Challenge

Week 2 Railwheel and Track

KKunal Kapadia27 Jun 2021

Objective
- Multiply the bearing load by 5 and compare the results to the 100000 N load (As done in week 2 video). Under both loads, compare total deformation, equivalent stress, and life.
- Implement a User specified result, calculate the Total Deformation from it, and compare it to the result generated by ANSYS's inbuilt result with a load of 100000 N.
Case Setup and Execution
1. Below are the points to be followed for case setup and execution.
  1. Geometry
    1. Import the geometry provided to you in workbench.
  2. Material
    1. Keep the material default (structural steel) for this simulation.
  3. Connections
    1. Contacts
      - Ansys would have made automatic contacts.
      - Change the contact between wheel and rail from bonded to friction with co-efficient of 0.3
      - Change the contact between shaft and wheel from bonded to fricitonless.
    2. Joints
      1. Below is the list of joints to be applied.
        
        Joint 1
        
        Connection Type - Body to Ground
        
        Type - Translation
        
        Scope - Shaft
        
        Joint 2
        
        Connection Type - Body to Ground
        
        Type - Fixed
        
        Scope - Sides of rail track
        
        Note :- The direction should be changed in so that X axis is in the direction of the displacement.
        
        Joint 3
        
        Connection Type - Body to Ground
        
        Type - Planar
        
        Scope - Flate side face of the wheel
  4. Meshing
    - Global Size = 50 mm.
    - Face Sizing = 35mm.
      1. Select the contact faces where actual displacement is going occur.
  5. Boundary Condition
    1. Analysis Settings
      1. No. of steps - 5
        
        Step 1
        
        Auto Time Stepping - Program Controlled
        
        Solver Type - Direct
        
        Large Deflection - ON
        
        Force Convergence - ON
        
        Output Controls
        
        Change all the output controls to YES
        
        Step 2 - Step 5
        
        Auto Time Stepping = ON
        
        Define By - Time
        
        Carry Over Time Step - ON
        
        Minimum Time Step - 1E-003s.
        
        Maximum Time Step = 0.1s.
  6. Load Conditions
    1. Load 1 - Bearing Load
      1. On the inner diameter of wheel
      2. Define By - Components
      3. Axis Y - [-1e + 05] N
    2. Joint Load
      1. Type Displacement
      2. Give displacement of 100 mm for each increament for each step.
        
        Load Case 1
        
        Load Case 2
Results of Case 1 - Bearing Load [1E + 005] N
1. Total Deformation
2. Equivalent Stress
3. Life
4. User Defined Result
  - use the following expression = sqrt( UX^2 + UY^2 + UZ^2 )
Results of Case 2 - Bearing Load [5E + 005] N
1. Total Deformation
2. Equivalent Stress
3. Life
4. User Defined Result
  - use the following expression = sqrt( UX^2 + UY^2 + UZ^2 )
Comparing the results
- Cases Total Deformation (Max) mm Equivalent Stress (Max) MPa Life Cycles ( Min ) User defined result (mm)
  
  Case 1 1001.4 145.59 82175 1001.4
  
  Case 2 1001.3 581.46 974.43 1001.3
Conclusions
- Above results show that Equivalent Stress in Case 2 is more than Case 1.
- And henceforth life cycle of the system in case 2 decreases significantly compared case 1.

Week 2 Railwheel and Track

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Cases	Total Deformation (Max) mm	Equivalent Stress (Max) MPa	Life Cycles ( Min )	User defined result (mm)
Case 1	1001.4	145.59	82175	1001.4
Case 2	1001.3	581.46	974.43	1001.3

Ship work like thisin your own course.

Talk to a career counsellor

Ship work like this
in your own course.