Week 4 -Wire Bending Challenge
Wire Bending Challenge
AIM
To carry out a static structural analysis on Wire bending challenge with given material.
PROCEDURE
To find and compare the results of Equivalent stress, Total deformation, Equivalent elastic strain for all the cases.
CASE 1 : Copper Alloy (Non Linear)
CASE 2 : Aluminium Alloy (Non-Linear)
CASE 3 : Magnesium Alloy (Non-Linear)
This challenge, you will have to perform an analysis to simulate the bending of a wire in ANSYS. You will have to use Copper Alloy (Non Linear), Aluminium Alloy (Non-Linear), and Magnesium Alloy (Non-Linear) for the wire alone. You need to find out the Equivalent stress and Equivalent strain on the wire alone. Compare the results and submit a well-formatted report on this.
CASE 1 : Copper Alloy (Non Linear)
Import the geometry.
select the material.
strainless steel.
Copper Alloy (Non Linear)
And open the model panel.
In connection panel connect the wire to lever.
And connect the wheel to wire.
contact size = frictional.
frictional co-efficient = 0.2
formulation = augmented tagrange.
interface treatment = add offset and ramped effect.
normal striffness factor = 0.1.
joint option.
revolve joint
groung to lever.
mesh the component.
use method option and use tetrahedral.
sizing option of 2.2mm in 4 face.
type = sphere of influence.
sphere centre = coordinate system.
sphere radius = mm.
element size = 0.8mm
sizing option is 0.8mm and by using the diameter 7mm
by creating the coordinate axis.
Analysis setting
step = 8
1st step
solver type = direct
week spring = program control.
large deformation = ON.
Auto time step = ON.
define by = time
initial time step = 0.1s
minimum time = 1e-2s
maximum time = 0.2s
2nd to 8th step
Auto time step = ON.
define by = time
minimum time = 1e-2s
maximum time = 1s
carring time step = ON
fixed support
Joint rotaion
displacement
-20
-40
-60
-80
-100
-120
-140
-140
total deformation.
Equivalent stress.
Equivalent strain
Aluminium Alloy(Non-linear)
Import the geometry.
select the material.
strainless steel.
Aluminium Alloy (Non-Linear)
And open the model panel.
In connection panel connect the wire to lever.
And connect the wheel to wire.
contact size = frictional.
frictional co-efficient = 0.2
formulation = augmented tagrange.
interface treatment = add offset and ramped effect.
normal striffness factor = 0.1.
joint option.
revolve joint
groung to lever.
mesh the component.
use method option and use tetrahedral.
sizing option of 2.2mm in 4 face.
type = sphere of influence.
sphere centre = coordinate system.
sphere radius = mm.
element size = 0.8mm
sizing option is 0.8mm and by using the diameter 7mm
by creating the coordinate axis.
Analysis setting
step = 8
1st step
solver type = direct
week spring = program control.
large deformation = ON.
Auto time step = ON.
define by = time
initial time step = 0.1s
minimum time = 1e-2s
maximum time = 0.2s
2nd to 8th step
Auto time step = ON.
define by = time
minimum time = 1e-2s
maximum time = 1s
carring time step = ON
fixed support
Joint rotaion
displacement
-20
-40
-60
-80
-100
-120
-140
-140
total deformation.
Equivalent stress.
Equivalent strain
Magnesium Alloy (Non-Linear)
Import the geometry.
select the material.
strainless steel.
Magnesium Alloy (Non-Linear)
And open the model panel.
In connection panel connect the wire to lever.
And connect the wheel to wire.
contact size = frictional.
frictional co-efficient = 0.2
formulation = augmented tagrange.
interface treatment = add offset and ramped effect.
normal striffness factor = 0.1.
joint option.
revolve joint
groung to lever.
mesh the component.
use method option and use tetrahedral.
sizing option of 2.2mm in 4 face.
type = sphere of influence.
sphere centre = coordinate system.
sphere radius = mm.
element size = 0.8mm
sizing option is 0.8mm and by using the diameter 7mm
by creating the coordinate axis.
Analysis setting
step = 8
1st step
solver type = direct
week spring = program control.
large deformation = ON.
Auto time step = ON.
define by = time
initial time step = 0.1s
minimum time = 1e-2s
maximum time = 0.2s
2nd to 8th step
Auto time step = ON.
define by = time
minimum time = 1e-2s
maximum time = 1s
carring time step = ON
fixed support
Joint rotaion
displacement
-20
-40
-60
-80
-100
-120
-140
-140
total deformation.
Equivalent stress.
Equivalent strain
RESULT
Total deformation stress strain
Copper Alloy (Non Linear) 330.32MAX 330.32MAX 0.0030216MAX
Aluminium Alloy (Non-Linear) 262.64MAX 340.19MAX 0.0048333MAX
Magnesium Alloy (Non-Linear) 262.64MAX 257.36MAX 0.0057321MAX