Menu

Executive Programs

Workshops

Projects

Blogs

Careers

Student Reviews



More

Academic Training

Informative Articles

Find Jobs

We are Hiring!


All Courses

Choose a category

Loading...

All Courses

All Courses

logo

Vehicle Ride 2

GIVEN  Total weight = 1900kg F/R distribution = 55% front Unsprung mass in the front = 90kg Unsprung mass in the rear = 60kg SOLUTION  Total mass in the front = 55% of 1900 = 1045kg Total mass in the rear = 1900-1045 = 855kg  Front sprung mass axle = Total mass in the front - unsprung mass in the front =…

    Project Details

    Loading...

    Leave a comment

    Thanks for choosing to leave a comment. Please keep in mind that all the comments are moderated as per our comment policy, and your email will not be published for privacy reasons. Please leave a personal & meaningful conversation.

    Please  login to add a comment

    Other comments...

    No comments yet!
    Be the first to add a comment

    Read more Projects by RAHUL PARAMESWARAN (2)

    Vehicle Ride 2

    Objective:

    GIVEN  Total weight = 1900kg F/R distribution = 55% front Unsprung mass in the front = 90kg Unsprung mass in the rear = 60kg SOLUTION  Total mass in the front = 55% of 1900 = 1045kg Total mass in the rear = 1900-1045 = 855kg  Front sprung mass axle = Total mass in the front - unsprung mass in the front =…

    calendar

    12 Nov 2020 07:06 AM IST

      Read more

      Vehicle Ride 1

      Objective:

        Given Data: Front sprung masss natural frequency = 1.15Hz  Wheel base = 2700mm = 2.7m Speed = 60mph = 26.8m/s Solution: Frequency = `1/(2pi)* sqrt((riderate)/(eachmass)`.....................(a)  consider design condition sprung mass each corner = (1825-90-60)/4 = 418.75kg using this mass in (a)…

      calendar

      04 Sep 2020 10:49 AM IST

        Read more
        Showing 1 of 2 projects