Week 11 Challenge

1. Given data

Vertical force = 125KN

friction coefficient = 0.3 (code book) along longitudinal direction

friction coefficient = 0.1 (code book) along transverse direction

for teflon = 0.1

friction load = vertical force* friction coefficient

= 125*0.3

=87.5 KN (longitudinal direction)

friction load = 125*0.1

12.5 KN (transverse direction )

friction force = 125*0.1

= 12.5 KN (teflon pad used)

2. figure 1 Stop support

figure 2 guyed support

figure 3 guyed support+ rest support

figure 4 guyed support+ rest support

figure 5 guyed support

figure 6 guyed support

3. Acoording to the given details in the question

based on the sizes of pipes,

we are taking point loads for 24 inch pipe, 12 inch pipe, and 18 inch pipe

and udl for 8 inch pipe

on Cable tray udl is 1 kn/sq.meter

on 8 inch pipe udl is 1.9kn/sq.meter

these are the loads UDL and point loads are acting on the pipe rack