Challenge

Week 3 Challenge

Ans1.1) 

The primary load cases to be considerd for the design are the

  • Dead load
  • Live load / Imposed load 
  • Wind load 
  • Earthquake load 

Ans1.2) 

One -way slab is the slab whose ratio of longer span to the shorter span is greater than two where ly/lx is greater than two , where lx stands for shorter dimension and ly for longer span dimensions.

Ans1.3)

 The unit weight of structural steel and soil as per the  IS 875 part 1 is

  • The unit weight of structural steel is 7840 Kg / m^3
  • The Unit weight of soil is 18 kN/m3 

Ans1.4) Sections that can be defined using Properties tab in STAAD Pro are 

  • Circular section 
  • Rectangular section 
  • Trepezodial section 
  • Tee section 
  • Genaral section 
  • Tapered I 
  • Tapered tube 

Ans1.5) 

  • Primary Beams are the beam located at the exterior of the Structural elements
  • The beam can not have much load on the exterior Beams or primary Beams
  • Secondary beam are laid on the primary beam 

Ans2.1)

 The factors that influence the design presure intensity of a high rise building are 

  • k1 = probability factor ( risk coefficient.)

  • k2 = terrain, height and structure size

  • k3 = topography factor 

     Design Wind Pressure - The design wind pressure at any height above mean ground level shall be obtained by the following relationship 
     between wind pressure and wind velocity

        Pz = 0.6 v^2

Ans2.2)

The load transfer process of a reinforced concrete building is as follows

  1. Slab 
  2. Secondary beam                                        
  3. Primary beam
  4. Columns
  5. Foundation 

Ans3.1)

One - way slab 

  • The ratio of the longer span to the shorter span is greater than 2 is know as one - way slab
  • Where LY / LX is greater than 2

Two - way slab 

  • The ratio of the longer span to the shorter span is less than or equal to 2 is know as two way slab 
  • Where LY / LX is Less than 2

Ans3.2)

  • Secondary beam are the internal beam that are restrained on the primary beam
  • They are the simply supported beam 
  • In secondary beam the moment is Zero at the end of the beam 

Ans3.3)

Indian Standards for each load case

  • For Dead load  : IS code 875 Part 1
  • Live load         : IS code 875 part 2
  • Wind load        :  IS code 85 part 3
  • Seismic load    : IS 13927  

Parameters of each load case

  • The parameter of Dead load are 1) unit weight 2) Volume of the section that may be rectangular section , circular section etc
  • The parameter of Live load are depend on the building type residential building, commercial building, industrial building , area type room , toilet room , corridoors , roof etc.

Each load case

  • A load case is a combination of different types of loads with safety factors applied to them.
  • A structure is checked for strength and serviceability against all the load cases it is likely to experience during its lifetime.

Ans3.4)

  • Go to property section 
  • Click on Define material
  • Select the section , Rectangular section , circular section etc
  • Select the material type concrete , steel , aluminum
  • For the rectangular  section enter YD and ZD in the column below 
  • Click add and close 
  • Select the material type and assign to the selected view 

For the support

  • Click on the support 
  • Click on the create 
  • Select the type of support do we want to assign the section 
  • Click on add close 

Ans3.5)

  • First create a simple model by using the node in staad pro.
  • Click on the create beam option and create a beam in the direction of x and Z axis 

 PRACTICAL

ANS1.1) 

Wind presure  Pz  =  0.6 v^2

     where Vz = Vb X k1 X k2 X K3 

        Vb = Wind speed at the certain location  = 47m/sec 

        K1 = Risk coffiecient   =1.07

        K2 =  Terrain height and structure factor = 1.12

        K3 =  Topography factor = 1.0

        Vz = Vb X k1 X k2 X K3 

             = 47 X 1.07 X 1.12 X 1.0

             =  56.88

Pz=0.6(vz)2 = 0.6*56.88^2

= 1941.2 N/m2

Ans1.2)

The Dead load of the section considering the section length 5 m and width 0.23 m and depth is 0.5m

        Dead load of the section =  Unit weight x volume of the section  

                                            = unit weight of concrete is 25 KN/m

                                            =  Volume of the section = 0.5 x 0.23 X1

                                            = 0.115 m^3

                          Dead load   =  25 X 0.115 

                                           =   2.875 KN/m

           Live load = considering the General Building 

  Bathrooms & Toilets in all types of buildings 2 1.8
kitchens

Dwelling houses

hostels hotels & hospitals.

2

3

1.8

4.5

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