Week 2 Railwheel and Track

Railwheel and Track

Introduction to Rail Wheel: A train wheel or rail wheel is a type of wheel specially designed for use on railway tracks.
A rolling component is typically pushed onto an axle and mounted directly on a railway carriage or locomotive, or
Indirectly on a bogie, also called a truck. Wheels are cast or forged and are heat-treated…

Introduction to Rail Wheel:

A train wheel or rail wheel is a type of wheel specially designed for use on railway tracks. A
rolling component is typically pushed onto an axle and mounted directly on a railway
carriage or locomotive, or
Indirectly on a bogie, also called a truck. Wheels are cast or forged and are heat-treated to
have a specific hardness. New wheels are trued, using a lathe, to a specific profile before
being pressed onto an axle. All wheel profiles must be regularly checked to ensure proper
interaction between the wheel and the rail. Incorrectly trued, or worn out wheels can
increase rolling resistance, reduce energy efficiency and may even cause a derailment. A
railroad wheel typically consists of two main parts: the wheel itself, and the tire (or tyre in
British English) around the outside. A rail tire is usually made from steel, and is typically
heated and pushed onto the wheel, where it remains firmly as it shrinks and cools.
Monobloc wheels do not have encircling tires, while resilient rail wheels have a resilient
material, such as rubber, between the wheel and tire.

Rail wheel design can be observed as given below:

Case 1: Multiply the bearing load by 5 times and compare the results with the load of 100000 N (As done in week 2 video). Compare the Total Deformation, Equivalent stress, and the life under both the loads

procedure for the Railwheel and Track for static structural analysis :

material selection : steel

Geometry:

Static structural:

selection of the step as follows

1. Material selection
2. Geometry
3. Model
4. Setup
5. Solution
6. Result

1) material selection : steel

2) Geometry:

if you want edit some part of the geometry opent the file in space claim :

import from the save folder :

3) Model:

in geomtrey of the model there are 3 parts

as shown bellow:

material used for each part is sttructural steel:

* check for the connection :

1) contact

2) joint

in contact :

frictional and frictionless

as shown bellow :

fricional: between wheel and track

frictionless:shaft and wheel connection

Joints:

1. Fix
2. Translational
3. Planer

1) Fix: rail track as fix support

information need to fill in the given condition :

connection type	body-ground
type	fix
scope	2 face
behaviour	rigid
scoping method	geometry selection

2) Translational

information need to fill in the given condition :

connection type	body-ground
type	Translational
scope	1 face
behaviour	rigid
scoping method	geometry selection

image for the translation :

3) Planer:

connection type	body-ground
type	Planer
scope	1 face
behaviour	rigid
scoping method	geometry selection

mesh:

face sizing: (select the contacted face on which load is applied ) as shown:

element size: 35 mm

Input for the static structural :

1. Bearing load
2. joint dispacement

1) Bearing load

scoping method	geometry selection
geometry	1 face
defined by	component
coordinated system	globle coordinated system
Y component	-5e+005N

for bearing support as shown:

2) joint dispacement :

joint	ground to part2\solid1
DOF	X Displacement
type	Displacement
magnitude	tabular Data

magnitude data:

step	time	Displacement
1	0	0
1	1	100
2	2	200
3	3	300
4	4	400
5	5	500

magnitude data:

for the solution :

as per requirement the of case one : insert all through the static solution

1. total deformation
2. stress
3. srain
4. contact tool -frictional (pressure)
5. force reaction
6. user defined Result
7. stress2 (for rail whhel only) select by solid selection
8. strain2 (for rail whhel only) select by solid selection
9. contact tool2 -frictionless (pressure)

now click on solve

Result fot all the condition which we apllied:

Bearing load :10000N

Equivalent strain:

Equivalent stress:

equivalent strain 2: for train wheel

equivalent stress 2: for train wheel

User define result:

contact tool: pressure value(frictional)

contact tool: pressure value (frictionless)

here the comparison between two apllid force

1) Bearing load

load	100000 N	500000 N
total deformation	14.655mm	14.676mm
stress	0.28424MPa	1.408 MPa
strain	1.786e-006	8.7561e-006
contact tool	0.52029MPa	2.5972MPa
force reaction	23931N	1.1956e+005N
stress2 (for rail whhel only)	0.49205MPa	2.4487MPa
strain2 (for rail whhel only)	2.9982e-006	1.481e-005
contact tool2 -	3.1613e-003MPa	1.9872e-002MPa

Case 2:

Implement a User-defined result and calculate the Total Deformation from this result and check if it is the same as that obtained by the inbuilt result by ANSYS for a load of 100000 N

angular in X direction Deformation:

scoping method	geometrical selection
source	Expression
Expression	RX
Output unit	Angle

Total deformation:

2) joint dispacement :

scoping methid	geometry selection
source	expression
expression	sqrt(UX^2+UZ^2+UY^2))
output unit	length

Conclusion :

1. Static structural analysis on the Railwheel and Track setup is done.
2. i have Multiply the bearing load by 5 times and compare the results with the load of 100000 N . Compare the Total Deformation, Equivalent stress, and the life under both the loads is done
3. Implement a User-defined result and calculate the Total Deformation from this result it is get the same as that obtained by the inbuilt result by ANSYS for a load of 100000 N.

with this report i have attached zip file for further reference for my analysis

thank you for your time