GIVEN Total weight = 1900kg F/R distribution = 55% front Unsprung mass in the front = 90kg Unsprung mass in the rear = 60kg SOLUTION Total mass in the front = 55% of 1900 = 1045kg Total mass in the rear = 1900-1045 = 855kg Front sprung mass axle = Total mass in the front - unsprung mass in the front =…
RAHUL PARAMESWARAN
updated on 12 Nov 2020
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Vehicle Ride 2
GIVEN Total weight = 1900kg F/R distribution = 55% front Unsprung mass in the front = 90kg Unsprung mass in the rear = 60kg SOLUTION Total mass in the front = 55% of 1900 = 1045kg Total mass in the rear = 1900-1045 = 855kg Front sprung mass axle = Total mass in the front - unsprung mass in the front =…
12 Nov 2020 07:06 AM IST
Vehicle Ride 1
Given Data: Front sprung masss natural frequency = 1.15Hz Wheel base = 2700mm = 2.7m Speed = 60mph = 26.8m/s Solution: Frequency = `1/(2pi)* sqrt((riderate)/(eachmass)`.....................(a) consider design condition sprung mass each corner = (1825-90-60)/4 = 418.75kg using this mass in (a)…
04 Sep 2020 10:49 AM IST