Challenge

Week 6 Challenge

Aim :-To analyze and design the raft foundation considering  earth pressure , seft weight , surcharge , 70R loads.

Modeling in Staad Pro:- The bridge is modeled as a plan  frame structure taking the centerline dimension of the structure in Staad -pro . As the length of the bridge is more than twice its width , the box will be analyzed for unit length and the design will be adopted for the entire length . Loads corresponding to the unit length are evaluated and the structure analyzed and designed.Since the box is fully resting on the soil, discrete spring supports are provided below the base on a sub -grade modulus of the soil available at the base. The sizes of the member are assigned accordingly in the model.

Loading on the structure 

Self - weight of the base slab 

The Sizes of the members are given below :-

The thickness of the top slab =0.85m

Assumed Height of top haunch =0.15m

The thickness of the Bottom slab =0.9m

Assumed Height of bottom haunch =0.15m

Clear Height =5.5m

Clear weight =12m

The Volume of the bottom Slab is =0.9*1*(12*0.9*0.9)

                                                 =12.42m^3

Weight of bottom Slab =12.45*25

                                =310.5kN

Earth Pressure :- 

Angle of repose =30 degree

At rest earth pressure co-efficient= 0.5

Density of soil=20 kN/m^3

Height from the top 

The intensity of earth pressure (kN/m^2)=rest earth pressure *density of soil*height

Height from top (m) The intensity of earth pressure (kN/m^2)
0.425 0.5*20*0.425=4.25
0.85 0.5*20*0.85=8.5
1 0.5*20*1=10
6.2 0.5*20*6.2=62
6.35 0.5*20*6.35=63.5
6.8 0.5*20*6.8=68

The earth pressure acting on the structure is ssigned as trapezoidal on the both sides of the box structure in staad.

Similarly , the live load surcharge and braking loads are applied using specific load commands 

Live load surcharge:-

Equivalent height=12

Intensity of loading=1.2*20*0.5

                           =12kN/m^2

Braking load 

Max. Live  load on the box =700 kN

Width of the box = 12m

Braking Load =14.58 kN

Load Combination 

Partial Safety Factors for the ulitmate limit state are considered as per IRC 6. The following loaded combinations are used.

The Analysis is carried out using STAAD-PRO.

From the analysis results, a critical case of the load values is adopted for the design.The bending moment will be maximum at the center of the base slab . For the worst combination design has to be carried out. The critical section for shear will be at the distance "d" from the face of the support. The bending moment, shear force and deflection daigram are given below.

Analysis Results:-

Load Bending Moment Mz,(kN.m) Shear Force Fy, (kN)
Dead Load 398.83 232.11
Earth Pressure  41.38 1.07
Live Load Surcharge 12.98 17.8
 Braking Load  11.94  6.06

2.Design of the member based on the analysis and indicate the selection of the member size.

The members of the underpass i.e, the top and bottom slabs and vertical walls are designed as the beam members subjected to axial thrust and flexure.The assumed dimensions of the selections are for adequacy of the Reinforcement provided and stresses in the concrete and reinforcing steel.

Using the load combination, bending Moment envelops for the structures are obtained. for the Maximum B.M corresponding,axial forces are picked out from the STAAD post-Processor.

Max factored bending moment =470kN.m

Max factored shear force 320kN

Depth of base slab,D 900m

Width of base slab ,b 1000mm

Grade of concrete M30

Grade of steel Fe500

Es = 2*10*5Mpa

Ecm 31000Mpa

DEsign yeild strength of shear reinforcement Fywd=0.87fyk/ys

                                                                          =0.8*500*/1.15

                                                                          =348 Mpa

material Safety factor  

COncrete 1.5

Steel = 1.15

Ulimate compressive strain in concrete 0.035 up to fck

Modular ratio 6.45

Long trem modulr ratio 12.9

Ulimate tensile strain in steel =0.00217

Coefficient, 0.67

Factor 0.8

1

The design value of concrete comressive strength fcd=a*fck/ym

13.4 Mpa

Fav= 10.72

The effective depth of the member 900-50-10

                                                 =840mm

M/(bd^2*Fav)

470*10^6/(1000*840^2*10.72)

0.062

518.52 mm

Force in compression =Force in Tension 

fy*As/Ys=n*fcd*a`lamda`x*b =Fav*x*b

M=Fav*x*b*(d-bx)

which gives , x=d(1-(1-4bkav)^(1/2)/2b

53.44mm<518.52 mm

Reinforcement area ,

1317.6mm^2

Provide 10 mm reiforcement=1963mm^2>1317.6mm^2

Hence ok 

Netural axis depth, 79.62 mm <518.58 mm

Hence ok

Xlim/d

518/840

0.617

Rlim4.98

Effective depth required( Mu/(Rlim*b))

307mm<900 mm

Hence Safe 

Selection of member Size:-

The size of the base slab depends upon factors such as the height of the bridge, uplift pressure acting on the foundation, soil fill on the top of the box.

When the height of the bridge is more, the size of the member required will be more because of the increase in lever arm as well as force. In such cases, the forces can be reduced by reducing the height of the structure and providing fill on top.The hydrological parameter should be taken into account in this case.

To avoid uplift, the size of the base slab can be increased. Alternately, the lenght of the raft slab can be increased. This will result in an increased in uplift but can be compensated by the earth from the top. The more the fill on top slab , the proportion of the raft foundation is more. Generally, span /10 is adopted for selection of base slab thickness , later it can be optimized seeing design and economy. While determining the member sizes feasibility , safety , hydrology, and site criteria also be oberved.

4 .To analyze the change in shear in the base slab if there is a 5m fill SIDL due to earth fill 

The thickness of the earth fill on top is 5m

The density of fill material 20 kN/m^3

UDL due to earthfill 100kN/m

It is applied as a dead load on top, Uniformly distributed throughout the weigth of underpass.

After analysis, the design shear force is taken as 

Shear design :-

Shear force=0.5*1000*840*16.26*13.4

Where v is the strength reduction factor 

Longitudinal force=0 kN

Shear force by shear reinforcement

Shear resistance of the section without shear reinforcement 

Vrdc=0.12k(80plfck)^0.33+0.15ac*p*bw*d

=100.937 Kn

Hence shear reinforcement is required

The diameter of the bar used as shear reinforcement is 2

Shear force by shear reinforcement Vns

Provide shear reinforcement vertically 

To analyze the change in shear in the base slab if there is a 0m fill SIDL due to earth fill 

After analysis, the design shear force is taken as 

Shear design :-

Shear force=91511.3 kN

Where v is the strength reduction factor 

Longitudinal force=0 kN

Shear force by shear reinforcement

=100.937 kN

Shear resistance of the section without shear reinforcement 

Hence shear reinforcement is required and should be provided as per IRC 112-2020.

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