Week 2 Challenge
1. Net Area for tension member calculation problem
Calculate the net section area for the tension member as shown in Figure below. The plate size is 260 x 20 thick and Bolt size is 20 mm.
Plate – Drilled Hole
Aim- To Calculate net section area of tension member of given figures.
Given data-
Plate width b= 260mm, thickness of plate t= 20mm, Bolt Size =20mm
Bolt hole dia dh =20+2 = 22 mm
As per IS-800.2007 Clause-6.3
Net area of cross section An = (b-n dh) t = (260 – 4 X 22) X 20 = 3440 mm2
Plate – Zigzag bolting

Angle (200 x 100 x 12 with M20 bolt)
Sip Steps:
- Refer Slide 26 for Net area calculation formula
- For angle section Flatten the member and calculate the gauge distance

2. Sag rod design problem
Design a sag rod as shown in Figure below. Purlins are supported at 1/3rd points by sag rods.
Assume centre to centre distance of Rafter spaced at 8 m , spacing of purlin = 1.2 m, Self weight of roofing (including thermal insulation)= 60 kg/m2 , Wind pressure intensity = 150 kg/m2,Slope of rafter = 15 degrees, Live Load =75 kg/m2. Assume self weight of purlin as 100 kg/m.
Tip Steps :
- Calculate total gravity load (DL & LL) on the purlin
- Calculate Wind load acting on the purlin. Note that wind load acts perpendicular to the member.
- Resolve and calculate the load acting parallel to the roof
- Force contribution to each sag rod is calculated
- Calculate required net area and chose a desired sag rod size.

3. Determine section size for given tensile load
Design a single angle member of length 5m to carry axial tensile force of 500 kN. Yield strength fy of the material to be considered is 350 N/mm2.
Tip Steps :
- Calculate required area of cross section from factored load
- Choose an angle section from required area calculated
- Calculate design strength of the member due to yielding
- Calculate design strength of member by tearing of net section
- For a given member assume bolts placed with appropriate edge/end/pitch/gauge distance and calculate block shear capacity
- Check slenderness is within limit

