/2-3*22)12=1536 MM^2

A2=(200-12/2)*12=2328 MM^2

K=3A1/3A1+A2=3*1536/3*1536+2328=0.6643

AN=1536+0.6643*2328=3082.62 MM^2

TDN=0.8*3082.62*490/1.25=966712.692 N OR 966.712692 KN

TDN= 966.712692 KN>750 KN HENCE SAFE

DESIGN STRENGTH DUE BLOCK SHEAR

ATG=(40+60+60)12=1920 MM^2

ATN=(40+60+60-2.5*22)=1260 MM^2

AVG=(40+60+60+60)12 =2640 MM^2

AVN=(40+60+60+60-3.5*22)12=1716 MM^2

TDB1=AVG*FY/SQUAREROOT*3*GAMMA@MO+0.9*ATN*FU/GAMMA@M1

TDB1=2640*350/SQUAREROOT*3*1.1+0.9*2160*490/1.25

TDB1=929502.2261 N

TDB1=929.5022 KN >750 KN HENCE SAFE

TDB2=0.9*AVN*FU/SQUAREROOT*3*GAMMA@M1+ATG*FY/GAMMA@M0

TDB2=0.9*1716*490/SQUAREROOT*3*1.25+*1920*350/1.1

TDB2=960439.715 N

TDB2=960.4397 KN >HENCE SAFE

TENSION CAPACITY OF ANGLE=929.50 KN > 750 KN HENCE SAFE

CHECK FOR STIFFNESS

TABLE 3 OF CODE

KL/R

3000/39.2=76.53 <350 HENCE SAFE

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